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An exact two-level energy readout and its moments

Physical scope

A finite, exact model computation in the two-level state space of the framework: the energy observable E_1 P_1 + E_2 P_2 for two distinct energies in joules, its spectral measure, the outcome probabilities of a pure and of a statistical mixture (mixed for interior weights and pure at the endpoints), and the mean, second moment and variance of the readout. The energies are model parameters; the item asserts no apparatus realization, no measurement statistics from a laboratory and no empirical value.

Example

Let H=C2 carry the standard inner product ⟨z,w⟩=z1w1‾+z2w2‾ (Real and complex inner product spaces, with the inner product linear in the first argument, Hilbert space, The induced length is a norm, Conjugation is an involutive real-field automorphism, zz‾=∣z∣2, and modulus is definite, multiplicative, and subadditive), with orthonormal basis e1=(1,0), e2=(0,1). Fix two distinct energies E1≠E2 in joules (model parameters, not measured values), and consider the assigned sharp observable A:=E1Te1,e1+E2Te2,e2,uA=J, with Tu,vx=⟨x,v⟩u the rank-one calculus of Rank-one operator calculus (Assigned sharp observables and the outcome law of the framework). Then:

(i) A is bounded and self-adjoint with D(A)=H; its spectral projection-valued measure is EA(B)=1E1∈B Te1,e1+1E2∈B Te2,e2(B⊆R Borel), so the spectrum is σ(A)={E1,E2} and the outcome lies in it almost surely: μρA({E1,E2})=1 for every preparation ρ. This probability-one statement does not logically exclude realizations in a null event.

(ii) For the pure preparation of the unit vector ψ=c1e1+c2e2, ∣c1∣2+∣c2∣2=1, the outcome law is μψA({E1})=∣c1∣2,μψA({E2})=∣c2∣2,μψA(B)=∑i:Ei∈B∣ci∣2, and for the statistical mixture ρ=w Te1,e1+(1−w)Te2,e2 with 0≤w≤1 the law is μρA({E1})=w, μρA({E2})=1−w. This preparation is mixed exactly when 0<w<1; at w=0 it is the pure state Te2,e2, and at w=1 it is the pure state Te1,e1.

(iii) With p:=∣c1∣2 and q:=∣c2∣2=1−p, the mean, second moment and variance of the pure preparation are ⟨E⟩ψ=E1p+E2q,⟨E2⟩ψ=E12p+E22q,Var⁡ψ=pq (E1−E2)2, and for the mixture replace p by w and q by 1−w; all three numbers are finite and exact because A is bounded.

The computation is a model-internal readout: the Ei are parameters of the assigned observable, the probabilities are those of the framework's outcome law, and no laboratory measurement, apparatus or empirical value is asserted.

Facts & Assumptions

Given: The Hilbert space H=C2 with the standard inner product and orthonormal basis (e1,e2); distinct real energies E1≠E2 in joules; the assigned observable A=E1Te1,e1+E2Te2,e2 with unit J; a unit vector ψ=c1e1+c2e2; a weight w∈[0,1]; the Axiom of Countable Choice and the Axiom of Choice (The Axiom of Countable Choice (ACω), The Axiom of Choice), the choice hypotheses of the cited spectral suppliers.

[F1]

Rank-one calculus and one-dimensional projections. Tu,vx=⟨x,v⟩u is linear in x, with Tu,v∗=Tv,u and Tu,u self-adjoint and positive; for unit u the operator Tu,u is the orthogonal projection onto Cu with Tu,u2=Tu,u, its trace is 1, and for orthonormal u,v one has Tu,uTv,v=0 (Rank-one operator calculus, Rays, unit vectors and rank-one Hilbert projections,).

[F2]

Finite-dimensional spectral structure. The eigenvectors e1,e2 of the normal operator A form an orthonormal basis of H, so Te1,e1+Te2,e2=I (Complex spectral theorem: a normal endomorphism of a finite-dimensional complex inner product space has an orthonormal eigenbasis, and conversely).

[F3]

Spectral PVM uniqueness. A self-adjoint operator has a unique regular PVM on the Borel sets of R representing it, and the spectral PVM is that measure (Spectral theorem for unbounded self-adjoint operators (PVM form)).

[F4]

Outcome law. For an assigned observable the law is μρA(B)=tr⁡(ρEA(B)), equal to ∥EA(B)ψ∥2 for a pure preparation, and it is affine under mixtures (Assigned sharp observables and the outcome law of the framework clauses (b) and (c), The Born outcome law: probability measure, mixtures, atoms and spectral support clauses (a) and (b)).

