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Riemann-Roch for smooth projective surfaces

Statement

Assume the Axiom of Choice (The Axiom of Choice). Let k be a field, let X be an integral smooth projective surface over k, and let KX be a canonical divisor (The canonical divisor of a smooth projective surface). Then for every invertible OX-module L (Invertible sheaves) χ(X,L)=χ(X,OX)+12(L⋅L−L⋅KX), and equivalently, for every Cartier divisor D on X (Cartier divisor) with OX(D)≅L, χ(X,OX(D))=χ(X,OX)+12 D⋅(D−KX). Here χ is the Euler characteristic (Euler characteristic of a coherent sheaf). The right-hand side is an integer and is independent of the choice of canonical divisor and of the representative divisor of L (The canonical divisor of a smooth projective surface). No ampleness, effectivity or vanishing hypothesis is imposed on L.

Facts & Assumptions

Given: a field k, an integral smooth projective surface X over k, a canonical divisor KX, and an invertible sheaf L.

[F1]

The intersection product is defined by the alternating sum L1⋅L2=χ(X,OX)−χ(X,L1∨)−χ(X,L2∨)+χ(X,L1∨⊗L2∨) of Intersection numbers of Cartier divisors on a smooth projective surface, is symmetric and Z-bilinear, and satisfies L1∨⊗L1≅OX (The surface intersection product is symmetric and bilinear, Dual of a line bundle is its tensor inverse, Tensor product of sheaves of modules, Invertible sheaves).

[F2]

The canonical sheaf satisfies OX(KX)≅ωX=⋀2ΩX/k1, and KX⋅L=ωX⋅L for every invertible L (The canonical divisor of a smooth projective surface).

[F3]

Serre duality: for every invertible sheaf E the cup-product pairing Hq(X,E)×H2−q(X,E∨⊗ωX)→k is perfect with finite-dimensional groups, so χ(X,E)=χ(X,E∨⊗ωX); in particular χ(X,ωX)=χ(X,OX) (Serre duality for locally free sheaves on a smooth projective variety, Euler characteristic of a coherent sheaf).

[F4]

The Axiom of Choice is inherited from the Serre-duality and Euler-characteristic suppliers of [F3]; the sheaf L and the divisor KX are given data.

Proof

technique · direct: evaluate the defining alternating sum on the pair $(\mathcal L^{\vee},\mathcal L\otimes\omega_X^{\vee})$ and replace two terms by Serre duality
1.1F1

The defining sum. Put A:=L∨ and B:=L⊗ωX∨. By [F1], A⋅B=χ(X,OX)−χ(X,A∨)−χ(X,B∨)+χ(X,A∨⊗B∨)=χ(X,OX)−χ(X,L)−χ(X,L∨⊗ωX)+χ(X,ωX), because A∨≅L, B∨≅L∨⊗ωX and A∨⊗B∨≅ωX (Dual of a line bundle is its tensor inverse).

2.1F3step 1.1

Serre duality in the two last terms. By [F3] with E=L∨⊗ωX, whose dual twisted by ωX is L, we have χ(X,L∨⊗ωX)=χ(X,L); and χ(X,ωX)=χ(X,OX). Hence A⋅B=2(χ(X,OX)−χ(X,L)).

3.1F1F2step 1.1step 2.1

Bilinearity. By [F1] and [F2], A⋅B=L∨⋅(L⊗ωX∨)=−L⋅L+L⋅ωX=L⋅KX−L⋅L, where L⋅KX is the intersection with ωX by [F2]. Comparing with step 2.1 and rearranging, 2(χ(X,OX)−χ(X,L))=L⋅KX−L⋅L,that isχ(X,L)=χ(X,OX)+12(L⋅L−L⋅KX). The right-hand side is an integer because χ is; it depends only on the isomorphism class of L and on the canonical class, hence is independent of the chosen representative divisor and canonical divisor (The canonical divisor of a smooth projective surface).

4.1F4step 3.1∎

The divisor form. If D is a Cartier divisor with OX(D)≅L, then L⋅L=D⋅D and L⋅KX=D⋅KX by the dictionary of Intersection numbers of Cartier divisors on a smooth projective surface and The canonical divisor of a smooth projective surface, so χ(X,OX(D))=χ(X,OX)+12D⋅(D−KX). The Axiom of Choice is inherited from [F4]; no further selection is made.

Depends on

Used by

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Sources