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Effective restriction to integral divisors from constructed tilt and duality theory

Statement

Let X be a smooth integral projective complex threefold, H an ample Cartier divisor, v=H3, and μ(F)=H2ch1(F)/(vrk⁡F) for positive-rank sheaves. Assume explicitly ordinary numerical sheaf BG: (H2ch⁡1(F))2−2(vrk⁡F)(Hch⁡2(F))≥0 for every μ-semistable torsion-free F. Let E be μ-stable reflexive of rank R>0. For a stable sheaf A define δL(A)=μ(A)−sup⁡{μ(G)<μ(A):0≠G⊂A is a positive-rank coherent subsheaf}, including full-rank subsheaves. Set δ=min(δL(E),δL(E∗)), which is positive, and D=[(H2ch1(E))2−2(vR)(Hch2(E))]/(vR)2≥0. For any positive integer k and any integral Cartier divisor Y∈∣kH∣, if k≥(R+2)D/R+1 and k/2+k2/4−D≥D/δ, then E|Y is torsion-free and slope-semistable for H|Y, where the slope on possibly singular Y is defined by the first two Hilbert-polynomial coefficients. For R≥2 one has δ≥1/[vR(R−1)], so this explicit lower bound may replace δ. At each rational b<μ(A), any ordinary stable torsion-free A is weak-tilt-stable for sufficiently large α², for the source slope νb,(α2+b2)/2; weak strict stability means ν(F)<ν(A/F). The theorem is conditional on ordinary sheaf BG, not a proof of that numerical hypothesis.

Proof

Given: Exactly the Statement hypotheses and conventions, including the explicit ordinary sheaf BG premise.

1.1givenA1F1algebra

Let E be an ordinary slope-stable torsion-free sheaf of rank R>0, let b<μ(E) be rational, and put d=C1(E)−bC0(E)>0. E belongs to Bb. We prove it is weak-tilt-stable for all sufficiently large a=α2. Here weak stability uses ν(F)<ν(E/F) for nonzero proper subobjects, not the stronger and inappropriate condition ν(F)<ν(E) when the quotient is numerically zero.

2.1givenA1F1step 1.1algebra

There is no null subobject of E in Bb. In fact a Bb subobject A⊂E is a coherent sheaf: taking ordinary cohomology shows H−1(A)=0. If s(A)=0 it is supported in dimension at most one, so cannot inject as a sheaf into the torsion-free E. For any subobject A, write Q=E/A and K=H−1(Q). The ordinary sequence is

3.1givenA1F1step 2.1algebra

0→K→A→E→H⁰(Q)→0.

4.1givenA1F1step 3.1algebra

Thus A is torsion-free, K∈Fb, and its image G⊂E is nonzero (otherwise A=K would lie in both Tb and Fb). Ordinary slope stability gives μ(G)≤μ(E), with equality possible only for a full-rank image whose quotient has codimension at least two. Since μ(K)≤b<μ(E) when K≠0, one obtains μ(A)≤μ(E). If 0<s(A)<d, equality is impossible: it would force K=0, rank G=R and c1(G)=c1(E), hence s(A)=d. Therefore for relevant proper positive-denominator subobjects

5.1givenA1F1step 4.1algebra

C0(A)/s(A)>C0(E)/d=xE>0.

6.1givenA1F1step 5.1algebra

The difference is uniformly separated from zero. Indeed C0(A)d−C0(E)s(A)=C0(A)C1(E)−C0(E)C1(A) is a positive integral multiple of v=H3, while 0<s(A)<d. Hence

7.1givenA1F1step 6.1algebra

xA≥xE+v/d2.

8.1givenA1F1step 7.1algebra

If E is unstable at any sufficiently large a, its first HN factor A is semistable, has 0<s(A)<d, and Δ(A)≥0 by the already constructed tilt discriminant theorem. The same conclusion holds for a proper finite-slope equal-phase factor of a semistable E. From Δ(A)≥0 and C0(A)>0,

9.1givenA1F1step 8.1algebra

λa(A)≤1/(2xA)−axA/2≤1/(2xE)−a(xE+v/d2)/2.

10.1givenA1F1step 9.1algebra

But λa(E)=t(E)/d−axE/2. For large a this makes λa(A)<λa(E), a contradiction. Null quotients have slope infinity and do not violate weak strict stability. Thus E is weak-tilt-stable for all sufficiently large a. This proof uses the tilt discriminant after it was derived by the one-way large-parameter classification, so it is not circular.

11.1givenA1F1step 10.1algebra

For a slope-stable sheaf E define its strict subsheaf gap

12.1givenA1F1step 11.1algebra

δ_L(E)=μ(E)−sup{ μ(G)<μ(E) : 0≠G⊂E is a coherent subsheaf of positive rank }.

13.1givenA1F1step 12.1algebra

The supremum is attained and δ_L(E)>0: ranks are at most R, integral degrees are discrete, and degrees of subsheaves are bounded above. The set is nonempty, for example E(−mH)⊂E for a nonzero section of O(mH). Full-rank subsheaves are INCLUDED; this matters in the dual application.

