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CounterexampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)
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Bounded free-photon energy need not yield a Fock-vector limit

Statement refuted

Every normalized coherent family in the transverse free-photon Fock space with uniformly bounded expectation of Hph=ℏc dΓ(∣k∣) converges strongly in that Fock space as its infrared cutoff ϵ↓0.

Construction

Take a unit vector e∈R3, set b(n)=PT(n)e for n∈S2, fix κ>0, and use fϵ(k)=1{ϵ<∣k∣<κ}∣k∣−3/2b(k^). This gives the explicit transverse coherent family from Logarithmic coherent infrared tail: finite energy, no Fock limit.

Facts & Assumptions

Given: The planned transverse free-photon space and the exact coherent-family result of Logarithmic coherent infrared tail: finite energy, no Fock limit.

[F1]

Logarithmic coherent infrared tail: finite energy, no Fock limit: for any transverse b with Cb=∫S2∣b∣2dΩ>0, the vectors C(fϵ) have norm one, energy expectation ℏc Cb(κ−ϵ), weak limit zero, and no strong Fock-space limit.

[A1]

e∈R3 is a unit vector, κ>0, and ℏ,c>0; cutoffs satisfy 0<ϵ<κ. These are the chosen model parameters in the Counterexample.

[F2]

Agreement with the existing polar sphere measure: the Euclidean chart measure on S2 equals polar surface measure and is invariant under orthogonal transformations.

[F3]

Surface integration on compact C1 hypersurfaces: surface integration is the Euclidean chart integral with density det⁡(DXTDX).

[A2]

The Axiom of Countable Choice (ACω): assume the same Countable Choice carried by the coherent-tail and surface-measure suppliers; no stronger choice principle is used.

Counterexample

Given: [A1]–[A2], [F1]–[F3], and the profile in the Counterexample.

1.1A1A2F1F2F3algebra

For b(n)=PT(n)e, ∣b(n)∣2=1−(n⋅e)2. By [F2], rotate e to the third coordinate axis. The regular sphere chart X(y,z)=(1−y2−z2,y,z) on ∣y∣,∣z∣<1/4 lies in the belt ∣n⋅e∣<1/2 and has area density (1−y2−z2)−1/2≥1 by [F3]. Its parameter rectangle has area 1/4, so this belt has positive surface measure. On the belt ∣b(n)∣2≥3/4, hence Cb>0; also b is continuous, square-integrable on the finite sphere measure, and transverse.

2.1A1A2F1step 1.1algebra∎

Apply [F1] to this b. It gives unit vectors with 0≤⟨C(fϵ),HphC(fϵ)⟩≤ℏc Cbκ<∞, yet no strong Fock-space limit. This contradicts the asserted implication and is the required counterexample.

Depends on

Dependency tree · 2 levels

Sources