Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The free translation action of the circle on itself

Example

Assume AC. Let T=M=R/Z, with T acting on M by left translation t⋅[x]=[t+x]. Use the period-one tangent generator e, so the library convention gives Xe=−∂x, and let η be the global one-form on R/Z descended from −dx on R. In the chosen Borel model the map [v,x]↦v⋅x identifies ET×TT with ET, hence HT0(T;R)=R and HTk(T;R)=0 for k>0. The invariant Cartan complex is R[u]⊕R[u]η, with ∣u∣=2, ∣η∣=1, dTP(u)=0, and dT(P(u)η)=−uP(u). Its cohomology is R in degree zero and zero in positive degrees, agreeing with the Borel calculation for this action.

Example references

[Borel and Cartan definitions and the fixed sign convention] Borel and Cartan equivariant cohomology for a compact torus

[Period-one circle exponential] The standard product torus as a compact Lie group

[Fundamental-vector-field sign convention] Fundamental vector fields for a left action

[Contractible free circle model] Milnor's join model is a contractible free G-space

Facts & Assumptions

Given: AC, T=M=R/Z, the left translation action, and the Borel and Cartan conventions in the A-page definition.

[A1]

Assume AC, as carried by the A-page definition and its imported mathematical inputs. The Axiom of Choice

[F1]

The selected Borel quotient is (ET×M)/T under (v,x)⋅h=(v⋅h,h−1⋅x); the Cartan differential uses the negative-exponential fundamental vector field. Borel and Cartan equivariant cohomology for a compact torus

[F2]

The selected Milnor model for the circle is free and contractible. Milnor's join model is a contractible free G-space

[F3]

Homotopy-equivalent spaces have isomorphic real singular cohomology. Singular cohomology is homotopy invariant

[F4]

The real singular cochain complex is dual to the real singular chain complex, and singular cohomology is its cocycle quotient. Singular cochain complex with coefficients Singular cohomology with coefficients

[F5]

The fundamental field for e is the derivative of [x]↦[x−s] at s=0. Fundamental vector fields for a left action

[F6]

Smooth differential forms on the circle are smooth sections of its exterior cotangent powers. A smooth differential k-form

[F7]

The period-one tangent generator exponentiates as s↦[s]. The standard product torus as a compact Lie group

Proof

1.1A1F1F2F3construct

Define Φ([v,x])=v⋅x from ET×TT to ET, where v⋅x is the right Milnor action. It is well-defined because Φ([v⋅h,x−h])=(v⋅h)⋅(x−h)=v⋅x. Its inverse is v↦[v,0]: Φ([v,0])=v, and the quotient relation gives [v,x]=[v⋅x,0]. Both maps are continuous by the quotient topology and continuity of the group action, so this is a homeomorphism. By [F2], ET is contractible; [F3] identifies its real singular cohomology with that of a point.

1.2F1F5F6F7given

Integer translations preserve dx, so −dx descends through the standard quotient charts to a global smooth one-form η on the circle. The circle translations act transitively, so an invariant smooth function is constant. Every smooth one-form is f(x)dx for a smooth periodic function f; invariance under all translations forces f constant. Since higher forms vanish on a one-dimensional manifold, the invariant form algebra is spanned by 1 and η=−dx. By [F7], the negative-exponential flow is [x]↦[x−s], hence Xe=−∂x and ιXeη=1; also dη=0. Substitution in [F1] gives dTP(u)=0 and dT(P(u)η)=−uP(u).

2.1F4step 1.1algebra

A point has one singular simplex in each dimension. If σn is its unique n-simplex, then ∂σ0=0; for n≥1, ∂σn=(∑j=0n(−1)j)σn−1, whose coefficient is 1 for even n and 0 for odd n. Thus Cn({∗};R)=R, and its coboundary δn is identity for odd n and zero for even n. The cohomology quotient in [F4] is therefore R in degree zero and zero in every positive degree. Together with step 1.1 this proves the stated Borel cohomology.

3.1step 2.1step 1.2algebra∎

Multiplication by u is injective on R[u], so the differential from the odd summand R[u]η has zero kernel and image uR[u] in the even summand. Therefore Cartan cohomology is the quotient R[u]/uR[u]≅R in degree zero and is zero in positive degrees, matching step 2.1. The constant polynomial 1 survives, while every positive power uk is the boundary −dT(uk−1η); no odd class survives.

Depends on

Dependency tree · 2 levels

Sources