Alphabeta Math
Physics theoremStatement: AI-adaptedProof: AI-adaptedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Classification of the motions of the damped oscillator by the discriminant, and nonincreasing energy E′=−c x′2

Physical scope

The motion classification of the damped oscillator model with m>0, k>0, c>=0: the three solution families determined by the sign of the discriminant c^2-4mk (distinct real roots, double root, oscillatory roots), uniqueness and global existence for every datum, the identity E'=-c x-dot^2 for the mechanical energy E=m x-dot^2/2+k x^2/2, nonincrease of the energy, strict negativity of its derivative when c>0 and x-dot is nonzero, and the characterisation of the constant-energy motions as the rest motion when c>0. The result is a conditional deduction from the declared model data; it asserts no value of the parameters, no measured decay and no behaviour of any real damper.

Statement

Adopt the damped oscillator model of The damped oscillator model: a harmonic restoring force with a phenomenological linear drag −cx˙, c≥0 with m>0, k>0, c≥0, force law F(x,v)=−kx−cv and mechanical energy E(x,v)=12mv2+12kx2. Write Δ:=c2−4mk,γ:=c2m,λ±:=−c±Δ2m (Δ≥0),ω:=4mk−c22m (Δ<0), and note that Δ=−4mk<0 and ω=k/m when c=0. Then:

  1. Classification and uniqueness. Let J⊆R be an interval with nonempty interior. A curve x:J→R is a motion of the model if and only if it is one of the following:
  2. Energy dissipation. For every motion x:J→R the energy e(t):=E(x(t),x′(t)) is differentiable at every interior point of J with e′(t)=−c x′(t)2≤0, and for t1<t2 in J one has e(t2)−e(t1)=−c∫t1t2x′(s)2 ds≤0: the energy is nonincreasing on J. If c>0, then the following are equivalent: (i) e is constant on J; (ii) x′(t)=0 at every interior point of J; (iii) x is constant on J; (iv) x≡0 on J, the rest motion of the model. Moreover, at every interior point with x′(t)≠0 one has e′(t)<0, so the energy strictly decreases there.
  3. Rest points. The rest points of the model are exactly the pairs (x,0) with kx=0, that is (0,0), and the constant curve x≡0 is its maximal motion with datum (t0,0,0).

The statement is read for the declared data; it asserts no value of m,k,c and no empirical decay law.

Facts & Assumptions

Given: The damped model with data (m,c,k,0), m>0, k>0, c≥0, its motions x:J→R, its energy E, and the constants Δ,γ,λ±,ω.

[L1]

Model vocabulary (The damped oscillator model: a harmonic restoring force with a phenomenological linear drag −cx˙, c≥0, The one-dimensional force models: data, motions, phase system, potential presentation, energy and equilibria clauses (b), (d), (f), The damped driven oscillator model: second-order equation, phase-plane system and characteristic data): the motion equation is m x′′+c x′+k x=0, which is the homogeneous damped oscillator model of The damped driven oscillator model: second-order equation, phase-plane system and characteristic data with the same data; the force law is presented through U(x)=12kx2 with residual force d=−cv; the mechanical energy is E=12mv2+12kx2.

[L2]

The homogeneous damped oscillator: solution classification by the discriminant and uniqueness for initial data with m>0, c≥0, k>0: the model's solutions on an interval with nonempty interior are exactly the three displayed families by the sign of Δ; for every datum at 0 there is exactly one solution R→R, with the displayed coefficients; and every solution extends to R. For c=0 one has Δ=−4mk<0 and ω=4mk/(2m)=k/m because m>0 (Square roots exist: a unique a≥0 with (a)2=a; the positives are {x2:x≠0}).

[L4]

Integration (Newton–Leibniz needs only continuity on [a,b], differentiability on (a,b), and a Riemann-integrable extension of the interior derivative, A continuous function on [a,b] is Riemann integrable, by Heine-Cantor and Riemann's criterion, If f≤g on [a,b] and both are integrable then ∫abf≤∫abg; and m(b−a)≤∫abf≤M(b−a)): if G is continuous on [t1,t2] and differentiable on (t1,t2) with integrable derivative, then ∫t1t2G′=G(t2)−G(t1); a continuous real function on [t1,t2] is Riemann integrable; and if h1≤h2 are integrable on [t1,t2] with h1≤h2 pointwise, then ∫h1≤∫h2. In particular a nonpositive continuous integrand has nonpositive integral.

