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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Direct check of the flat power-law data against the Friedmann-system equations

Example

Fix real constants c>0, GN>0, A>0, t∗>0, t0∈R and w>−1, and put

q:=23(1+w),I:=(t0,∞),a(t):=A(t−t0t∗)q,ε(t):=3c2q28πGN (t−t0)2,p(t):=w ε(t),

with real powers in the sense of Real powers for positive bases, with the zero-base positive-exponent convention. Then:

  1. The functions a,ε,p are smooth on I, a(t)>0 and ε(t)>0 for every t∈I, and on I

H(t)=qt−t0,a¨(t)a(t)=q(q−1)(t−t0)2.

  1. The Friedmann-system datum (c,GN,0,I,0,a,ε,p) satisfies the Friedmann equation (F), the acceleration equation (A), the continuity equation (C) and the spatial-component equation (S) of The Friedmann, acceleration and continuity equations of an FLRW model datum on I. In particular w=0 gives q=23 and w=13 gives q=12.

Facts & Assumptions

Given: The constants c,GN,A,t∗,t0,w with c>0, GN>0, A>0, t∗>0, w>−1, the interval I=(t0,∞), the functions a,ε,p of the example, and the equations (F), (A), (C), (S) of The Friedmann, acceleration and continuity equations of an FLRW model datum.

[L1]

For x>0 and real α the real power xα=exp⁡(αlog⁡x) is strictly positive, continuous and differentiable on (0,∞) with (xα)′=αxα−1, and (xα)β=xαβ for real β (Real powers for positive bases, with the zero-base positive-exponent convention, Continuity and derivatives of positive-base real powers, The exponent, product, quotient, and iterated-power laws for positive real bases and real exponents). Smoothness on an open real interval means that derivatives of every finite order exist and are continuous; it will be established locally in step 1.1.

H2=8πGN3c2ε,a¨a=−4πGN3c2(ε+3p),ε˙+3H(ε+p)=0,−2aa¨+a˙2c2=8πGNc4 p a2,

where the first display is (F), the second (A), the third (C) and the fourth (S), each required at every point of I.

[L4]

The defining relations q=2/(3(1+w)) and w>−1 give q>0 and 3(1+w)q=2; equivalently 1+w=2/(3q) and 3q(1+w)=2.

Verification

1.1L1L2L4givenalgebra

(Smoothness and positivity.) Put u(t):=(t−t0)/t∗>0 on I. For every real α and integer m≥0, repeated application of [L1] and [L2] gives dmdtmu(t)α=t∗−m(∏r=0m−1(α−r))u(t)α−m, with empty product 1: at m=0 this is the function itself, and differentiating the formula at m introduces the factor (α−m)/t∗ and lowers the exponent by one, proving the formula at m+1. Each derivative is continuous by [L1] and continuity of the affine function u, so uα is smooth. Taking α=q proves smoothness of a=Auq; the same argument with the positive affine function v(t)=t−t0, whose derivative is 1, and α=−2 proves smoothness of ε=3c2q2v−2/(8πGN) and hence of p=wε. Finally a>0 by [L1] and A>0, and ε>0 because c,GN>0, q>0 by [L4], and v>0.

2.1L1L2step 1.1algebra

(Derivatives and the Hubble parameter.) By [L2], u˙=1/t∗ and a˙=Aq uq−1u˙=Aq uq−1/t∗. Since uq/(t−t0)=uq−1/t∗, this is a˙=q a/(t−t0), so H=a˙/a=q/(t−t0). Differentiating a˙=qa/(t−t0) by the product and quotient rules gives a¨=q(a˙(t−t0)−a)/(t−t0)2=q(q−1)a/(t−t0)2, hence a¨/a=q(q−1)/(t−t0)2. Also ε˙=−6c2q2/(8πGN(t−t0)3)=−2ε/(t−t0). This proves claim 1.

3.1L3step 2.1algebra

(Friedmann equation.) By [L3], (F) with k=0 is H2=8πGNε/(3c2). By step 2.1, H2=q2/(t−t0)2; by the definition of ε, 8πGN3c2ε=8πGN3c2⋅3c2q28πGN(t−t0)2=q2(t−t0)2. The two sides agree at every point of I.

3.2L3L4step 2.1algebra

(Acceleration equation.) By [L3], (A) with Λ=0 is a¨/a=−4πGN(ε+3p)/(3c2). By step 2.1 and p=wε, the left-hand side is q(q−1)/(t−t0)2 and the right-hand side is −4πGN3c2(1+3w)3c2q28πGN(t−t0)2=−(1+3w)q22(t−t0)2. Since q>0 by [L4], the needed identity q(q−1)=−12(1+3w)q2 is equivalent to 2q−2=−(1+3w)q, that is, to 3(1+w)q=2, which is [L4]. Hence (A) holds.

3.3L3L4step 2.1algebra

(Continuity equation.) By step 2.1, ε˙=−2ε/(t−t0); by steps 2.1 and [L4], 3H(ε+p)=3qt−t0(1+w)ε and 3q(1+w)=2, so 3H(ε+p)=2ε/(t−t0). Hence ε˙+3H(ε+p)=0 on I, which is (C).

3.4L3L4step 2.1algebra

(Spatial-component equation.) By [L3], (S) with k=Λ=0 is −(2aa¨+a˙2)/c2=8πGN p a2/c4. By step 2.1, 2aa¨+a˙2=(2q(q−1)+q2)a2/(t−t0)2=(3q2−2q)a2/(t−t0)2; the right-hand side is 8πGNc4w3c2q28πGN(t−t0)2a2=3wq2a2c2(t−t0)2. Equality of the two displayed expressions is equivalent to −(3q2−2q)=3wq2, that is, to 2q=3q2(1+w), which holds because 3q(1+w)=2 by [L4]; hence (S) holds.

4.1step 1.1step 2.1step 3.1step 3.2step 3.3step 3.4∎

(Conclusion.) Steps 1.1 and 2.1 establish claim 1, and steps 3.1, 3.2, 3.3 and 3.4 establish (F), (A), (C) and (S) at every point of I, which is claim 2; the last sentence of claim 2 is the substitution w=0, w=13 in q=2/(3(1+w)). No equation of state beyond p=wε, no field equation and no physical premise was used.

Remarks

  • What is checked. The example verifies the displayed data against all four scalar equations of The Friedmann, acceleration and continuity equations of an FLRW model datum by direct differentiation; in particular it does not invoke the equivalence proposition of the A page, so it independently exhibits data satisfying (F), (A), (C) and (S) simultaneously. The physically interpreted field-equation reading of these data belongs to the physics theorem on the A page and is not asserted here.

  • What is not claimed. No uniqueness, no statement about the limit t↓t0, no extension beyond I and no numerical value of any constant is asserted; A, t∗ and t0 are arbitrary real model data with A>0, t∗>0.

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