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Finite matrix formal inverse and gauge-covariant kernel — Examples

1 · Prerequisites

2 · Summary

These examples give a rational off-shell Dirac matrix check, the exact transverse angular coefficient for a fixed vector, and a bounded-energy coherent family without a strong Fock limit. The last result is a counterexample in the declared free transverse-mode model, not a construction of an interacting charged QED sector. Draft QFT-MG01 supplier carriers are present, and their page inventory lists those items; the prerequisite records retain the exact mathematical hypotheses, with independent review and native readiness recorded separately.

3 · Logical flowchart

4 · Definitions, postulates, theorems and proofs

None yet.

5 · Examples, experiments and counterexamples

ExampleConstruction: AI-adaptedVerification: AI-adaptedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)Open item page →

Exact rational Dirac Ward matrix example

Example

For any μ>0, use h=diag⁡(1,−1,−1,−1), p=(0,0,0,0), and k=(2μ,0,0,0). Both p and p+k are off shell. The exact rational matrices are S0(p)=−1μI4,S0(p+k)=2β+I43μ,Γ(k)=2μβ.

Facts & Assumptions

Given: μ>0, p=0, k=(2μ,0,0,0), and the Dirac matrices in Off-shell free Dirac Ward telescoping and tree currents.

[F1]

Off-shell free Dirac Ward telescoping and tree currents: when both h(p,p)−μ2 and h(p+k,p+k)−μ2 are nonzero, S0(p)=(Γ(p)+μI4)/(h(p,p)−μ2) and S0(p+k)Γ(k)S0(p)=S0(p)−S0(p+k).

[F2]

Dirac Clifford matrices and energy projections: β=diag⁡(I2,−I2), so β2=I4; the item fixes Γ(p) with the effective matrix h=−η.

[A1]

μ>0 has inverse-length units; the momenta p=0 and k=(2μ,0,0,0) use the same inverse-length coordinate convention as Off-shell free Dirac Ward telescoping and tree currents.

Verification

Given: [F1], [F2], and the numerical momenta and positive parameter in the Example.

1.1A1F1algebra

Here h(p,p)−μ2=−μ2 and h(p+k,p+k)−μ2=3μ2, so both rational inverses are defined. Since Γ(p)=0 and Γ(k)=2μβ, the inverse formula in [F1] gives the displayed S0(p) and S0(p+k).

2.1F1F2step 1.1algebra∎

Using β2=I4 from [F2], S0(p+k)Γ(k)S0(p)=−(2β+I4)2β3μ=−4I4+2β3μ=S0(p)−S0(p+k). Thus this off-shell rational instance satisfies the exact matrix Ward identity.

ExampleConstruction: AI-adaptedVerification: AI-adaptedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)Open item page →

Fixed-vector transverse angular coefficient 8π/3

Example

Let e∈R3 be a unit vector and PT(n)=I3−nn⊤ for n∈S2. Then the angular coefficient in the coherent infrared family with b(n)=λPT(n)e, λ∈R∖{0}, is ∫S2∣b(n)∣2 dΩ=8πλ23.

Facts & Assumptions

Given: The unit vector e, the scalar λ≠0, and the transverse projection and angular integral in Logarithmic coherent infrared tail: finite energy, no Fock limit.

[F1]

Logarithmic coherent infrared tail: finite energy, no Fock limit uses PT(n)=I3−nn⊤ and Cb=∫S2∣b(n)∣2dΩ for a measurable transverse b∈L2(S2;C3).

[A1]

e∈R3 is a unit vector and λ∈R∖{0}, as stated in the Example.

[F2]

Agreement with the existing polar sphere measure: the Euclidean chart measure on S2 equals polar surface measure and is invariant under orthogonal transformations.

[F3]

Surface integration on compact C1 hypersurfaces: surface integration is the Euclidean chart integral with density det⁡(DXTDX).

[F4]

A box with a degenerate side is Lebesgue null, and so is every coordinate hyperplane in Rn: coordinate hyperplanes and singletons have Lebesgue measure zero, hence chart seams and poles have zero area when their coordinate parameter sets are null.

