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Conditional state for a projective measurement

Statement

Let ρ be a density operator and (Pa)a∈Ω a finite projective measurement on a nonzero finite-dimensional complex inner-product space H. Put pa=tr⁡(ρPa). If pa>0, then

ρa:=PaρPapa

is a density operator whose image im⁡(ρa):={ρax:x∈H} is contained in im⁡(Pa) (Kernel and image of a linear map). This statement assigns a conditional state only on positive-probability branches.

Facts & Assumptions

Given: The density operator ρ, the projective measurement (Pa)a∈Ω, and an outcome a with pa>0.

[F1]

Finite projective measurements: Pa∗=Pa=Pa2 and distinct outcome projections are orthogonal.

[F2]

Projective measurement outcome weights are probabilities: pa=tr⁡(ρPa) is the probability of outcome a.

[F5]

Density operator: on a nonzero finite-dimensional complex inner-product space, a density operator is nonnegative and has trace one.

[F3]

For A∈Mm×n(F) and B∈Mn×m(F), tr⁡(AB)=tr⁡(BA): tr⁡(AB)=tr⁡(BA) for compatible rectangular matrices.

[F4]

Trace is a linear functional on Mn(F): trace preserves scalar multiples.

[F6]

Non-negative and positive operators: a nonnegative operator is self-adjoint and has nonnegative quadratic form on every vector.

[F7]

Kernel and image of a linear map: the image of a linear map T is im⁡T={T(x):x is in the domain}.

Proof

1.1givenF1F5F6

Set τa=PaρPa. Self-adjointness of Pa and ρ gives ⟨τax,y⟩=⟨ρPax,Pay⟩=⟨x,τay⟩ for all x,y, so τa is self-adjoint. For every x∈H, ⟨τax,x⟩=⟨ρPax,Pax⟩≥0 by [F5] and [F6], so τa is nonnegative. Since pa>0 is real, scaling the same pairing identity by 1/pa makes ρa=τa/pa self-adjoint; its quadratic form is nonnegative as well, so ρa is nonnegative.

1.2givenF1F2F3F4F5

By [F3] and Pa2=Pa, tr⁡(τa)=tr⁡(PaρPa)=tr⁡(ρPa2)=pa by [F2]. Hence [F4] gives tr⁡(ρa)=pa/pa=1, so ρa is a density operator by [F5].

2.1givenF1F7step 1.1step 1.2∎

For every x∈H, ρax=Pa(ρPax)/pa is of the form Pay with y=ρPax/pa. By [F7], every such vector lies in im⁡(Pa), so im⁡(ρa)⊆im⁡(Pa).

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