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Local spin-connection Clifford compatibility

Statement

Assume ACω. Let (M,g,N) be a smooth time-oriented Lorentzian four-manifold, let U⊆M be a nonempty open set, and let E=(E0,E1,E2,E3) be a smooth future-directed tetrad on U. Let ∇ be a smooth affine Lorentz connection on TM∣U with smooth connection matrix ωIJ in E, meaning ∇XEJ=∑IωIJ(X)EI as in Local Lorentz tetrad and connection. Write ωIJ:=ηIKωKJ=−ωJI for η=diag⁡(−1,1,1,1), so ηIJ denotes the entries of η−1=η. Fix an integer n≥1 and constant matrices γI∈Mn(C) satisfying

γIγJ+γJγI=2ηIJIn.

Let V∈Γ∞(TM∣U) be a smooth vector field and let ψ∈C∞(U,Cn) be smooth. With VI:=ηIJVJ, define c(V):=VIγI and, on Cn-valued fields and forms,

Dψ:=dψ+Γψ,Γ:=14ωIJγIγJ,

where d acts componentwise. Then

D(c(V)ψ)=c(∇V)ψ+c(V)Dψ,

where (∇V)I:=dVI−ωJIVJ are the covector components of the induced Lorentz connection and c(∇V):=(∇V)IγI. This is precisely a local matrix identity under the stated hypotheses; it does not assert that the matrices γI or the operator D are compatible with, or induced by, a separately supplied SL(2,C) representation or principal-connection lift. Such compatibility is an additional condition when this identity is used to describe an associated spinor bundle.

Facts & Assumptions

Given: ACω, the smooth tetrad and Lorentz connection on U, constant matrices of the stated size satisfying the Clifford relation, and the smooth fields V and ψ.

[A1]

Assume ACω and the smooth tangent-bundle convention for the tetrad and fields (The Axiom of Countable Choice (ACω), Local Lorentz tetrad and connection).

[F1]

Local Lorentz tetrad and connection: ωIJ=−ωJI, the local connection acts on frame components by dVI+ωIJVJ, and the local coframe has Minkowski metric η.

Proof

1.1givenA1algebra

From the Clifford relation, γIγJγK=2ηJKγI−2ηIKγJ+γKγIγJ. Subtracting γKγIγJ gives [γIγJ,γK]=2(ηJKγI−ηIKγJ). This is an algebraic identity for every triple of indices, including repeated indices, and uses no group-representation covariance hypothesis.

2.1A1F1step 1.1algebra

Contract step 1.1 with 14ωIJ. Since ωIJηJK=−ωKI by antisymmetry and ωIJηIK=ωKJ, the two terms each contribute −12ωKJγJ after relabeling the summed index. Hence [Γ,γK]=−ωKJγJ. The contraction is valid because each ωIJ is scalar-valued and the gamma matrices are constant in the chosen local frame.

3.1A1F1step 2.1algebra∎

Write c(V)=VKγK. Then step 2.1 gives dc(V)+[Γ,c(V)]=dVKγK−VKωKJγJ=(dVJ−ωKJVK)γJ=c(∇V). For a spinor ψ, expand D(c(V)ψ)=d(c(V)ψ)+Γc(V)ψ and use Γc(V)=c(V)Γ+[Γ,c(V)]. The result is c(∇V)ψ+c(V)(dψ+Γψ)=c(∇V)ψ+c(V)Dψ, as asserted.

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