Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passverified 2026-10-22 (gpt-6.1-sol)
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Scalar-field potential and Cauchy-data pairing

Example

Let T3:=R3/Z3 with quotient map q:R3→T3, and let M:=Rt×T3. The one-forms dx,dy,dz on T3 are the forms descended from the translation-invariant coordinate one-forms on R3; ∂x,∂y,∂z denote their dual descended coordinate vector fields. For f∈C∞(M,R), spatial derivatives mean derivatives of its Z3-periodic lift to Rt×R3. Define ∇f:=(∂xf,∂yf,∂zf),∣∇f∣2:=(∂xf)2+(∂yf)2+(∂zf)2,Δf:=∂x2f+∂y2f+∂z2f. Give M the orientation dt∧dx∧dy∧dz and flat metric g=−dt2+dx2+dy2+dz2, and write vol=dt∧dx∧dy∧dz. The constant-time cut Σt={t}×T3 has orientation dx∧dy∧dz, equal to contraction of vol with ∂t.

Distinguish this geometric cut from its representing chain. Let it:T3→M be the inclusion it(p)=(t,p), with image Σt. In positive affine coordinates on the standard simplex, put T3:={r∈R3:rj≥0, r1+r2+r3≤1} with orientation dr1∧dr2∧dr3. For each permutation ρ∈S3, put v0ρ=0 and vjρ:=∑k=1jeρ(k) for 1≤j≤3, where e1,e2,e3 is the standard basis of R3. Define aρ(r):=∑j=13rjvjρ,Q:=∑ρ∈S3sgn⁡(ρ) aρ. Here Q is a finite smooth singular three-chain in R3. For a smooth map f, its chain pushforward means composition of each simplex: f#(∑jcjσj):=∑jcj(f∘σj). The representing chain in M is Ct:=(it∘q)#Q=∑ρ∈S3sgn⁡(ρ) τt,ρ,τt,ρ:=it∘q∘aρ. Every simplex has the stated domain orientation and coefficient sgn⁡(ρ). The affine images are the six ordered-coordinate regions of the cube. Adjacent regions have identical ordered face maps and opposite signed face coefficients; on the exterior, opposite cube faces have matching ordered face maps after q, again with opposite coefficients. Thus ∂Ct=0. By saying that Ct represents the oriented cut Σt, we mean precisely that for every smooth three-form α on M, ∫Ctα=∫[0,1]3(it∘q)∗α. The right side integrates the coefficient relative to dx∧dy∧dz. This equality follows by summing the six simplex pullbacks with their orientation coefficients, as checked in step 3.1; it invokes only this explicit cube decomposition. Restrictions of fields and forms below are to the geometric cut Σt, whereas boundary and chain-integration operations use Ct.

For one-forms, define the Hodge map by ∗dt=−dx∧dy∧dz,∗dx=−dt∧dy∧dz,∗dy=dt∧dx∧dz,∗dz=−dt∧dx∧dy, and extend it linearly with smooth coefficients. Let ψ∈C∞(M,R), let μ≥0 be a fixed real parameter, and take L=−12dψ∧∗dψ−12μ2ψ2vol. All objects here are mathematical; no physical units or empirical interpretation are assigned. Let u1,u2∈C∞(M,R) satisfy (−∂t2+Δ−μ2)ui=0(i=1,2), and define the smooth two-parameter field family ψa,b:=au1+bu2 on P=R2. At (a,b)=(0,0) the base solution is ψ=0; the commuting parameter variations are δ1ψ:=∂aψa,b=u1 and δ2ψ:=∂bψa,b=u2. The chosen potential and current are θ(ψ;δψ)=−δψ∗dψ,ω(δ1,δ2)=δ2ψ∗dδ1ψ−δ1ψ∗dδ2ψ. On the oriented finite smooth singular cycle Ct defined above, the integrated form is ΩCt(δ1,δ2)=∫[0,1]3(δ1ψ ∂tδ2ψ−δ2ψ ∂tδ1ψ) dx dy dz. The integral on the right is over the fundamental cube for the descended three-form. The initial-data pair used here is (ψ∣Σt,∂tψ∣Σt). Write L=Lcoord vol; then Lcoord=12(∂tψ)2−12∣∇ψ∣2−12μ2ψ2. Define its canonical momentum density by π:=∂Lcoord∂(∂tψ)=∂tψ. Thus the displayed form is the canonical pairing of the variations of (ψ∣Σt,π∣Σt).

