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Determinant flatness and charge normalization for framed U(N) ASD data

Statement

Assume full Axiom of Choice. Let S4=HP1 have the unit round metric and positive stereographic orientation dx0∧dx1∧dx2∧dx3, where z1=x0+ix1, z2=x2+ix3. Let E→S4 be a smooth Hermitian rank-N bundle, N≥2, with a smooth unitary connection A and a unitary framing Φ:E∞→CN. Its curvature FA is an anti-Hermitian endomorphism-valued two-form; set FA+=(FA+∗gFA)/2, where ∗g is the Hodge star for the stated metric and orientation, and assume FA+=0. The determinant-line connection is the connection induced by A on det⁡E=ΛNE. Its framing at ∞ determines a unit vector in (det⁡E)∞. With

qN(E,A)=−18π2∫S4tr⁡N(FA∧FA)

and determinant Chern-form convention c(A)=det⁡(I−FA/(2πi)), one has

qN(E,A)=−⟨c2(E),[S4]⟩∈−Z≥0.

Thus k=−qN=⟨c2(E),[S4]⟩ is a nonnegative integer, with the sign corresponding to the anti-self-dual equation FA+=0.

The induced determinant-line connection is flat. Its framing at ∞ determines a unique global unit parallel section, so the framed unitary bundle reduces to a framed SU(N) bundle.

Facts & Assumptions

Given: Full AC, a smooth framed Hermitian rank-N bundle on the specified compact oriented round S4, a smooth unitary connection, and FA+=0.

[A1]

Full AC is the choice-function principle; restricting its choice function to any countable family gives countable choice. The Axiom of Choice

[F1]

In local unitary frames FA=dA+A∧A is anti-Hermitian, the Hodge star is that of the specified orientation, and qN=−(8π2)−1∫tr⁡N(FA∧FA). Zero-FI regular ADHM and framed twistor data, Trace-normalized instanton number and self-dual sectors

[F2]

The trace curvature obeys DAFA=0, and trace annihilates commutators, so dtr⁡FA=0. Principal curvature, Cartan structure equation, and Bianchi identity

[F3]

HdR2(S4)=0 under countable choice, and S4 is simply connected. De rham cohomology of spheres, Sn is simply connected for every n≥2

[F4]

A flat connection has local parallel frames and path-independent parallel transport on sufficiently small coordinate balls. A flat connection admits local parallel frames, Flat connections have locally path-independent parallel transport on a coordinate ball

[F5]

The total Chern form is det⁡(I−FA/(2πi)), and its real de Rham class is the realification of the topological Chern class. Chern, Pontryagin, and Euler characteristic forms, Chern classes from the projective-bundle relation, Characteristic forms represent topological characteristic classes over the reals, The de Rham theorem

Proof

1.1givenF1F2algebra

In a local unitary frame let Fdet⁡A be the curvature of the induced connection on det⁡E. The induced connection on the top exterior power has local connection matrix tr⁡A, hence Fdet⁡A=tr⁡FA. Put η=−itr⁡FA, a real two-form because FA is anti-Hermitian. By [F2], dη=0, and the linearity of trace in FA+=0 gives ∗gη=−η.

2.1A1F3step 1.1algebra

By [A1] and [F3], η is exact, so choose a smooth real one-form α with η=dα. The ASD equation gives ∫S4η∧∗gη=−∫S4dα∧η=−∫S4d(α∧η)=0, since dη=0 and S4 is compact without boundary. The integrand η∧∗gη is the nonnegative squared norm density of the real form η; zero integral forces η=0 pointwise. Hence Fdet⁡A=0 and the determinant connection is flat.

3.1F3F4step 2.1construct

Choose the unit vector v∞ in (det⁡E)∞ specified by the determinant of the framing. For any x∈S4, parallel transport v∞ along a piecewise smooth path from ∞ to x. If two paths are chosen, their concatenation is a loop. By [F3] the loop is null-homotopic; subdivide a null-homotopy square into finitely many rectangles mapped into coordinate balls, which is possible by compactness and a Lebesgue number for the pulled-back coordinate-ball cover. On each rectangle [F4] makes boundary transport the identity. Multiplying around the subdivision cancels the interior edges, so the two path transports agree. The resulting section is smooth by local parallel frames, is parallel by construction, and agrees with v∞; uniqueness follows from uniqueness of parallel sections along each path. Its unit norm is preserved by unitary parallel transport, so the determinant framing reduces the structure group to SU(N).

4.1F1F5step 2.1algebra∎

Writing C=−FA/(2πi), the degree-four term of det⁡(I+C) is c2(A)=12((tr⁡C)∧(tr⁡C)−tr⁡(C∧C)). Step 2.1 gives tr⁡FA=0, so this reduces to c2(A)=(8π2)−1tr⁡N(FA∧FA). Therefore qN=−∫S4c2(A). By [F5] and the de Rham integration pairing, ∫S4c2(A)=⟨c2(E),[S4]⟩, an integer. Finally qN=(8π2)−1∫B(FA∧FA) for the positive invariant form B(X,Y)=−tr⁡N(XY); since FA=−∗gFA and B is positive definite, qN=−(8π2)−1∫B(FA∧∗gFA)≤0. This proves the stated sign and nonnegativity of k=−qN.

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