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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-09
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Classical integral varieties are birational exactly when their function fields are isomorphic over k

Statement

Assume the Axiom of Choice, inherited from the Nullstellensatz route. Two integral classical varieties over algebraically closed k are birationally equivalent exactly when their function fields are isomorphic over k. For affine varieties this is also equivalent to the existence of mutually inverse dominant rational maps.

Facts & Assumptions

Given: AC and integral classical varieties X,Y over the same algebraically closed field k, equipped with compatible affine atlases.

[F1]

Field embeddings correspond bijectively to dominant rational maps of affine varieties (Dominant rational maps to an affine variety correspond to field embeddings).

[F2]

Pullback reverses composition and preserves identities (Dominant maps pull back function fields functorially).

[F3]

Rational agreement on a nonempty open extends over the common domain for affine targets (Morphisms defined on an open source and agreeing on a dense open agree on their common domain).

[F4]

All nonempty affine opens of an integral variety have canonically the ambient field (Compatible affine charts of an integral classical variety have one function field).

[F5]

Charts and their compatible affine subopens are open in the whole variety (Integral classical varieties in the compatible affine-atlas register).

[F6]

Birational equivalence for integral varieties means isomorphic nonempty opens (Birational maps and birational equivalence of classical varieties).

[F7]

Principal opens form a basis in an affine chart (Principal opens form a basis and multiply under intersection).

[F8]

Proof

technique · direct
1.1

First let X,Y be affine and let σ:k(Y)k(X) be a k-isomorphism. F1 gives dominant rational maps Φ:XY and Ψ:YX for σ and σ1. F2 makes the pullbacks of their composites identity embeddings, and injectivity of the bijection in F1 forces both composites to be identity rational maps. Conversely mutually inverse dominant rational maps give inverse k-field embeddings by F2.

F1F2given
2.1

Choose representatives ϕ:UY and ψ:VX of the inverse maps. Set U0=Uϕ1(V) and V0=Vψ1(U). Dominance makes both nonempty open. Their compositions agree rationally with the identities; F3 extends those identities over all U0 and V0. If xU0, put y=ϕ(x). Then yV and ψ(y)=xU, so yV0. Conversely if yV0, x=ψ(y)U and ϕ(x)=yV, so xU0. Thus the restrictions U0V0 and V0U0 are inverse morphisms. This produces the required nonempty open isomorphism.

F3step 1.1algebra
3.1

Now let X,Y have compatible integral affine atlases and let their fields be k-isomorphic. Choose one nonempty affine chart in each. F4 transfers the field isomorphism to their chart fields, and steps 1.1–2.1 give isomorphic nonempty opens in these charts. By F5 these opens are open in the whole X and Y, so F6 makes X,Y birationally equivalent.

F4F5F6step 1.1step 2.1
4.1

Conversely suppose h:UV is an isomorphism of nonempty opens of X,Y. Take a point x of U, a chart A containing x and a chart B containing h(x). The open UAh1(B) contains x. F7 and F8 give a nonempty principal affine open W of A in it. Its image h(W) is open in Y and is affine via the isomorphism with W; its regular functions are identified with those on W. Taking fractions and applying F4 identifies k(X) with k(W), then with k(h(W)), then with k(Y), all over k. This proves the reverse direction and, together with steps 1.1–3.1, all claimed equivalences.

F4F5F7F8given

Sources

Source comparison: Milne, Algebraic Geometry, v6.10, Proposition 3.36 p. 74 and Proposition 5.39 p. 117. Conventions here distinguish arbitrary affine algebraic sets from nonempty irreducible varieties.

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Sources