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The standard two-form of a phase domain is closed and nondegenerate, with contraction ιvω=∑iai dpi−∑ibi dqi

Statement

Let n≥1, let U be a phase domain with canonical one-form λU, standard two-form ωU=∑idqi∧dpi and matrix J=(0nIn−In0n) (A phase domain, its canonical one-form and its standard symplectic two-form). For a point z∈U write ωz:=(ωU)z. Then:

  1. ωU is closed: dωU=0;
  2. for all v,w∈R2n, written in the coordinate frame as v=(a,b) and w=(c,d) with a,b,c,d∈Rn, one has ωz(v,w)=vTJ w=a⋅d−b⋅c;
  3. for every v=(a,b)∈Rn×Rn the contraction is the covector ιvωz=∑i=1nai dpi−∑i=1nbi dqi;
  4. JT=−J, J2=−I2n, and J is invertible with J−1=JT=−J;
  5. consequently v↦ιvωz is a linear isomorphism R2n→(R2n)∗, so ωU is nondegenerate at every point and (U,ωU) is a symplectic manifold.

Facts & Assumptions

Given: The phase domain U⊆R2n, its standard two-form ωU, a point z∈U, and vectors v=(a,b), w=(c,d) in Rn×Rn (A phase domain, its canonical one-form and its standard symplectic two-form).

[F1]

For the coordinate two-form dqi∧dpi the defining multilinear evaluation gives (dqi∧dpi)(v,w)=dqi(v)dpi(w)−dqi(w)dpi(v)=aidi−cibi, where v has q-block a and p-block b and w has q-block c and p-block d (A smooth differential k-form, Ck Euclidean maps and diffeomorphisms).

[F2]

Coordinate formula for the exterior derivative and d2=0 (The local coordinate formula for the exterior derivative, The exterior derivative squares to zero): for smooth coefficients, d(∑jgj dηj)=∑jdgj∧dηj, and the exterior derivative of an exact form vanishes.

[F3]

Block matrix algebra: for the block matrix J one has J=(0nIn−In0n), so JT=(0n−InIn0n)=−J and J2=(−In0n0n−In)=−I2n; hence (−J)J=I2n=J(−J) and J−1=−J=JT (Rectangular matrix multiplication and the identity matrix In, including zero-sized shapes, Invertible Euclidean linear maps).

[F4]

A linear map T:R2n→(R2n)∗ is invertible if and only if its kernel is trivial, by finite dimension and rank-nullity (Linear map between vector spaces over the same field, Invertible Euclidean linear maps). Nondegeneracy of a two-form is the pointwise statement of Symplectic vector space and Symplectic form and symplectic manifold.

Proof

technique · direct; evaluate the constant-coefficient two-form on the coordinate frame, read off the contractions and the block identities, and conclude pointwise nondegeneracy
1.1F2given

Closedness: since dqi∧dpi=d(qi dpi) by [F2], summing gives ωU=dγ with γ=∑iqi dpi, whence dωU=d2γ=0.

1.2F1givenalgebra

Evaluation and contraction: by [F1], ωz(v,w)=∑i(aidi−cibi)=a⋅d−b⋅c; in block form this is vTJw, since Jw=(d,−c) and (a,b)⋅(d,−c)=a⋅d−b⋅c. Reading the same evaluation as a covector in w gives ιvωz=∑iai dpi−∑ibi dqi.

1.3F3

Block identities: [F3] gives JT=−J, J2=−I2n and J−1=JT=−J.

2.1step 1.1step 1.2F4∎

Nondegeneracy: if ιvωz=0, then by step 1.2 the covector has all coefficients zero, so a=0 and b=0, that is v=0; hence the linear map v↦ιvωz has trivial kernel and, by [F4], is an isomorphism R2n→(R2n)∗. Thus ωz is nondegenerate and, with step 1.1, (U,ωU) is a symplectic manifold.

Remarks

  • The point of the block form is that all five clauses are pointwise linear-algebra statements with constant coefficients; no completeness, boundedness or topological hypothesis on U is used.
  • The published The canonical cotangent two-form is symplectic states the same closedness and nondegeneracy for the canonical form on a cotangent bundle (under countable choice); the present lemma is the choice-free local form on a phase domain, stated so that the flow, canonical-map and generating-function items below can compute with it directly.

Depends on

Dependency tree · 2 levels

Sources