Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-02
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A ring homomorphism whose kernel contains a two-sided ideal factors uniquely through the quotient ring

Statement

A ring homomorphism whose kernel contains a two-sided ideal factors uniquely through the quotient ring.

If I⊴R, f:R→S is a ring homomorphism, and I⊆ker⁡f, there is a unique ring homomorphism fˉ:R/I→S such that fˉ(r+I)=f(r).

Facts & Assumptions

Given: A two-sided ideal I⊴R and a ring homomorphism f:R→S with I⊆ker⁡f.

[L2]

A two-sided ideal is an additive subgroup (Left, right and two-sided ideals).

[L3]

Every subgroup of an abelian group is normal (Every subgroup of an abelian group is normal).

[L4]

The canonical quotient map is a surjective ring homomorphism (The canonical projection R→R/I is a surjective ring homomorphism with kernel I).

[L5]

A group homomorphism killing a normal subgroup factors uniquely through its quotient (A homomorphism that kills a normal subgroup factors uniquely through the quotient group).

[L6]

A ring homomorphism preserves addition, multiplication, and identity (Ring homomorphism: additive, multiplicative, and required to send 1 to 1).

Proof

technique · constructive
1.1

By [L1]--[L3], I is normal in the additive group of R; applying [L5] to the additive homomorphism underlying f defines fˉ(r+I)=f(r) and proves representative independence.

L1L2L3L5L6givenconstruct
2.1

Since [L4] gives (r+I)(s+I)=rs+I, one has fˉ((r+I)(s+I))=f(rs)=f(r)f(s), and fˉ(1+I)=f(1)=1; thus fˉ is a ring homomorphism.

step 1.1L4L6givenalgebra
3.1

The factor identity f=fˉ∘π holds by step 1.1, and any ring-homomorphic factor is additive, so the uniqueness in [L5] proves its uniqueness as a ring factor.

step 1.1step 2.1L5L6discharge-construct∎

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Sources