14.1givenA1F1step 13.1algebra

Let P=(μ(E),C2(E)/C0(E)) and Δ(E)≥0. Let L be a line through P with parabola roots x<y≤μ(E), and suppose

15.1givenA1F1step 14.1algebra

μ(E)−y < δ_L(E), R(μ(E)−y) < y−x.

16.1givenA1F1step 15.1algebra

Then E is tilt-semistable at every point of L∩U. It suffices first to take a rational b∈(x,y). At large a it is stable by the argument beginning at step 1.1. The rational fixed-b local finite-class argument gives a first finite wall if stability is lost before L. To spell out the wall existence being consumed: the tilt-discriminant support bound holds for every semistable class; at any finite positive a the inequalities in the local finite-class proof bound all potential semistable destabilizer classes in a compact parameter neighborhood. This proves local wall finiteness for this fixed object and fixed heart. Starting at a large stable parameter, the first parameter of loss is consequently an equal-phase semistable exact sequence with both denominators strictly between 0 and d. A numerically proportional equality class has a parameter-independent slope equality and cannot be a first loss of stability.

17.1givenA1F1step 16.1algebra

Suppose such a wall lies above L. If Δ(E)>0, its line through P has parabola roots x′<x<y<y′<μ(E). Exact numerical-line transport supplies the same semistable sequence 0→A→E→Q→0 in every heart for b∈(x′,y′). A is a coherent sheaf. Write K=H−1(Q) and T=H0(Q). From the cohomological endpoint bounds in the transport theorem,

18.1givenA1F1step 17.1algebra

μ_min(A)≥y', μ_min(T/tors T)≥y', μ_max(K)≤x'.

19.1givenA1F1step 18.1algebra

If K has positive rank k, then the ordinary cohomology sequence gives

20.1givenA1F1step 19.1algebra

C₁(E)≥v[ y'(R+k)−x'k ],

21.1givenA1F1step 20.1algebra

because rank A+rank T=R+k and torsion contributes nonnegative divisor degree. Consequently R(μ(E)−y′)≥k(y′−x′)≥y′−x′, contradicting R(μ(E)−y)<y−x. Hence K=0 and A is a genuine subsheaf of E. It has μ(A)≥y′>y. Also μ(A)<μ(E): ordinary slope stability proves this for smaller rank, and in equal rank equality would make Q supported in codimension at least two, contrary to its positive denominator. Thus

22.1givenA1F1step 21.1algebra

0<μ(E)−μ(A)<μ(E)−y<δ_L(E),

23.1givenA1F1step 22.1algebra

a contradiction. If Δ(E)=0, any equal-phase semistable factors have Δ≥0 and lie in the same forward Lorentz cone. A sum on its null boundary forces both numerical vectors proportional to E, so they cannot produce a first loss of stability; this covers the y=μ(E) case too. Therefore E stays semistable down to L at this rational b. The numerical-line transport theorem then gives all real b∈(x,y).

24.1givenA1F1step 23.1algebra

The weak inequalities μ(E)−y≤δ_L(E) and R(μ(E)−y)≤y−x also suffice for semistability. At a fixed b on L, raise w slightly while keeping b fixed; the line from this raised point to P has smaller μ(E)−y and larger y−x, so the strict case applies. Semistability is closed in w in the fixed heart, being an intersection of closed subobject inequalities. Let w decrease to its desired value. No two-parameter deformation theorem is used.

25.1givenA1F1step 24.1algebra

Assume E is reflexive. Its dual E* is ordinary slope-stable of slope −μ(E). To verify this, for any positive-rank subsheaf G⊂E* of rank⁡<R, dualization gives a generic quotient E→G∗ whose image I is a genuine lower-rank torsion-free quotient of E. Stability gives μ(I)>μ(E), while the inclusion I⊂G* gives μ(G∗)≥μ(I). Hence μ(G)<−μ(E). After saturation this rules out every destabilizing subsheaf. For a full-rank subsheaf its degree is at most that of E*, so it cannot destabilize either.

26.1givenA1F1step 25.1algebra

For b>μ(E), E[1] lies in the finite part of Bb. There are no maps G[1]→E[1] from a boundary-slope semistable sheaf G because μ(G)=b>μ(E). There are no maps from coherent K supported in codimension at least two: these are Ext1(K,E)=0. The latter follows from the reflexive kernel presentation 0→E→V→W→0 with V locally free and W torsion-free: Hom⁡(K,W)=0 and Ext1(K,V)=0 by depth at least two along the support of K; the regular-sequence/coherent-duality proof of the preceding structural helper supplies exactly this Ext vanishing. A general null object is an extension of these two types.

27.1givenA1F1step 26.1algebra

The constructed truncated derived dual of E[1] is E*: reflexive sheaves on a smooth threefold have only their ordinary dual in cohomological degree zero and a possible zero-dimensional Ext¹ in degree one, which τ≤0 discards. The derived-dual semistability theorem therefore identifies semistability of E[1] at (b,w) with semistability of E* at (−b,w), with opposite source slope. Thus the left safe-region theorem for E* proves the right branch, using the strictly defined dual subsheaf gap δ_L(E*). This handles full-rank modifications as well as lower-rank quotients; no improper use of a proper-quotient gap is made.

28.1givenA1F1step 27.1algebra

Let E be an ordinary μH-stable reflexive sheaf of rank R>0 on the smooth projective threefold X. Put

29.1givenA1F1step 28.1algebra

D=Δ(E)/C₀(E)²≥0, δ=min(δ_L(E),δ_L(E*))>0.

30.1givenA1F1step 29.1algebra

Let k be a positive integer and let Y∈|kH| be any integral Cartier divisor. Suppose

31.1givenA1F1step 30.1algebra

k ≥ (R+2)/sqrt(R+1) · sqrt(D), k/2+sqrt(k²/4−D) ≥ D/δ.

32.1givenA1F1step 31.1algebra

The square root is real under these conditions, and the actual required open intersection is automatic: if D>0, the first coefficient is strictly greater than 2, while if D=0, k>0. Then E|Y is slope-semistable on the integral polarized divisor (Y,H|Y). No smoothness of Y is assumed. Equivalently, with z=k2/4−D and e=k/2−z,

33.1givenA1F1step 32.1algebra

R e≤2z, e≤δ.

34.1givenA1F1step 33.1algebra

The equivalence uses e(k/2+z)=D and the elementary rearrangement R(k/2−z)≤2z iff k²≥(R+2)²D/(R+1).

35.1givenA1F1step 34.1algebra

The line through Π(E) and Π(E(−kH)) has slope ℓ=μ(E)−k/2 and parabola roots

36.1givenA1F1step 35.1algebra

x=μ(E)−k/2−z, y=μ(E)−k/2+z.

37.1givenA1F1step 36.1algebra

Their width is 2z; μ(E)−y=e and x−μ(E(−kH))=e. the argument beginning at step 11.1 makes E semistable everywhere on this line. Applying the reflected left safe region to the ordinary stable dual E*(kH), with its unchanged gap δL(E∗), makes E(−kH)[1] semistable there too, by the argument beginning at step 25.1. Their source slopes both equal ℓ. The non-strict boundary case follows by raising w at a fixed interior b and using the two strict safe regions separately, then letting w decrease; the two slopes need coincide only at the limiting point.

38.1givenA1F1step 37.1algebra

Since E is torsion-free and Y is Cartier, multiplication by its defining section is injective and gives the exact derived triangle E→i∗(E∣Y)→E(−kH)[1]. At an interior point on the line the three objects lie in Bb, so it is a short exact sequence there. The extension of the two equal-slope semistable objects is semistable: otherwise a higher-slope subobject has zero maps to both factors, by the elementary subobject/quotient inequalities. Thus i*(E|Y) is tilt-semistable of slope ℓ.

39.1givenA1F1step 38.1algebra

The restriction E|Y is torsion-free on the integral divisor. Indeed E has depth at least min(2,dim OX,p) at every point because it is reflexive, and the defining nonzerodivisor reduces depth by one. At every nongeneric point of Y this gives depth at least one, so there is no associated point away from the generic point; a torsion submodule would have such an associated point. This also excludes zero-dimensional torsion at the singular points of E or Y.

40.1givenA1F1step 39.1algebra

For a coherent quotient E∣Y→Q, sheaves i*Q and its kernel are torsion in X, so the quotient is an epimorphism in Bb. A positive-rank quotient on Y has C1(i∗Q)=kvrk⁡Y(Q)>0. Tilt semistability yields

41.1givenA1F1step 40.1algebra

C₂(iQ)/C₁(iQ) ≥ C₂(i*(E|Y))/C₁(i*(E|Y)).

42.1givenA1F1step 41.1algebra

This is precisely the Hilbert-polynomial slope inequality on Y, including singular integral Y. Explicitly, ambient GRR gives α2(i∗Q)=C1(i∗Q) and α1(i∗Q)=C2(i∗Q)−KXHch⁡1(i∗Q)/2. Subtract rk⁡Y(Q) times the same coefficient for OY, whose Chern character is 1−e(−kH), to get

43.1givenA1F1step 42.1algebra

deg_{H|Y}(Q)=C₂(iQ)+rk_Y(Q) k²v/2, μ_{H|Y}(Q)=kv [ C₂(iQ)/C₁(i*Q)+k/2 ].

44.1givenA1F1step 43.1algebra

The positive factor and constant are independent of Q. Rank-zero quotients have assigned infinite slope and impose no restriction. Hence E|Y is slope-semistable, proving the full stated effective restriction theorem.

45.1givenA1F1step 44.1algebra∎

For R≥2, both δL(E) and δL(E∗) are at least 1/[v R(R−1)]. For a subsheaf of rank q<R, a strict slope difference has numerator a nonzero integer in denominator vRq≤vR(R−1). For q=R, its degree difference is a positive integer, giving the stronger 1/(vR); rank-one sheaves have only this full-rank case. Thus one may eliminate the unknown gaps by the universal explicit lower bound. This recovers a genuine uniform effective restriction consequence without assuming that the dual subsheaf gap equals a proper-quotient gap.

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