Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
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Uniqueness for the whole-space heat equation under Gaussian growth

Statement

Assume Countable Choice. Let T>0, C<∞, a≥0, and let u∈C([0,T]×Rn)∩C1,2((0,T]×Rn) satisfy ut−Δu=0 on Rn×(0,T), u(0,⋅)=0 and ∣u(t,x)∣≤Cea∣x∣2((t,x)∈[0,T]×Rn). Then u≡0.

Facts & Assumptions

Given: Countable Choice, T>0, C<∞, a≥0, and u in the stated class with ut−Δu=0 on Rn×(0,T), u(0,⋅)=0 and ∣u∣≤Cea∣x∣2 on the closed strip.

[A1]

Countable Choice is the ambient hypothesis (The Axiom of Countable Choice (ACω)).

[F1]

Whole-space maximum principle under Gaussian growth: if w∈C([0,T]×Rn)∩C1,2((0,T]×Rn) satisfies wt−Δw≤0 and w(t,x)≤Aea∣x∣2 on the closed strip, then sup⁡[0,T]×Rnw≤sup⁡Rnw(0,⋅), the finite subdivision into strips being available by the Archimedean property (Maximum principle on the whole space under Gaussian growth, Every complete ordered field is Archimedean).

Proof

Given: Countable Choice, T>0, C<∞, a≥0, and u satisfying ut−Δu=0 on the open strip, u(0,⋅)=0 and ∣u∣≤Cea∣x∣2 on the closed strip.

1.1A1F1given

The function u satisfies the hypotheses of [F1]: it lies in the stated class, ut−Δu=0≤0 on Rn×(0,T), and u≤∣u∣≤Cea∣x∣2 on the closed strip. Hence [F1] gives sup⁡[0,T]×Rnu≤sup⁡Rnu(0,⋅)=0, that is u≤0 everywhere on the strip.

2.1step 1.1F1F2given

By [F2] the function −u also lies in the class, with (−u)t−Δ(−u)=−(ut−Δu)=0≤0 on the open strip and (−u)(0,⋅)=0; moreover −u≤∣u∣≤Cea∣x∣2 on the closed strip. So [F2] and [F1] apply to −u and give sup⁡(−u)≤sup⁡(−u)(0,⋅)=0, that is u≥0 everywhere on the strip.

3.1step 1.1step 2.1F1given∎

Steps 1.1 and 2.1 give u≤0≤u on [0,T]×Rn, hence u≡0; the only choices made are the finite subdivisions supplied by the Archimedean property inside [F1], and Countable Choice is inherited from that supplier.

Depends on

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Sources