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A gradient load observed through Stokes pressure
Example
Assume Countable Choice. Let , let be a nonempty bounded connected Lipschitz open set, and let . Use with gradient norm and . Define and . The load is the gradient forcing in the weak sense. The unique weak Stokes solution is , and the bounded gauge-invariant sensor has reading .
Example references
Guermond, MATH 661, Chapter 53, §§53.1–53.2.2, homogeneous weak Stokes formulation, pressure gauge, and well-posedness.
Boffi–Brezzi–Fortin, Mixed Finite Element Methods and Applications, §§4.2.1–4.2.3 and §8.2.1, Example 4.2.2, pp. 225–229, 233–234, and 462–463, weak Stokes solvability and pressure modulo constants.
Facts & Assumptions
Given: Countable Choice; the stated domain and viscosity; the homogeneous weak Stokes spaces and equations; and the coordinate function on .
Countable Choice is required for the weak Stokes solvability input. Weak Stokes solvability on bounded connected Lipschitz domains
Stokes velocity and pressure spaces and weak forms: is the -closure of compactly supported smooth fields, , and the pressure term is .
Weak Stokes solvability on bounded connected Lipschitz domains: every bounded load in has a unique weak Stokes pair with its pressure in .
Lipschitz stability of bounded Stokes pressure observations: denotes that unique normalized pressure for load .
Bounded Stokes pressure sensors: a sensor is a bounded real-linear functional on .
Gauge-invariant pressure sensor weights: a weight in defines a bounded gauge-invariant pressure sensor.
Cauchy-Schwarz inequality for : the integral pairing of functions is bounded by the product of their norms.
Verification
Since is nonempty and open it contains a ball, so ; boundedness gives . Hence and is finite. Thus , , and its weak gradient is .
For , weak integration by parts gives . By the -closure in [F1], approximate any by such fields; both integrals converge by Cauchy–Schwarz, so the identity holds for all . Pointwise , whence and .
For every , by step 2.1, while for every . Thus satisfies both weak Stokes equations. Uniqueness in [F2] identifies it with the solution, so the pressure notation in [F3] gives .
By [F6], is bounded on ; by [F4], [F5], and , it is a bounded gauge-invariant sensor. Since a nonempty open contains a ball and no ball is contained almost everywhere in a hyperplane , is not zero almost everywhere; therefore .