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Hydrostatic susceptibility and Tolman variables

Physical scope

Conditional derivative identity and nonnegativity of the model chemical-potential response in the compact smooth static-background functional; no trace, microscopic existence, convergence, or empirical conclusion.

Statement

Fix the background data Σ,h,N,Φ,q,T0,p of the adopted compact hydrostatic functional and vary only its chemical-potential parameter μ0 inside the open interval U specified by that model. The local temperature profile T=T0/N has constant Killing-normalized value NT=T0; this is the model's Tolman profile. Write pμ and pμμ for the first and second derivatives of the pressure function with respect to its chemical-potential argument, evaluated at (T0/N(x),(μ0−qΦ(x))/N(x)). Then

∂μ0Whs=∫Σpμ(T0/N,(μ0−qΦ)/N)kBT0 dVh,∂μ02Whs=∫Σpμμ(T0/N,(μ0−qΦ)/N)NkBT0 dVh.

The model chemical-potential susceptibility χhs:=∂μ02Whs is nonnegative if pμμ(T0/N(x),(μ0−qΦ(x))/N(x))≥0 for every x∈Σ. With the stated SI conventions, Whs is dimensionless and χhs has units J−2. This is a deduction inside the adopted effective model, not an empirical charge-fluctuation claim.

Facts & Assumptions

Given: A compact nonempty smooth spatial manifold Σ without boundary, smooth h,N,Φ, N>0, fixed q∈R and T0>0, p∈C2(D), and an open interval U around μ0 on which all local (T,μ) profiles remain in D; hold these background inputs fixed while varying μ0.

[F1]

Restricted hydrostatic effective functional: Whs=(kBT0)−1∫ΣNp(T0/N,(μ0−qΦ)/N) dVh on the specified parameter interval, with the background held fixed.

[F2]

Static hydrostatic background and equation-of-state data: N is smooth and strictly positive, dVh is the Riemannian volume density on compact Σ with vol⁡h(Σ)<∞, and p is C2 on an open domain containing the local profiles.

[F3]

Riemannian volume density: in local coordinates dVh=det⁡(hij) ∣dx1dx2dx3∣ and its coordinate coefficient is positive.

[F4]

Riemannian volume is the radon measure of the riemannian density associates the Borel measure vol⁡h to dVh. Under ACω [A2], Measurable integration extends smooth density integration defines integration of Borel functions against this measure and gives linearity and order preservation for integrable functions. Since vol⁡h(Σ)<∞, every bounded Borel g:Σ→R is integrable and ∣∫Σg dVh∣≤∥g∥∞vol⁡h(Σ).

[F7]

A continuous function from a compact metric space to a metric space is uniformly continuous (Heine-Cantor: a continuous map from a compact metric space to any metric space is uniformly continuous).

[F8]

For a real function continuous on a closed interval and differentiable in its interior, the mean value theorem gives a point where its derivative equals the interval difference quotient (The mean value theorem, as the case g(x)=x of Cauchy's: for f continuous on [a,b] with a<b and differentiable on (a,b) there is c∈(a,b) with f(b)−f(a)=f′(c)(b−a)).

[F10]

The chain rule for total derivatives applies to the profile map r↦G(r,x) and the C2 pressure function p (The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a)).

[A1]

The pointwise convexity condition pμμ(T0/N(x),(μ0−qΦ(x))/N(x))≥0 holds for every x∈Σ when asserting the nonnegative conclusion.

[A2]

Adopt ACω as defined in The Axiom of Countable Choice (ACω), the explicit assumption of the intrinsic density-integration supplier [F4].

[A3]

The adopted SI Boltzmann constant satisfies kB>0.

Proof

1.1givenF1F2F4F5F6F7F8F10F11A2algebra

Choose a nondegenerate bounded closed interval I0⊂U whose interior contains μ0. It is compact by [F5], so I0×Σ is compact by [F5]. Define G(r,x)=(T0/N(x),(r−qΦ(x))/N(x)). This map is continuous and takes values in D, so its image K⊂D is compact by [F6]. With the Euclidean subspace metric, K is a compact metric space. Since p∈C2(D), pμ and pμμ are continuous and bounded on K by [F11], and uniformly continuous there by [F7]. Also N attains a minimum Nmin⁡>0 on compact Σ by [F11]. For r∈I0 put f(r,x)=N(x)p(G(r,x))/(kBT0). For sufficiently small h with r+h∈I0, the mean value theorem [F8] gives a point rh(x) between r and r+h with (f(r+h,x)−f(r,x))/h=∂rf(rh(x),x). The profiles satisfy ∣G(rh(x),x)−G(r,x)∣≤∣h∣/Nmin⁡ uniformly in x, so uniform continuity of pμ makes these quotients converge uniformly to ∂rf(r,x)=pμ(G(r,x))/(kBT0) by [F10]. By [F4] and finite total volume [F2], the difference between the integrals is bounded by vol⁡h(Σ)sup⁡x∣(f(r+h,x)−f(r,x))/h−∂rf(r,x)∣, which tends to zero. Hence differentiation passes through the finite-volume integral and yields ∂μ0Whs=∫Σpμ/(kBT0) dVh.

2.1step 1.1F1F2F4F7F8F10A2algebra

Differentiating ∂rf=pμ(G)/(kBT0) by [F10] gives ∂r2f=pμμ(G)/(NkBT0). The same mean value argument, now using uniform continuity of pμμ on K and 1/N≤1/Nmin⁡, shows that the difference quotients of ∂rf converge uniformly in x to ∂r2f. Applying the density-integral estimate from [F4] therefore gives ∂μ02Whs=∫Σpμμ/(NkBT0) dVh.

3.1step 2.1F3F4A1A2A3algebra∎

By [A1], each integrand value in the second formula is nonnegative because N(x)>0, kB>0 by [A3], and T0>0. By [F3] the Riemannian density is positive, and [F4] makes its integral nonnegative; hence χhs≥0.

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