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Chern character and charge of the normalized twistor monad

Statement

Let S4=HP1 have the unit round metric and the orientation dx0∧dx1∧dx2∧dx3 in the stereographic coordinates z1=x0+ix1, z2=x2+ix3. Write Z=PC(H2)≅CP3, fix the right quaternionic structure j with j2=−1, and define π:Z→S4 by π([v])=span⁡C(v,jv). Its fibers are the real twistor lines. The complex orientation on Z is the one for which vertical complex orientation followed by the displayed base orientation is the complex orientation. Let OZ(1) be the dual of the tautological line bundle and set H=c1(OZ(1))∈H2(Z;Z), viewed in rational cohomology for ch⁡. Let u∈H4(S4;Z) satisfy ⟨u,[S4]⟩=1.

Fix integers k≥0 and N≥2. Let E→S4 be a framed Hermitian rank-N bundle, with a smooth unitary connection A and Ward bundle E whose underlying smooth bundle is π∗E. Write FA for the anti-Hermitian curvature and FA+=(FA+∗gFA)/2, where ∗g is the Hodge star for the stated metric and orientation; assume FA+=0. Define

qN(E,A)=−18π2∫S4tr⁡N(FA∧FA).

Suppose E is the middle cohomology of a holomorphic complex exact at its end terms,

OZ(−1)⊕k⟶OZ⊕(2k+N)⟶OZ(1)⊕k.

Assume this middle cohomology is locally free. Then ch⁡(E)=N−kH2, c1(E)=0, and c2(E)=kH2. For the stated positive twistor orientation,

π∗u=H2.

Consequently k=⟨c2(E),[S4]⟩=−qN(E,A).

Facts & Assumptions

Given: The normalized monad, the smooth Ward pullback identification, the specified orientation, and a framed unitary ASD connection on S4.

[F1]

The total Chern character is additive on exact complexes of vector bundles, ch⁡(O(1))=eH, ch⁡(O(−1))=e−H, and on CP3 all classes of degree greater than six vanish. The Chern character and the Todd class

[F2]

For the oriented submersion π, the pullback of the positive point class is Poincaré dual to the twistor fibre. Each fibre is a complex projective line, and H integrates to 1 on it. Zero-FI regular ADHM and framed twistor data, The normal Thom class realizes the Poincare dual of a closed submanifold, Integral cohomology ring of complex projective space

[F3]

For a framed unitary ASD U(N) bundle on the round S4, the determinant connection is flat and the specified trace normalization gives −qN=⟨c2(E),[S4]⟩≥0. Determinant flatness and charge normalization for framed U(N) ASD data

[F4]

Chern classes are natural under pullback, the second Chern class of a bundle with c1=0 is represented by −ch⁡2, and Chern–Weil forms represent the corresponding real characteristic classes. Characteristic forms represent topological characteristic classes over the reals, The Chern character and the Todd class

Proof

Given: The normalized monad and the Ward pullback identification in the Statement.

1.1F1F4algebra

In the Grothendieck group, exactness of the monad gives [E]=(2k+N)[O]−k[O(−1)]−k[O(1)]. By [F1], its Chern character is (2k+N)−ke−H−keH=N−kH2, because the constant terms cancel to N, the linear terms cancel, the quadratic contribution is −kH2, and terms of degree at least four vanish on Z. Therefore c1(E)=0 and c2(E)=−ch⁡2(E)=kH2.

1.2F2algebra

Let x∈S4. In the explicit incidence chart of the Definition, μ1=z1, μ2=z2 at λ2=0, so the vertical complex orientation followed by the positive stereographic orientation is the complex orientation on Z. The submersion pulls the oriented normal disk at x back to the normal disk of its fibre; fibrewise normalization and uniqueness of the Thom class, followed by its relative-to-absolute map, therefore pull the positive point dual to the positive fibre dual. The class u is Poincaré dual to the positively oriented point x, so π∗u is Poincaré dual to the fibre Lx. By [F2] that fibre has its complex line orientation; as a linear CP1⊂CP3 its Poincaré dual is H2, since ∫LxH=1 and H2 generates degree-four cohomology. The twistor orientation clause in the Definition makes this the positive pullback class, hence π∗u=H2.

2.1F3step 1.1step 1.2algebra∎

Write c2(E)=mu for the integer m=⟨c2(E),[S4]⟩. Naturality and the Ward pullback in the Statement give mH2=π∗c2(E)=c2(E)=kH2 by step 1.1 and step 1.2. Since H2 is nonzero, m=k. Finally [F3] gives −qN=m=k, with the nonnegative sign fixed by the ASD equation.

Depends on

Dependency tree · 2 levels

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