Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-09
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The function field is independent of the chosen nonempty principal affine open

Statement

Assume the Axiom of Choice, inherited from the Nullstellensatz route. For every nonempty affine open U in an affine variety X, restriction gives the canonical identification Frac(OX(U))=k(X). In particular, for f0, k[DX(f)]=k[X]f and Frac(k[DX(f)])=k(X). The identifications commute with further nonempty affine-open restriction.

Facts & Assumptions

Given: AC, an affine variety X over algebraically closed k, and a nonempty affine open UX. For the principal case, fk[X] is nonzero.

[F1]

Nonempty open section algebras embed in k(X), compatibly with restriction (Regular functions on a nonempty open embed in the affine function field).

[F3]

An injective map from a domain into a field extends uniquely to its fraction field (Every injective ring map from a domain into a field factors uniquely through its field of fractions).

[F5]

Proof

technique · direct
1.1

Put A=k[X], B=OX(U) and K=k(X). Restriction sends A into B, and the embedding BK of F1 sends each restricted polynomial a to a/1. Thus ABK with these specified maps, and B is a domain as a subring of a field.

F1F2given
2.1

F3 extends BK to an embedding Frac(B)K. Its image contains every a/b for a,bA, b0, since AB. Such fractions exhaust K by F2, so this extension is surjective and is the claimed isomorphism.

F2F3step 1.1
3.1

For U=D(f), F4 and F5 identify B with the affine coordinate ring Af, so step 2.1 is the asserted principal-open identification. For a further nonempty affine open V, both restriction embeddings into K agree on sections by F1; their extensions agree on every ratio by the uniqueness in F3.

F1F3F4F5step 2.1

Sources

Source comparison: Milne, Algebraic Geometry, v6.10, §3k p. 74 and Proposition 3.32 p. 71. Conventions here distinguish arbitrary affine algebraic sets from nonempty irreducible varieties.

Depends on

Used by

Dependency tree · two levels

31 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources