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The signature of an oriented boundary vanishes, so the signature is an oriented cobordism invariant

Statement

Assume AC, inherited from Poincare-Lefschetz duality. Let W be a compact oriented smooth (4k+1)-manifold with boundary M=∂W carrying the induced orientation and inclusion i:M↪W. Then σ(M)=0. Consequently, if M0,M1 are closed oriented 4k-manifolds that are oriented cobordant (Oriented smooth cobordism), then σ(M0)=σ(M1): by Oriented smooth cobordism, ∂V=(−M0)⊔M1; reversing the orientation of V gives ∂(−V)=M0⊔(−M1) as an oriented boundary, so 0=σ(M0⊔(−M1))=σ(M0)−σ(M1) by The signature is additive under disjoint union and negates under orientation reversal. Hence σ descends to a well-defined additive map on oriented bordism classes Ω4kSO→Z and vanishes on null-cobordant classes (Null-cobordant closed manifolds).

Facts & Assumptions

Given: AC; a compact oriented smooth (4k+1)-manifold W with boundary M=∂W and inclusion i, with the induced boundary orientation.

[F1]

For a closed oriented 4k-manifold the signature is the inertia difference σ(M)=p−q of the nondegenerate middle form QM (The signature of a closed oriented manifold of dimension divisible by four, The middle-dimensional intersection form of a closed oriented 4k-manifold).

[F2]

With K=im⁡(i∗:H2k(W;R)→H2k(M;R)), one has K=K⊥QM, and K is a totally isotropic subspace of half the dimension of H2k(M;R) (The restriction image on a cobordism boundary is Lagrangian).

[F3]

A nondegenerate symmetric form with a totally isotropic subspace of exactly half the dimension has zero signature (A nondegenerate symmetric form with a half-dimensional isotropic subspace has zero signature).

[F4]

The signature is additive over disjoint unions and negates under orientation reversal: σ(X⊔Y)=σ(X)+σ(Y) and σ(−X)=−σ(X) (The signature is additive under disjoint union and negates under orientation reversal).

[F5]

Oriented cobordism is the equivalence relation generated by oriented bordisms: for a bordism V from M0 to M1, ∂V=(−M0)⊔M1, and a null-cobordant closed manifold bounds a compact oriented manifold (Oriented smooth cobordism, Null-cobordant closed manifolds, Unoriented and oriented bordism groups).

Proof

technique · direct; the boundary restriction image is a Lagrangian subspace, so the isotropic lemma kills the signature
1.1givenF1F2F3

Boundary vanishing: by [F2] the subspace K of H2k(M;R) is totally isotropic for the nondegenerate form QM and has dimension one half of dim⁡H2k(M;R); hence σ(M)=0 by [F1] and [F3].

2.1step 1.1F4F5

Cobordism invariance: let V be an oriented cobordism from M0 to M1, so that ∂V=(−M0)⊔M1 by [F5]. Reversing the orientation of V makes its boundary M0⊔(−M1), so step 1.1 gives 0=σ(M0⊔(−M1))=σ(M0)+σ(−M1)=σ(M0)−σ(M1) by [F4]; hence σ(M0)=σ(M1).

3.1step 1.1step 2.1F4F5∎

Descent: steps 1.1 and 2.1 show that σ is constant on oriented cobordism classes and vanishes on null-cobordant manifolds (which bound by [F5]); with additivity [F4] it descends to a well-defined additive map Ω4kSO→Z. The empty manifold has σ(∅)=0 and for k=0 the boundary of an oriented 1-manifold has signed count zero, consistent with step 1.1.

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