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A continuous symmetric coefficient orthogonal to every compactly supported variation vanishes

Statement

Let M be a smooth four-manifold, let g be a smooth symmetric nondegenerate covariant 2-tensor field on M (Smooth covariant 2-tensor fields on a smooth manifold), and let (U,x) be any smooth chart, with indices a,b,c,d=0,1,2,3. Write gab=g(∂a,∂b), let (gab) be the inverse matrix of (gab), and define the strictly positive chart weight w:=∣det⁡(gab)∣ on U. These are local matrix constructions; no signature, time orientation or orientation is assumed. A continuous covariant tensor field means a family of bilinear forms whose chart components are continuous; smooth means that they are C∞. For a covector or vector field the same regularity convention applies to its components in the coordinate dual basis or coordinate basis, respectively. Let F be a continuous symmetric covariant 2-tensor field on U. Suppose that for every smooth symmetric covariant 2-tensor field q on M whose support is a compact subset of U,

∫UFab(x) qab(x) w(x) d4x=0,

where qab=gacgbdqcd are the components of q raised with the inverse metric and the integral is the ordinary Riemann integral of the continuous compactly supported function Fabqabw in the chart coordinates (The lower and upper Darboux integrals over a nondegenerate rectangle in Rm). Then F=0 on U. Moreover, if W is a continuous covector field on U with ∫UWa(x) qa(x) w(x) d4x=0 for every smooth vector field q on M whose support is a compact subset of U, then W=0 on U.

Facts & Assumptions

Given: A smooth four-manifold M, a smooth symmetric nondegenerate covariant 2-tensor field g, a chart (U,x) with metric density w>0, and a continuous symmetric field F on U with the stated orthogonality property.

[L1]

In each chart gab is smooth: the adjugate formula writes each entry as a polynomial in the smooth gcd divided by the nowhere-zero determinant (If det⁡(A) is a unit, then A−1=det⁡(A)−1adj⁡(A)). Matrix multiplication gives gacgcb=δab. Thus raising qab=gacgbdqcd and lowering qab=gacgbdqcd are inverse operations preserving symmetry, smoothness and support. Also w is smooth and positive, since the determinant is smooth, nowhere zero and has constant sign near each point.

[L2]

Components prescribed smoothly with compact support inside one chart extend by zero to a smooth field on M. For a covariant 2-tensor this follows from the smooth Jacobian transformation law of Chart independence and the transformation law of a smooth covariant 2-tensor field on overlaps; outside its closed support it is zero on a neighborhood. For vectors and covectors the same assertion follows from the coordinate-basis change ∂/∂ya=(∂xc/∂ya)∂/∂xc and its dual: all transition coefficients are smooth (Smooth manifolds and their smooth charts). Compact support in the chart ensures smoothness at points outside the chart as well.

[L3]

For 0<r<R there is a smooth function ρ:R4→[0,1] with ρ=1 on the closed ball of radius r about 0 and support in the open ball of radius R; after translating and rescaling the chart coordinates this gives, about every point p∈U, nonnegative smooth bumps supported in any prescribed coordinate ball contained in U and equal to 1 near p (A smooth bump between concentric Euclidean balls).

[L4]

A continuous compactly supported function on a chart image is extended by zero to R4 and integrated on a nondegenerate closed rectangle containing its support in its interior. The extension is continuous, hence integrable by Every continuous function on a closed nondegenerate rectangle in Rm is Riemann integrable. The integral does not depend on this rectangle: extending a grid to a larger rectangle adds only zero cells, and a common containing rectangle compares any two choices. If this function is nonnegative and positive at a point, continuity gives a smaller closed rectangle Q0 and m>0 on which it is at least m. A grid containing the endpoints of Q0 has lower sum at least mvol⁡(Q0)>0; the integral is at least this sum by The lower and upper Darboux integrals over a nondegenerate rectangle in Rm, Lower and upper Darboux sums over a grid partition in Rm, and Grid partitions of a rectangle in Rm, their cells, refinements and mesh. A negative value is treated by changing sign.

Proof

technique · direct; suppose the coefficient is nonzero at a point, contract it with a fixed symmetric matrix, multiply by a bump and contradict the hypothesis
1.1L1algebra

(Nonvanishing coefficient at a point.) Suppose for contradiction that Fab(p0)≠0 for some p0∈U. Since the symmetric bilinear form F(p0) is nonzero, there are v,w∈Tp0M with F(p0)(v,w)≠0. Write v=∑ava∂a, w=∑bwb∂b at p0 and put sab:=12(vawb+wavb), a symmetric matrix with Fab(p0)sab=F(p0)(v,w)≠0. Replacing s by −s if necessary, the continuous function f:=Fabsab on U satisfies f(p0)>0; fix such an s.

2.1step 1.1L1L2L3construct

(A bump test field.) By continuity, f>0 on a coordinate ball B(p0,r0)⊆U. Choose 0<r<R<r0 with the closed coordinate ball of radius R about x(p0) contained in the positive region B(p0,r0) and let ρ be the bump of [L3], equal to 1 on the closed ball of radius r and supported in the open ball of radius R. Define the chart components qab:=ρ sab and lower them, qab:=gacgbdqcd; these are smooth, symmetric and supported in the compact coordinate ball of radius R, so by [L2] they define a smooth symmetric tensor field q on M with support compact in U.

3.1step 2.1L4algebra

(Contradiction.) For this q, Fabqabw=ρ f w is continuous and nonnegative with a strictly positive value at p0 (there ρ=1, w>0 and f>0), so its integral over U is strictly positive by [L4], contradicting the hypothesis that the integral vanishes for every such q. Hence no point with F(p0)≠0 exists and F=0 on U, as claimed.

4.1step 1.1step 3.1L2L3L4algebra∎

(Covector version.) Let W be a continuous covector field with the stated property and suppose Wa(p0)≠0. Choose s∈Tp0M with Wa(p0)sa>0 (replacing s by −s if necessary); by continuity f:=Wasa (with s read in the chart components) is strictly positive on a coordinate ball about p0. Taking the bump ρ of [L3] equal to 1 near p0 and supported in a smaller ball, the chart components qa:=ρ sa, extended by zero, define a smooth compactly supported vector field by [L2] applied slotwise, and ∫UWaqaw=∫Uρ f w>0 by [L4], contradicting the hypothesis. Hence W=0 on U; together with step 3.1 this proves both assertions.

Remarks

  • Local form. The lemma is stated in one chart because that is the form in which the compact variation argument is applied; a global version follows by applying it on each chart of a cover, and no choice beyond finitely many charts per point is used.

  • Why compact support is needed. The bump localizes the test variation about the point where the coefficient is nonzero; without compact support inside U the boundary of the chart would contribute and the conclusion could fail.

Depends on

Dependency tree · 2 levels

Sources