[A2]

The Axiom of Countable Choice (ACω): assume the same Countable Choice carried by the coherent-tail and surface-measure suppliers; no stronger choice principle is used.

Verification

Given: [A1]–[A2], [F1]–[F4] and the specified b(n)=λPT(n)e.

1.1A1A2F1F2F3F4algebra

Since [A1] gives ∣e∣=1 and ∣n∣=1, ∣PT(n)e∣2=e⊤(I3−nn⊤)e=1−(n⋅e)2. Rotational invariance in [F2] permits taking e=(0,0,1). Use the chart X(u,ϕ)=(1−u2cos⁡ϕ,1−u2sin⁡ϕ,u) for −1<u<1 and 0<ϕ<2π. Its tangent vectors are orthogonal with squared lengths (1−u2)−1 and 1−u2, so [F3] gives area density 1. The omitted azimuthal seam is a coordinate line in sphere graph charts, and each pole is a singleton in its graph chart; these parameter sets are null by [F4], and their chart integrals vanish. Thus with u=n3 the angular integral is 2π∫−11(1−u2) du.

2.1A1A2F1step 1.1algebra∎

The integral equals 2π[u−u3/3]−11=8π/3. Multiplying by λ2 yields Cb=8πλ2/3>0, which is the coefficient required by [F1].

CounterexampleConstruction: AI-adaptedVerification: AI-adaptedverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)Open item page →

Bounded free-photon energy need not yield a Fock-vector limit

Statement refuted

Every normalized coherent family in the transverse free-photon Fock space with uniformly bounded expectation of Hph=ℏc dΓ(∣k∣) converges strongly in that Fock space as its infrared cutoff ϵ↓0.

Construction

Take a unit vector e∈R3, set b(n)=PT(n)e for n∈S2, fix κ>0, and use fϵ(k)=1{ϵ<∣k∣<κ}∣k∣−3/2b(k^). This gives the explicit transverse coherent family from Logarithmic coherent infrared tail: finite energy, no Fock limit.

Facts & Assumptions

Given: The planned transverse free-photon space and the exact coherent-family result of Logarithmic coherent infrared tail: finite energy, no Fock limit.

[F1]

Logarithmic coherent infrared tail: finite energy, no Fock limit: for any transverse b with Cb=∫S2∣b∣2dΩ>0, the vectors C(fϵ) have norm one, energy expectation ℏc Cb(κ−ϵ), weak limit zero, and no strong Fock-space limit.

[A1]

e∈R3 is a unit vector, κ>0, and ℏ,c>0; cutoffs satisfy 0<ϵ<κ. These are the chosen model parameters in the Counterexample.

[F2]

Agreement with the existing polar sphere measure: the Euclidean chart measure on S2 equals polar surface measure and is invariant under orthogonal transformations.

[F3]

Surface integration on compact C1 hypersurfaces: surface integration is the Euclidean chart integral with density det⁡(DXTDX).

[A2]

The Axiom of Countable Choice (ACω): assume the same Countable Choice carried by the coherent-tail and surface-measure suppliers; no stronger choice principle is used.

Counterexample

Given: [A1]–[A2], [F1]–[F3], and the profile in the Counterexample.

1.1A1A2F1F2F3algebra

For b(n)=PT(n)e, ∣b(n)∣2=1−(n⋅e)2. By [F2], rotate e to the third coordinate axis. The regular sphere chart X(y,z)=(1−y2−z2,y,z) on ∣y∣,∣z∣<1/4 lies in the belt ∣n⋅e∣<1/2 and has area density (1−y2−z2)−1/2≥1 by [F3]. Its parameter rectangle has area 1/4, so this belt has positive surface measure. On the belt ∣b(n)∣2≥3/4, hence Cb>0; also b is continuous, square-integrable on the finite sphere measure, and transverse.

2.1A1A2F1step 1.1algebra∎

Apply [F1] to this b. It gives unit vectors with 0≤⟨C(fϵ),HphC(fϵ)⟩≤ℏc Cbκ<∞, yet no strong Fock-space limit. This contradicts the asserted implication and is the required counterexample.

Sources