Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A stationary point process of finite intensity has mean measure rho times Lebesgue measure

Statement

Assume AC and Countable Choice, as carried by the random-point-process supplier. Let η be a stationary locally finite point process on Rd with 0<ρ:=E[η(Q)]<∞, where Q=[0,1)d. Its mean measure ν(B):=E[η(B)] is

ν(B)=ρλd(B)

for every Borel B⊆Rd.

Facts & Assumptions

Given: AC, Countable Choice, a stationary point process η, and 0<ρ=E[η(Q)]<∞.

[A1]

AC is carried by the transitive point-process supplier dependencies. (The Axiom of Choice)

[A2]

Countable Choice is carried by the transitive point-process supplier dependencies and is used for the Borel Lebesgue measure calculus. (The Axiom of Countable Choice (ACω))

[F1]

For a measurable random locally finite Borel measure, ν(B)=E[η(B)] is a measure; all evaluations are measurable. (Mean measures and measurable nonnegative integrals of random measures)

[F2]

Stationarity means the law is invariant under θx, and ρ=E[η(Q)] for Q=[0,1)d. (Stationarity, finite intensity, and spatial ergodicity)

[F3]

Every locally finite translation-invariant Borel measure m on Rd satisfies m(B)=m(Q)λd(B). (A locally finite translation-invariant Borel measure on Rd is a multiple of Lebesgue measure)

Proof

Given: AC, Countable Choice, a stationary point process η with ρ=Eη(Q)∈(0,∞), and its mean measure ν.

1.1givenF1F2

By [F1], ν(B)=E[η(B)] is a Borel measure, and ν(Q)=ρ.

2.1step 1.1F2algebra

Let B be bounded Borel. Choose an integer n with B⊆[−n,n)d. This cube is a finite disjoint union of translates Q+k, k∈{−n,…,n−1}d. Stationarity [F2] gives ν(Q+k)=E[η(Q+k)]=ρ for every such k. Monotonicity and finite additivity therefore give ν(B)≤(2n)dρ<∞. Hence ν is locally finite.

2.2step 1.1F2

For any Borel B and translation x, the definition of recentering gives ν(B+x)=E[η(B+x)]=E[(θxη)(B)]=E[η(B)]=ν(B), where the third equality is stationarity [F2]. Thus ν is translation invariant.

3.1A1A2step 1.1step 2.1step 2.2F3∎

Apply [F3] to the locally finite translation-invariant measure ν. Since ν(Q)=ρ by step 1.1, it follows that ν(B)=ρλd(B) for every Borel B. This is the claimed mean-measure formula.

Sources

Last and Penrose, Chapter 8, §8.1 and Proposition 8.2; Baddeley, Lecture 2, §2.4. The proof checks the mean-measure hypotheses locally.

Depends on

Used by

Dependency tree · two levels

21 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources