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The spherical mean identity behind the wave equation

Statement

Assume the Axiom of Countable Choice (ACω, The Axiom of Countable Choice (ACω)), carried by the cited sphere, parameter, polar and divergence suppliers. Let c>0, let f∈C∞(R3) (unbounded f is allowed), and define the spherical mean

Mrf(x)=14π∫S2f(x+rn) dΩ(n),r≥0,

with the outward sphere measure of total area 4π (Surface integration on compact C1 hypersurfaces, Agreement with the existing polar sphere measure). Then r↦Mrf(x) is smooth for r≥0 and satisfies the Euler-Poisson-Darboux identity

∂r2Mrf(x)+2r∂rMrf(x)=ΔMrf(x)(r>0),

and the function Hf(x,t)=t Mctf(x), t≥0, satisfies

∂t2Hf=c2ΔHf,Hf(x,0)=0,∂tHf(x,0)=f(x).

All identities are local and need no decay of f, since every integration set is compact. This is the pure spherical-mean identity; it makes no claim about finite-domain boundary data or about general rough data.

Facts & Assumptions

Given: The Axiom of Countable Choice ACω; a constant c>0, a function f∈C∞(R3), and the spherical mean Mrf(x) over the unit sphere with chart/polar measure dΩ of total mass 4π.

[F1]

Parameter integrals over the sphere. Differentiating a compact surface integral in a parameter is legitimate when the integrand is smooth and all derivatives are continuous on the compact parameter and surface sets; the parameter-integral lemma supplies the surface-measure form and the interchange of the parameter derivative with the integral (Differentiation under the integral sign over a compact measurable set and over a compact C1 surface, Surface integration on compact C1 hypersurfaces).

[F2]

Divergence theorem and the Laplacian. On a bounded piecewise C1 domain with outward normal, ∫Ωdiv⁡F=∫∂ΩF⋅ν dS for C1 fields (Divergence for finite piecewise C1 presentations); the Laplacian is Δf=∑i∂i∂if (The Laplacian of a C2 function and of a C2 vector field) and ∫Br(x)Δf dy=∫Sr(x)∂νf dS.

[F3]

Radial differentiation and polar coordinates. The ball integral J(r)=∫Br(x)g dy of a continuous g has derivative J′(r)=∫Sr(x)g dS, by polar integration and the one-variable fundamental theorem (The first fundamental theorem: if f is integrable on [a,b] and continuous at c, then F′(c)=f(c); in particular a continuous f has F as a primitive, Polar coordinates decompose Lebesgue measure into r^{n-1} dr d sigma); on Sr(x) the outward normal is ν=(y−x)/r and the substitution y=x+rn gives dS=r2dΩ(n) with the chart/polar measure (Agreement with the existing polar sphere measure).

[F5]

Choice accounting. The Axiom of Countable Choice states that every at most countable family of nonempty sets has a choice function (The Axiom of Countable Choice (ACω)). It is assumed for the sphere/parameter conventions in [F1], the divergence theorem in [F2], and the polar/surface measure suppliers in [F3]. The elementary differentiation in [F4] uses no further choice.

Proof

technique · direct
1.1givenF1F4F5algebra

For fixed x the function r↦f(x+rn) is smooth on the compact sphere and the sphere measure is finite, so [F1] permits differentiation under the integral sign and gives ∂rMrf(x)=14π∫S2n⋅∇f(x+rn) dΩ(n), with all higher r-derivatives obtained by iteration.

2.1step 1.1F2F3F5algebra

For r>0 apply the divergence theorem [F2] on Br(x) to the C1 field ∇f: ∫Br(x)Δf(y)dy=∫Sr(x)∂νf dS; substituting y=x+rn with outward normal n and dS=r2dΩ by [F3] gives ∫Br(x)Δf=4πr2∂rMrf(x).

3.1step 1.1step 2.1F1F2F3F4F5algebra

Differentiate the identity of step 2.1 in r: by [F3] the derivative of the left side is ∫Sr(x)Δf dS=r2∫S2Δf(x+rn)dΩ(n)=4πr2Mr(Δf)(x), while the derivative of the right side is 4π(2r∂rMrf+r2∂r2Mrf); moving the Laplacian through the sphere integral by [F1] gives Mr(Δf)=ΔMrf, so dividing by 4πr2 yields ∂r2Mrf+2r∂rMrf=ΔMrf for r>0.

4.1step 3.1F4algebra

Set Hf(x,t)=tMctf(x) for t>0; differentiating twice with [F4] and the chain rule gives ∂tHf=Mctf+ct ∂rMctf and ∂t2Hf=2c∂rMctf+c2t∂r2Mctf; substituting step 3.1 at r=ct cancels the terms with ∂rMctf and leaves ∂t2Hf=c2tΔMctf=c2ΔHf.

5.1step 4.1F1F3algebra

At t=0 one has M0f(x)=14π∫S2f(x)dΩ=f(x), and ∂rM0f(x)=14π∫S2n⋅∇f(x)dΩ=0 because the chart/polar measure is invariant under n↦−n while n↦n⋅∇f(x) is odd (Agreement with the existing polar sphere measure); hence Hf(x,0)=0 and ∂tHf(x,0)=f(x), while the displayed equation at t=0 reduces to 2c ∂rM0f=0=c2⋅0.

6.1step 4.1step 5.1F1F2F3F5algebra∎

The stated Countable Choice premise is used only through [F1]-[F3] as recorded in [F5]; no choice-free proof is claimed. Every identity was proved on compact parameter and spatial sets with no decay of f used, and the defining integral is smooth in signed r as well, so the equation, the initial value and the initial velocity extend to t=0; this proves the stated spherical-mean identity.

Depends on

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