[L5]

Proof

technique · direct; transport the mathematical classification of the cited supplier (whose case split by the discriminant is performed there) to the model, then differentiate and integrate the energy along a motion
1.1givenL1L2

Clause 1: by [L1] the motions of the damped model are the solutions of the homogeneous damped oscillator equation with data (m,c,k) under the identification clause (f) of The one-dimensional force models: data, motions, phase system, potential presentation, energy and equilibria; [L2] gives the three unshifted families. For a datum at t0, the curve y(s)=x(t0+s) solves the same autonomous equation with y(0)=x0, y′(0)=v0; clause 4 of its supplier fixes the coefficients of y in s. Translating that unique all-real solution back gives existence, uniqueness and the restriction property for the datum at t0, and the special case c=0 with Δ=−4mk<0, γ=0 and ω=k/m. In that case the family of the classification is x(t)=Acos⁡(ωt)+Bsin⁡(ωt), which is exactly the motion family of the harmonic model in clause 1 of The motions of the harmonic model are the sinusoids Acos⁡(ω(t−t0))+Bsin⁡(ω(t−t0)): amplitude and phase, the least period, the conserved energy kR2/2 and the elliptical phase curves; hence the motions of the model with the parameter value c=0 are exactly those of the harmonic model with the same m and k.

1.2givenL1L3algebra

Clause 2: let x:J→R be a motion and e(t):=E(x(t),x′(t)). At every interior point t of J, x is twice differentiable and x′ is differentiable, so by [L3] e′(t)=m x′(t)x′′(t)+k x(t)x′(t)=x′(t)(m x′′(t)+k x(t))=−c x′(t)2, where the equation of motion was used in the last step. This is nonpositive, and it is strictly negative whenever c>0 and x′(t)≠0.

2.1step 1.2L4

For t1<t2 in J the function e is continuous on [t1,t2] and differentiable on (t1,t2) with continuous derivative by step 1.2. The derivative is Riemann integrable on this closed interval by [L4], so Newton–Leibniz gives e(t2)−e(t1)=∫t1t2e′(s) ds=−c∫t1t2x′(s)2 ds≤0, the inequality by the pointwise nonnegativity of the integrand and the monotonicity of the integral in [L4]. Hence e is nonincreasing on J.

2.2step 1.2L1L5algebra

Let c>0. If e is constant on J, then e′(t)=0 at every interior point, so x′(t)2=0 there by step 1.2, giving (ii); if (ii) holds then x is constant on J by [L5], giving (iii); if x is constant on J, then mx′′=0 and the equation reads kx=0 on J, so x≡0 because k>0 and J is nonempty, giving (iv); and (iv) trivially gives (i) because E(0,0)=0. This proves the equivalence of (i)-(iv).

3.1step 1.1L1algebra∎

Clause 3: substituting the constant curve x≡x∗ into the equation gives kx∗=0, that is x∗=0 because k>0; conversely x≡0 solves the equation, so (0,0) is a rest point and, by uniqueness in clause 1, the maximal motion with datum (t0,0,0).

Remarks

  • Two time scales in the heavily damped case. For c>0 the roots λ± are real and negative when Δ>0, with λ−<−c/(2m)<λ+<0; the source reads the reciprocal rates as a short momentum-relaxation time and a long coordinate-relaxation time. Those readings are remarks about the explicit families, not additional claims of this item.

  • Energy is not the only decreasing quantity. Clause 2 identifies the exact rate of energy loss at every instant; the monotone decrease on J follows by integration. Whether the motion tends to rest as t→∞, and how the decay compares with the explicit exponential bounds, is the subject of the following item for c>0.

Depends on

Dependency tree · 2 levels

Sources