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Refinement choices induce the same Čech map
Statement
Let be a topological space, let be a sheaf of abelian groups on , and let and be open covers of indexed by linearly ordered sets, with fixed-cover Čech cohomology (Fixed-cover Čech cohomology). Let be two refinement functions from to (Refinement map of ordered open covers) and let be the induced cochain maps. Then and are chain-homotopic (A chain homotopy), and consequently they induce the same homomorphism for every .
Explicitly, the homotopy is the family of degree maps for , and , where is evaluated at the displayed tuple of -indices in the alternating model (Ordered and alternating Čech complexes agree); it satisfies as maps , for every . In particular the refinement maps on cohomology do not depend on the choice of the refinement function.
Facts & Assumptions
, evaluated in the alternating model of , and commutes with the differentials (Refinement map of ordered open covers).
A refinement function from to satisfies for every (Refinement map of ordered open covers).
An ordered cochain extends to the alternating family with on tuples of pairwise distinct indices, so may be evaluated at an arbitrary tuple of -indices (Ordered and alternating Čech complexes agree).
A chain homotopy between chain maps consists of degree morphisms with for every (A chain homotopy).
A cochain complex is read as a chain complex by the reindexing convention , (Cochain complex in an abelian category).
Chain-homotopic chain maps induce the same map on homology: for every (Chain-homotopic maps induce the same map on homology).
is the cohomology of the ordered Čech complex (Fixed-cover Čech cohomology).
Restrictions are compatible and are group homomorphisms: for (Sections, restrictions, and global sections of a presheaf).
The -th cohomology object of a cochain complex is (Cohomology object of a cochain complex).
Proof
Given: A topological space , a sheaf of abelian groups on it, open covers , indexed by linearly ordered sets and two refinement functions from to .
Let be the cochain maps of the two refinement functions, so that and for every [F2] and the displayed formula of [F1] applies to both. For define on increasing tuples by the formula of the statement, and set . This is well defined: for a tuple the tuple has entries, so may be evaluated there in the alternating model [F3], and and for every by [F2], so the restriction lands in ; the map is additive in because evaluation and restriction are homomorphisms [F8].
Fix a tuple of pairwise distinct indices and suppress the restrictions to , which are compatible [F8]. Put for , a tuple of -indices, and for and let be the mixed tuple formed from the tuple with the -th entry deleted, so that has entries. Expanding the definitions, and , where is with the entry at position removed. Comparing entries gives when and when : deleting from and then forming the mixed tuple of split removes the entry , which occupies position of , in the first case, and removes the entry , which occupies position of , in the second.
Match the terms of the two sums. If then the pair of the second sum is admissible and contributes with coefficient , cancelling the term of the first sum; if then and the pair of the second sum is admissible with , contributing with coefficient and cancelling the same term. Conversely every term of the second sum is covered: a term with is the term of the first sum with , and a term with is the term of the first sum with . Hence in the sum all terms cancel in pairs except the terms of the first sum with and , that is and for .
It remains to identify the surviving terms. For the tuple deletes the entry at position of and hence equals , while deletes the entry at position of and hence equals ; in particular and . Therefore the surviving terms telescope: , the last equality by the formula of the cochain maps [F1] restricted to [F8].
Since was an arbitrary tuple of pairwise distinct indices, the identity holds as maps for every : for the first sum is empty because , and the second sum consists of the two surviving terms found in [step 2.1] and [step 3.1], which is the same computation. Reading the two cochain complexes as chain complexes by the reindexing convention [F5] and the family as a degree map, this identity is exactly the chain-homotopy relation of [F4] for , and , so and are chain-homotopic. By homotopy invariance [F6] they induce the same map on for every , that is the same map on for every , since is the -th cohomology object [F7] of the Čech complex, computed as a cokernel of cocycles by coboundaries [F9]. ∎
Depends on
- Refinement map of ordered open covers
- Ordered and alternating Čech complexes agree
- Chain-homotopic maps induce the same map on homology
- A chain homotopy
- Cochain complex in an abelian category
- Cohomology object of a cochain complex
- Fixed-cover Čech cohomology
- Sections, restrictions, and global sections of a presheaf
Used by
Dependency tree · two levels
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Sources
- The Stacks Project, Cohomology of Sheaves (standard reference, not scraped)
- Jiahui Gao and Shuwu Zhang, Lectures on Algebraic Geometry (standard reference, not scraped)