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Closed bulk current with nonzero boundary flux

Example

Let M=R4 with coordinates (X1,X2,X3,X4)=(t,x,y,z), orientation dt∧dx∧dy∧dz, and flat metric −dt2+dx2+dy2+dz2. For one-forms use ∗dt=−dx∧dy∧dz,∗dx=−dt∧dy∧dz,∗dy=dt∧dx∧dz,∗dz=−dt∧dx∧dy. Here the massless wave equation means (−∂t2+∂x2+∂y2+∂z2)u=0. Let u1:=t2+x2 and u2:=t, and define the smooth field family ψa,b:=au1+bu2 on P=R2. Both u1,u2 solve the massless wave equation, so ψ=0 at (a,b)=(0,0) is a solution and δ1ψ:=∂aψa,b=u1, δ2ψ:=∂bψa,b=u2 are commuting variations solving that same equation. Use the massless scalar Lagrangian L=−12dψ∧∗dψ, with selected potential θ(ψ;δψ)=−δψ∗dψ and current ω(δ1,δ2)=δ2ψ∗dδ1ψ−δ1ψ∗dδ2ψ. For 0<t1<t2 and L>0, put a0=(t1,0,0,0) and (ℓ1,ℓ2,ℓ3,ℓ4)=(t2−t1,L,1,1). Let T4:={r∈R4:rj≥0, ∑j=14rj≤1} with orientation dr1∧dr2∧dr3∧dr4. For each permutation ρ∈S4, define vertices v0ρ:=a0,vjρ:=a0+∑k=1jℓρ(k)eρ(k)(1≤j≤4), where e1,e2,e3,e4 is the standard basis in the ordered coordinates (t,x,y,z). Define the 24 affine simplex maps and their oriented sum by σρ(r):=v0ρ+∑j=14rj(vjρ−v0ρ),C:=∑ρ∈S4sgn⁡(ρ) σρ. Each map has domain orientation dr1∧dr2∧dr3∧dr4; the coefficient sgn⁡(ρ) orients it relative to dt∧dx∧dy∧dz.

For t∈{t1,t2}, let bt=(t,0,0,0) and (m1,m2,m3)=(L,1,1). With T3:={r∈R3:rj≥0, ∑j=13rj≤1} oriented by dr1∧dr2∧dr3, define, for ρ∈S3, w0t,ρ:=bt,wjt,ρ:=bt+∑k=1jmρ(k)e^ρ(k)(1≤j≤3), where e^1=e2, e^2=e3, and e^3=e4, and put σt,ρ(r):=w0t,ρ+∑j=13rj(wjt,ρ−w0t,ρ),Σt:=∑ρ∈S3sgn⁡(ρ) σt,ρ. Each Σt is oriented by dx∧dy∧dz. Define the side chain by B:=∂C−Σt2+Σt1, with the signed simplex-face multiplicities inherited from the boundary of C. The coordinate-order boundary calculation shows that B is supported on the six side faces of the box, each with outward-normal-first orientation from dt∧dx∧dy∧dz; their oriented volume forms are +dt∧dy∧dz at x=0, −dt∧dy∧dz at x=L, −dt∧dx∧dz at y=0, +dt∧dx∧dz at y=1, +dt∧dx∧dy at z=0, and −dt∧dx∧dy at z=1. Then the bulk current is closed on the box, and by definition of B, ∂C=Σt2−Σt1+B, but ΩΣt2−ΩΣt1=−L(t22−t12)≠0. The oriented side flux is L(t22−t12), so the finite-region balance is ΩΣt2−ΩΣt1=−∫Bω. The box is compact; the example uses no asymptotic region or falloff premise.

Diagram conventions

The following is the t–x projection of the four-dimensional box; the y,z directions are suppressed. It shows the two constant-time cuts and the faces x=0 and x=L. Boundary orientations are induced from dt∧dx∧dy∧dz by the outward-normal-first convention.

tx§t1§t2x=0x=LC

Facts & Assumptions

Given: The flat oriented spacetime, the massless scalar Lagrangian, the smooth two-parameter family ψa,b, the box simplex maps σρ, the cut chains Σt, and the oriented side chain B defined in the Example.

