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The one-dimensional free Schr"odinger operator as the weak second-derivative operator

Statement

Assume the Axiom of Countable Choice and the Axiom of Choice (The Axiom of Countable Choice (ACω), The Axiom of Choice). Let m,ℏ>0, put c:=2π2ℏ2/m, and let H0 be the free one-dimensional operator of Real multiplication operators and free plus bounded-potential Schrödinger operators clause (b) with d=1, this c and b=0: H0:=F2∗Mc∣ξ∣2F2,D(H0):={f∈L2(R;C):∣ξ∣2F2f∈L2(R;C)}, where F2 is the unitary Plancherel transform of that theorem and Mc∣ξ∣2 is multiplication by the function ξ↦c∣ξ∣2. Let D2 denote the second weak derivative, defined componentwise on the locally integrable classes of R (Weak derivative of a locally integrable function), and let W2,2(R;C) be the Sobolev space (Integer-order Sobolev spaces and their norms). Then:

(a) D(H0)=W2,2(R;C) as sets and H0f=−ℏ22m D2ffor every f∈D(H0); equivalently, F2(H0f)(ξ)=c∣ξ∣2F2f(ξ) and F2(−ℏ22mD2f)(ξ)=c∣ξ∣2F2f(ξ) for almost every ξ, and the two L2 classes agree.

(b) For every real bounded measurable V:R→R, the operator H0+MV of clause (c) of the cited theorem, with domain D(H0), coincides with the operator f↦−ℏ22mD2f+Vf on the same domain; in particular, for E∈R and ψ∈W2,2(R;C) the eigenvalue equation (H0+MV)ψ=Eψ is equivalent to the weak equation −ℏ22mD2ψ+Vψ=Eψ elementwise in L2(R;C).

The statement identifies operators on the same domain; it asserts neither smoothness of the classes in W2,2 nor any physical interpretation.

Facts & Assumptions

Given: m,ℏ>0; c=2π2ℏ2/m; the operator H0 of the cited theorem with d=1, c and b=0; the weak derivative D and the second weak derivative D2; the Sobolev space W2,2(R;C); a real bounded measurable V.

[F1]

Fourier multipliers of weak derivatives. For every u∈L2(Rn) whose weak derivatives Dαu of all multi-indices ∣α∣≤k again lie in L2 and every such α, the unitary Plancherel transforms satisfy F2(Dαu)(ξ)=(2πiξ)αF2u(ξ) for almost every ξ (Distributional derivatives are polynomial Fourier multipliers). In one dimension with α=(2) this reads F2(D2u)(ξ)=−4π2ξ2F2u(ξ) a.e.; in particular D2u is the L2 class with that Plancherel transform.

[F2]

The free operator. H0 is self-adjoint, D(H0) coincides with W2,2(R;C) as a set with equivalent norms, and for every f∈D(H0), F2(H0f)=c∣ξ∣2F2f; moreover H0≥b=0 in the quadratic-form sense (Real multiplication operators and free plus bounded-potential Schrödinger operators clauses (b), (c)).

[F3]

Plancherel is injective. The Plancherel transform F2 is a surjective linear isometry of L2(R;C); in particular F2g=0 implies g=0 (Plancherel theorem, Integer-order W^{k,2} and H^k agree with equivalent norms).

[F4]

Boundary of the construction. For real bounded measurable V, MV is the bounded multiplication operator of clause (a) of the cited theorem and H0+MV is self-adjoint on D(H0) (Real multiplication operators and free plus bounded-potential Schrödinger operators clauses (a), (c)).

Proof

technique · direct; compare the Plancherel multipliers of $H_0$ and of the weak second derivative, using the Fourier characterization of the Sobolev space and the injectivity of Plancherel

Given: The data of the statement and [F1]-[F4].

1.1givenF1F2

[Domain] By [F2] the sets D(H0) and W2,2(R;C) coincide, and by [F1] a class u∈L2(R;C) has a second weak derivative in L2 exactly when ξ↦(2πξ)2F2u(ξ) is in L2, i.e. exactly when ∣ξ∣2F2u∈L2; this is the defining condition of D(H0) in the statement, so the domain identity of (a) holds with no appeal to any additional regularity.

1.2givenF1F2F3algebra

[Multiplier comparison] Fix f∈D(H0). By [F2], F2(H0f)(ξ)=c∣ξ∣2F2f(ξ) for almost every ξ. Let g:=−ℏ22m D2f; since f∈W2,2, D2f∈L2 and [F1] gives F2g(ξ)=−ℏ22m(−4π2ξ2)F2f(ξ)=2π2ℏ2mξ2F2f(ξ)=c∣ξ∣2F2f(ξ) for almost every ξ. Hence F2(H0f−g)=0 in L2, and [F3] gives H0f=g. This proves (a).

2.1step 1.1step 1.2F1F4algebra∎

[Bounded perturbations] Let V be real, bounded and measurable and let f∈D(H0). By step 1.1 f∈W2,2, so −ℏ22mD2f∈L2 by [F1] and Vf∈L2 because V is bounded; moreover (H0+MV)f=H0f+Vf=−ℏ22mD2f+Vf by step 1.2 and the definition of MV, on the common domain D(H0)=D(MV)∩D(H0) of clause (c) of the cited theorem. Since the two operators have the same domain and the same values, they coincide; the eigenvalue equation and the weak equation are therefore the same elementwise identity in L2. This proves (b).

Remarks

  • Why the factor c. With the Plancherel convention f^(ξ)=∫f(x)e−2πixξdx the weak Laplacian has multiplier −4π2∣ξ∣2, so −ℏ22mD2 has multiplier 2π2ℏ2m∣ξ∣2: the constant c of the cited theorem is fixed by this convention and not a convention-free physical statement.
  • What is not asserted. The lemma compares two mathematical operators. It asserts no smoothness of W2,2 classes, no boundary values, no self-adjointness statement beyond that of the cited theorem, and no identification with any measured Hamiltonian.

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