Facts & Assumptions

Given: The flat oriented product spacetime, the real scalar ψ, the parameter μ≥0, the displayed Lagrangian and Hodge map, and a smooth two-parameter family of field variations.

[F1]

The chosen current ordering is ω(δ1,δ2)=δ2θ(δ1)−δ1θ(δ2), and ΩΣ=∫Σω. Covariant presymplectic current

[F2]

If the Euler form vanishes and both variations solve the linearized equations, then dMω=0. On-shell closure and finite-region symplectic flux

[F3]

A change L↦L+dMμ, θ↦θ+δμ+dMY changes the integrated form only by the corresponding integral over ∂Σ. Potential ambiguity changes the current by a corner term

[F4]

A reduced symplectic phase space is asserted only after a smooth solution space and smooth quotient satisfying the stated hypotheses are supplied. Admissible presymplectic reduction and Hamiltonian generators

[F5]

The exterior derivative obeys the degree-one graded product rule. The exterior derivative is a graded derivation

[F6]

In coordinates, d(∑IfI dxI)=∑IdfI∧dxI. The local coordinate formula for the exterior derivative

[F7]

The wedge product of forms is the pointwise wedge of their alternating covariant tensors. The wedge product of differential forms

Verification

Given: As in [F1]–[F4]. The base field is ψ=0 when the on-shell closure clause is used; the displayed variations satisfy the linearized equation.

1.1givenF5F6F7algebra

In coordinates, L=(12ψt2−12∣∇ψ∣2−12μ2ψ2)vol, so δL=(ψtδψt−∇ψ⋅∇δψ−μ2ψδψ)vol. The graded product rule [F5] and the displayed Hodge map give dM(δψ∗dψ)=dδψ∧∗dψ+δψ dM∗dMψ, and [F6] gives dM∗dMψ=(−ψtt+Δψ)vol. Therefore δL=δψ(−ψtt+Δψ−μ2ψ)vol−dM(δψ∗dψ), so the selected potential is θ=−δψ∗dψ.

2.1givenF1algebrastep 1.1

Apply the two commuting parameter derivatives to θ. The terms containing δ1δ2ψ cancel, leaving δ2θ(δ1)−δ1θ(δ2)=δ2ψ∗dMδ1ψ−δ1ψ∗dMδ2ψ. This is [F1]'s current in the chosen sign order.

2.2givenF2F3step 1.1

At ψ=0, the Euler equation is −ψtt+Δψ−μ2ψ=0. The linearized variations obey the same equation, so [F2] gives dMω=0. Since ∂Ct=0, [F3] shows that a potential ambiguity does not change the integrated pairing on this cut.

3.1step 2.1algebra

On a constant-t cut, the pullbacks satisfy (∗df)∣Σt=−(∂tf) dx∧dy∧dz for every smooth f. Step 2.1 therefore gives ω∣Σt=(δ1ψ ∂tδ2ψ−δ2ψ ∂tδ1ψ) dx∧dy∧dz. The affine map for ρ has Jacobian determinant sgn⁡(ρ) and image 1≥xρ(1)≥xρ(2)≥xρ(3)≥0. Hence the six regions partition the cube up to common faces, and the coefficient sgn⁡(ρ) orients each simplex positively relative to dx∧dy∧dz. A common interior face is obtained by swapping adjacent entries of ρ; deleting the distinct intermediate vertex gives the same ordered face map, while the permutation coefficient changes sign, so these boundary terms cancel as singular chains. On opposite exterior faces, the remaining coordinate-order triangles have identical ordered vertex maps after translation by ei, hence after applying q; their induced boundary orientations are opposite, so they cancel as well. Thus ∂Ct=0, and integration over this chain equals integration of the descended form over [0,1]3, giving the displayed formula.

4.1givenstep 3.1algebra

The coordinate density gives π=∂Lcoord/∂ψt=ψt. Substitution into step 3.1 yields ΩCt(δ1,δ2)=∫(δ1ψ δ2π−δ2ψ δ1π), the canonical Cauchy-data pairing.

5.1F4step 4.1∎

Step 4.1 computes the integrated two-form but does not prove the global smooth solution-space or quotient hypotheses in [F4]. Thus this example asserts the Cauchy pairing for the displayed model and cut only; it claims no general symplectic reduction.

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