Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Every injective ring map from a domain into a field factors uniquely through its field of fractions

Statement

Let D be an integral domain, K a field, and f:DK an injective unital ring homomorphism. There is a unique unital ring homomorphism f~:Frac(D)K such that f~(d/1)=f(d) for all dD. It is injective and satisfies f~(a/b)=f(a)f(b)1.

Facts & Assumptions

Given: An injective unital ring homomorphism f:DK from an integral domain to a field.

[F1]

Every nonzero element of a field is a unit (Field).

[F2]

A map that sends every localisation denominator to a unit factors uniquely through the localisation, by the displayed fraction formula (Universal property of localisation: maps that invert S factor uniquely through S1R).

[F3]

The canonical map embeds D in Frac(D) (Frac(D) is a field and dd/1 embeds the integral domain D).

Proof

technique · direct
1.1

If b0 in D, injectivity gives f(b)0, so [F1] makes f(b) a unit. Since the denominators defining Frac(D) are exactly the nonzero elements, [F2] gives the unique extension and its formula.

F1F2
2.1

If f~(a/b)=0, multiply f(a)f(b)1=0 by the unit f(b) to obtain f(a)=0. Injectivity of f gives a=0, hence a/b=0. Thus f~ is injective.

step 1.1F3algebra

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 21 results over 14 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources