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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-22
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Regular value theorem for Banach manifolds

Statement

Assume the Axiom of Choice (The Axiom of Choice). Let M and N be Ck Banach manifolds with k1 (Countable base Banach manifold and smooth map), and assume that the specified Ck atlas of M is maximal: every Ck chart compatible with all of its charts is already a member of that atlas. Let f:MN be of class Ck, let qN and suppose that

Df(p):TpMTqN  is surjective with complemented kernel for every pf1(q).

Then f1(q) is a split Ck submanifold of M (Split Banach submanifold) and

Tp(f1(q))=kerDf(p)for every pf1(q).

Facts & Assumptions

Given: AC, Ck Banach manifolds M,N with k1, a maximal specified Ck atlas on M, a Ck map f:MN, a point qN, and for every pf1(q) a surjective Df(p) with complemented kernel.

[L1]

Tangents and differentials on Banach manifolds, the chart-independence of the differential, and functoriality (Tangent space and differential on a Banach manifold, Banach manifold differentials are chart independent); split submanifolds and their slices (Split Banach submanifold). A chart of a structured manifold means a member of its specified atlas; by the maximal-atlas hypothesis on M, every Ck chart compatible with that atlas is such a member (Countable base Banach manifold and smooth map).

[L2]

Implicit function theorem for Ck maps between Banach spaces, k1 (Implicit function theorem for Banach spaces); it is applied under the assumed AC.

[L3]

A bounded bijection between Banach spaces has a bounded inverse under DC (Bounded inverse theorem), and AC supplies DC (AC supplies the countable and dependent choices used in Banach integration).

[L4]

A complemented closed subspace has a closed complement with bounded projections; a bounded linear isomorphism carries a complemented subspace onto a complemented subspace (A complemented closed subspace of a normed space).

[L5]

Chain rule and the derivative of the identity for maps between open subsets of Banach spaces (Chain sum product and composition rules for Banach derivatives, Fréchet derivative between Banach spaces).

Proof

technique · direct
1.1

Fix pS:=f1(q) and choose specified-atlas charts φ0:UE of M at p and ψ:VF of N at q. Put a:=φ0(p) and b:=ψ(q). The translated coordinate map φ:=φ0a is a Ck chart compatible with the specified atlas of M; maximality therefore makes φ a chart of the structured manifold, and φ(p)=0. Writing L:=Df(p), the recentered coordinate representative f^(x):=ψ(f(φ1(x)))b is Ck on the open set Ω:=φ[Uf1[V]]E, satisfies f^(0)=0, and has Df^(0)=Dψ(q)LDφ(p)1. Translations have identity derivative, so this follows from chart functoriality and the chain rule without requiring a translated target chart to belong to the atlas of N.

L1L5
2.1

The kernel of Df^(0) is K:=Dφ(p)[kerL], a complemented subspace of E: the chart derivative Dφ(p) is a bounded linear isomorphism by [L1] and [L5] applied to φφ1=id, and [L4] transports the given complement of kerL to a complement of K; moreover Df^(0) is surjective, because Dψ(q) and Dφ(p) are isomorphisms and L is onto.

step 1.1L1L4L5
3.1

Fix a topological direct sum E=KE1 with bounded projections PK, PE1 existing by [step 2.1] and [L4], and let L1:=Df^(0)E1:E1F. Then L1 is a bounded linear bijection: it is injective because kerDf^(0)=K meets E1 only in 0, and surjective because Df^(0) is onto and agrees with L1 on E1; hence L11 is bounded by [L3] and AC supplies the DC that [L3] assumes.

step 2.1L3L4algebra
4.1

Define G:ΩF on the open set Ω:={(w,u)K×E1:w+uΩ} by G(w,u):=f^(w+u). Then G is Ck, G(0,0)=0, and its partial derivative in the second variable at (0,0) is L1, a bounded linear isomorphism by [step 3.1]; by [L2] there are open neighbourhoods AK of 0 and BE1 of 0 and a Ck map h:AB with {(w,u)A×B:f^(w+u)=0}={(w,h(w)):wA}.

step 3.1L2
5.1

The map Θ(w,u):=(w,uh(w)) is a homeomorphism of A×E1 onto itself with inverse (w,v)(w,v+h(w)), and both maps are Ck. It carries the zero set {(w,h(w)):wA} of [step 4.1] onto the slice A×{0}. Let U1:=φ1(A×B) and define Φ:=ΘφU1. Its image Θ(A×B) is open, and Φ is a Ck chart compatible with every specified-atlas chart χ: on each overlap the two transitions are Φχ1=Θφχ1,χΦ1=χφ1Θ1, restricted to open domains, hence are Ck. Maximality of the specified atlas of M now implies that Φ is a chart of the structured manifold. Finally, Φ[U1S]=Φ[U1](K{0}), so Φ is the split chart required by the library definition.

step 4.1L1L4L5algebra
6.1

In the charts Φ and ψ of [step 5.1], the coordinate representative of f is b+f^Θ1; its derivative at 0 is Df^(0)DΘ(0)1=Df^(0) because DΘ(0)=I. Indeed, h(0)=0 and Dh(0)=0, the latter by differentiating G(w,h(w))=0 at w=0 with [L5], which gives DKG(0,0)+L1Dh(0)=0 and DKG(0,0)=Df^(0)K=0. Consequently the kernel of the differential of f at p, computed in the charts Φ and ψ, is exactly the set of classes [Φ,k] with kK, which by [step 5.1] is the tangent space of S at p; hence TpS=kerDf(p).

step 5.1L1L4L5algebra
7.1

Since pS was arbitrary, [step 5.1] gives a split chart for S at every one of its points, so S is a split Ck submanifold of M, and [step 6.1] identifies its tangent space at each pS with kerDf(p).

step 5.1step 6.1

Depends on

Used by

Dependency tree · two levels

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