[F5]

Moments. For a unit vector in D(A) the mean and second moment are ⟨Aψ,ψ⟩ and ∥Aψ∥2, and the variance is the second moment minus the square of the mean (clauses (a)-(c), Mean, second moment and variance of an assigned observable in a preparation clauses (a) and (b)).

[F6]

States of the model. A state is a self-adjoint positive trace-class operator of trace one. A pure state is Tψ,ψ for a unit vector ψ, equivalently a rank-one orthogonal projection; a state is mixed when it is not pure (The state space: density operators, pure and mixed states, and purity, Density operators and Pure states). The statistical mixture here is a state by positivity and the rank-one trace formulas in [F1].

Verification

technique · direct; compute the spectral measure, the outcome probabilities and the moments on the explicit two-dimensional data
1.1givenF1F2F3F4F6algebra

[The observable and its spectral measure] A=E1Te1,e1+E2Te2,e2 is bounded with ∥A∥≤max⁡{∣E1∣,∣E2∣} and self-adjoint because each Tei,ei is self-adjoint by [F1] and Ei∈R; Ae1=E1e1 and Ae2=E2e2. Define E′(B):=1E1∈BTe1,e1+1E2∈BTe2,e2; [F1] gives that each value is an orthogonal projection and that Te1,e1Te2,e2=Te2,e2Te1,e1=0, while [F2] gives E′(R)=I; multiplicativity and countable additivity hold because the two-point space {E1,E2} is finite, and the integral of the identity against E′ is E1Te1,e1+E2Te2,e2=A. By uniqueness [F3], E′ is the spectral PVM of A, so σ(A)={E1,E2}. Its displayed PVM has EA({E1,E2})=I, so [F4] gives μρA({E1,E2})=tr⁡(ρ)=1 for every preparation, proving the almost-sure support claim of (i).

2.1givenstep 1.1F1F2F4F6algebra

[Outcome probabilities] For the unit vector ψ=c1e1+c2e2, the identity Tei,eiψ=⟨ψ,ei⟩ei=ciei from [F1] gives EA(B)ψ=∑i:Ei∈Bciei, whose norm squared is ∑i:Ei∈B∣ci∣2; by [F4] this is μψA(B), so in particular μψA({Ei})=∣ci∣2 and the total mass is ∣c1∣2+∣c2∣2=1. For the mixture, ρ is self-adjoint, positive and trace class by [F1] and w,1−w≥0, with trace w+(1−w)=1, so it is a state by [F6]. If 0<w<1, then ρe1=we1 and ρe2=(1−w)e2 give range H, of dimension two; hence ρ is not a rank-one projection and is mixed. At w=0 or w=1 it equals the respective rank-one projection Te2,e2 or Te1,e1 and is pure. Now [F4] and linearity of the trace give μρA({E1})=tr⁡(ρTe1,e1)=w because tr⁡(Te1,e12)=1 and tr⁡(Te2,e2Te1,e1)=0 by [F1], and similarly μρA({E2})=1−w; this is clause (ii).

3.1givenstep 2.1F1F5F6algebra∎

[Moments of the readout] With p=∣c1∣2, q=∣c2∣2, the vector ψ lies in D(A)=H, so [F5] applies: the mean is ⟨Aψ,ψ⟩=E1p+E2q, the second moment is ∥Aψ∥2=E12p+E22q, and the variance is their difference, computed as E12p+E22q−(E1p+E2q)2=p(1−p)E12+q(1−q)E22−2pqE1E2=pq(E1−E2)2, using p+q=1 and [F6]. For the mixture ρ=wTe1,e1+(1−w)Te2,e2, which is a state by [F6], the same identities give mean wE1+(1−w)E2 and variance w(1−w)(E1−E2)2, since the law is the two-point law of (ii) and the moments of a finite two-point law are the displayed sums. All quantities are finite because A is bounded. This is clause (iii).

Remarks

  • The two eigenvalues E1≠E2 are distinct, so the eigenspaces are one-dimensional and the spectral projections are exactly the rank-one projections Tei,ei; a degenerate energy would replace them by the projection onto the eigenspace and the exact-value probabilities by its trace weight, in agreement with Atoms of the spectral measure and eigenvalues of a self-adjoint operator.
  • The example is a finite model computation, not a reported experiment: nothing here identifies E1,E2 with the levels of a specific physical system, and no counts, uncertainty or apparatus behaviour is asserted.

Depends on

Dependency tree · 2 levels

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