[A1]

δ1ψ=t2+x2 and δ2ψ=t each solve −∂t2δψ+∂x2δψ+∂y2δψ+∂z2δψ=0.

[F1]

The current has Iyer–Wald ordering and ΩΣ=∫Σω. Covariant presymplectic current

[F2]

On a solution with linearized variations, dMω=0 and ΩΣ2−ΩΣ1=−∫Bω for a finite chain C with ∂C=Σ2−Σ1+B. On-shell closure and finite-region symplectic flux

[F3]

A change in θ changes the integrated current by its exact corner term on ∂Σ. Potential ambiguity changes the current by a corner term

[F4]

A reduced symplectic space requires a supplied smooth quotient of the null distribution with a descended closed nondegenerate form. Admissible presymplectic reduction and Hamiltonian generators

[F5]

The exterior derivative obeys the degree-one graded product rule. The exterior derivative is a graded derivation

[F6]

In coordinates, d(∑IfI dxI)=∑IdfI∧dxI. The local coordinate formula for the exterior derivative

[F7]

The wedge product of forms is the pointwise wedge of their alternating covariant tensors. The wedge product of differential forms

Verification

Given: As in [A1] and [F1]–[F4], with the box simplex maps, cut chains, and side chain defined in the Example.

1.1A1F1F2F5F6F7algebra

The scalar-current formula from the chosen decomposition is ω=δ2ψ∗dδ1ψ−δ1ψ∗dδ2ψ. Substitution of the displayed variations and Hodge map gives ω=(x2−t2) dx∧dy∧dz−2tx dt∧dy∧dz. By [F6], differentiating the first term gives −2t dt∧dx∧dy∧dz; differentiating the second gives +2t dt∧dx∧dy∧dz. The graded product rule [F5] justifies the coefficient differentiations. Thus dMω=0, agreeing with [F2].

1.2givenconstructalgebra

Set si=(Xi−(a0)i)/ℓi for 1≤i≤4. In these coordinates, the affine simplex σρ has ordered vertices 0,eρ(1),eρ(1)+eρ(2),…,eρ(1)+⋯+eρ(4). Its determinant is sgn⁡(ρ)ℓ1ℓ2ℓ3ℓ4, so the coefficient sgn⁡(ρ) gives the box orientation. Its image is 1≥sρ(1)≥⋯≥sρ(4)≥0; these 24 sectors cover the box with disjoint interiors. Two sectors adjacent by swapping entries ρ(k),ρ(k+1) share a face obtained by deleting their different intermediate vertices; the ordered face maps agree while their permutation coefficients are opposite, so every internal boundary term cancels. On s1=1, time is first in the permutation, and the remaining boundary simplices are exactly Σt2 with positive coefficient. On s1=0, time is last; the permutation sign is reversed relative to the spatial order, so the boundary chain is −Σt1. The other exterior facets are the six side faces and form B. Outward-normal-first contraction of the volume form with their coordinate normals gives the six orientations listed in the Example. Hence ∂C=Σt2−Σt1+B.

2.1A1F1algebrastep 1.1

On a cut with orientation dx∧dy∧dz, ΩΣt=∫0L∫01∫01(x2−t2) dy dz dx=L33−Lt2. Therefore ΩΣt2−ΩΣt1=−L(t22−t12).

3.1A1F1F2step 1.2step 2.1

At x=L, the outward-normal-first boundary orientation is −dt∧dy∧dz, while ω∣x=L=−2tL dt∧dy∧dz; the oriented flux is L(t22−t12). At x=0 the pullback is zero because the coefficient 2tx vanishes. The y and z faces have zero pullback because each term in ω contains respectively dy or dz. Hence the total oriented side flux is ∫Bω=L(t22−t12), verifying [F2].

4.1F3step 3.1

For each cut, [F3] identifies any potential-induced change with an integral over its boundary; the explicit calculation is for the fixed potential in the Statement and makes no claim that a boundary counterterm vanishes on these cuts.

5.1F4step 2.1step 3.1∎

The nonzero difference in step 2.1 shows that this bulk-closed current does not define a cut-independent integrated form without a boundary-flux condition. The example supplies no quotient or descended symplectic form beyond the hypotheses in [F4].

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