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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-09
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Compatible affine charts of an integral classical variety have one function field

Statement

Assume the Axiom of Choice, inherited from the Nullstellensatz route. All nonempty affine charts and all nonempty affine opens of an integral classical variety X have canonically isomorphic fraction fields. These comparisons satisfy the cocycle identity on triple intersections and commute with restriction and isomorphisms. The resulting field is denoted k(X).

Facts & Assumptions

Given: AC, an integral classical variety X over algebraically closed k with a compatible affine atlas, and nonempty affine opens of X.

[F1]

Transition maps identify the regular functions on chart overlaps (Integral classical varieties in the compatible affine-atlas register).

[F2]

Two nonempty opens of an irreducible space meet, and every nonempty open remains irreducible (Irreducibility is equivalent to the nonempty-open intersection criterion).

[F3]

Principal opens form a basis in each affine chart (Principal opens form a basis and multiply under intersection).

[F4]

Nonempty principal opens of a chart are affine (Every nonempty principal open is a classical affine variety).

[F5]

An affine variety and a nonempty affine open have the same function field (The function field is independent of the chosen nonempty principal affine open).

[F6]

Equality of sections on a nonempty open determines equality of the associated fractions (Regular functions on a nonempty open embed in the affine function field).

Proof

technique · direct
1.1

Let U,V be two nonempty affine opens of X. Their overlap is nonempty by F2. F3 supplies a nonempty principal open WUV in U. By F4 it is affine, and F1 identifies its locally regular structure with that inherited from V. Thus W is also an affine open of V. F5 identifies both k(U) and k(V) with k(W), defining a comparison cUV:k(U)k(V).

F1F2F3F4F5given
2.1

For another choice W, the intersection WW is nonempty open in U. Choose a nonempty principal open T of U in that intersection. It is affine with the inherited structure in W and W. F5 says all field comparisons are restriction maps, and F6 says two fraction values that agree after restriction are equal. Both candidate comparisons therefore agree after passing to k(T), an isomorphic field, so they are equal.

F2F3F4F5F6step 1.1
3.1

For three nonempty affine opens U,V,Z, choose a nonempty principal open T of U inside UVZ, possible by applying F2 twice and then F3. By step 2.1 it may be used in every pairwise comparison. All three identifications then pass through k(T), so cVZcUV=cUZ, cUU is the identity, and cVU=cUV1. Restrictions commute by the same construction. An isomorphism of varieties carries common affine opens and their regular-function restrictions to common affine opens; its pullbacks commute pointwise with restrictions and hence with their field extensions. This proves compatibility with isomorphisms and defines a single field independent of the chosen chart.

F1F2F3F5step 1.1step 2.1

Sources

Source comparison: Milne, Algebraic Geometry, v6.10, 3k p. 74, 5.10 p. 103, §5k p. 116. Conventions here distinguish arbitrary affine algebraic sets from nonempty irreducible varieties.

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Sources