Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Cherednik BGG reciprocity and the KZ projective rank

Statement

For every E,F∈Irr⁡W, one has (P(E):Δ(F))=[∇(F):L(E)]=[Δ(F):L(E)]. Put rE=dim⁡KZ⁡(L(E)). Then PKZ⁡=⨁EP(E)rE represents the exact vector-space-valued KZ functor and dim⁡End⁡O(PKZ⁡)=∣W∣. This rank calculation uses no dimension or freeness hypothesis on the reflection Hecke algebra; the equality dim⁡Hq(c)(W)=∣W∣ remains an explicit extra hypothesis when this is used to prove the quotient equivalence.

Facts & Assumptions

Given: A finite complex reflection group W on h and an arbitrary conjugacy-invariant parameter c, with the current minus-sign Cherednik normalization.

[F1]

Projectives have standard flags and dim⁡Hom⁡(P(E),M)=[M:L(E)]; costandards have Hom/Ext1 orthogonality and the same K0 classes as standards (Cherednik category O has a standard-filtered projective generator, Cherednik costandards have orthogonality and the standard character).

Proof

1.1F1F2algebra

Apply Hom⁡(−,∇(F)) along a standard flag of P(E). The Hom and Ext1 orthogonality in [F1] makes the resulting Hom sequences short exact, and the dimension adds one exactly for a Δ(F) section. Thus (P(E):Δ(F))=dim⁡Hom⁡(P(E),∇(F)). The projective-cover Hom formula identifies the latter with [∇(F):L(E)], and the costandard character equality makes this [Δ(F):L(E)]. This proves BGG reciprocity with the highest-weight and projective prerequisites supplied by [F1].

2.1F1F2step 1.1algebra

Let F:Oc→C-vector spaces be any exact linear functor with finite-dimensional values. Put rE=dim⁡F(L(E)) and PF=⨁EP(E)rE. Choose a basis of each F(L(E)) and lift its finitely many vectors to F(P(E)), using exactness on P(E)↠L(E). For a chosen lift v, the map Hom⁡(P(E),M)→F(M) sending f to F(f)v is natural. Their sum gives Hom⁡(PF,−)→F. On every simple this is an isomorphism by the projective-cover Hom formula and the chosen basis. Both functors are exact, so induction on composition length, applied to their short exact value sequences, makes it an isomorphism on every object. With F=KZ⁡, this constructs the stated representing projective PKZ⁡. Some rE may be zero; no generation claim for all of Oc is needed.

3.1F1F2step 2.1algebra∎

Projective exactness and a standard flag give dim⁡Hom⁡(P(E),P(F))=[P(F):L(E)]=∑G(P(F):Δ(G))[Δ(G):L(E)]. Inserting BGG and the multiplicities rE into the endomorphism dimension yields dim⁡End⁡(PKZ⁡)=∑E,F,GrErF[Δ(G):L(E)][∇(G):L(F)]=∑Gdim⁡KZ⁡(Δ(G))dim⁡KZ⁡(∇(G)). A standard localizes to a vector bundle of rank dim⁡G; the monodromy fiber at the chosen regular basepoint has exactly that dimension, including the endpoint action used in the orbifold definition. Thus dim⁡KZ⁡(Δ(G))=dim⁡G. The equality in K0 from [F1] and exactness of KZ give the same dimension for ∇(G). Therefore dim⁡End⁡(PKZ⁡)=∑G(dim⁡G)2=∣W∣, by [F2]. No dimension or freeness assertion about the reflection Hecke algebra was used. Consequently this dimension comparison is available under precisely the separate Hecke-rank hypothesis stated for quotient equivalence.

Depends on

Used by

Dependency tree · two levels

17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources