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Existence of a smooth future-directed tetrad field near every event

Statement

Let (M,g,N) be a time-oriented smooth Lorentzian four-manifold and let p∈M (Smooth time-oriented Lorentzian four-manifolds: the geometric objects of the model). Then there is an open neighborhood U⊆M of p and a smooth future-directed tetrad field (E0,E1,E2,E3) on U (Local frame fields, coordinate frames and tetrad fields), i.e. gq(EA(q),EB(q))=diag⁡(−1,1,1,1)AB for all q∈U with E0(q) future-directed for every q∈U.

Facts & Assumptions

Given: A time-oriented smooth Lorentzian four-manifold (M,g,N) and a point p∈M.

[L1]

A tetrad field on an open set is a tuple of four smooth vector fields that is pointwise a g-orthonormal ordered basis, and it is future-directed when its first member is future-directed at every point (Local frame fields, coordinate frames and tetrad fields).

[L2]

There is an ordered gp-orthonormal basis of TpM (Every Lorentz form admits an ordered basis with matrix diag(-1,1,1,1)).

[L3]

For a nonzero timelike v∈TpM one has gp(v,Np)≠0, and Cp+={v:gp(v,v)<0, gp(v,Np)<0} is the future timelike component (Classification of future and past causal vectors by a timelike field, Timelike, null, spacelike and causal vectors of a Lorentz vector space).

[L4]

The component functions gab(q)=gq(∂a∣q,∂b∣q) of g in a smooth chart are C∞ (Smooth covariant 2-tensor fields on a smooth manifold).

[L6]

A vector field on a chart domain is smooth exactly when its coordinate component functions are smooth (Smoothness of a vector field is equivalent to smooth coordinate components).

[L7]

A smooth map between smooth manifolds is continuous (Cr and smooth maps between smooth manifolds).

[L8]

If f:X→R is continuous at x and f(x)>0, then there is an open neighborhood W of x with f>0 on W; the same holds with > replaced by <. (Continuity of a map of topological spaces at a point and globally)

[L9]

Finite sums, products and composites of C∞ maps on Euclidean domains are C∞ (Ck Euclidean maps are closed under componentwise algebra and composition).

[L11]

If U⊆Rn is open and f:U→Rn is injective, Ck with k≥1, and Df is invertible everywhere, then f[U] is open and f:U→f[U] is a Ck diffeomorphism (An injective regular Ck map is a Ck diffeomorphism onto its image).

[L12]

The smooth structure of the tangent bundle used for smooth vector fields assumes the axiom ACω (The Axiom of Countable Choice (ACω)).

Proof

technique · direct, by an explicit construction with successive shrinking of neighborhoods
1.1L2L3L5L6L12given

Choose a smooth chart (U0,x) around p. By [L2] there is an ordered gp-orthonormal basis (b0,b1,b2,b3) of TpM; by [L3], gp(b0,Np)≠0, so after replacing b0 by −b0 if necessary we may assume b0 is future-directed, still an orthonormal basis. Expand each bA uniquely in the coordinate basis, bA=∑abAa ∂a∣p [L5], and define BA:=∑abAa ∂a on U0, with the constants bAa as coefficients. Each BA is a smooth vector field by [L6] (so that the tangent-bundle smooth structure of [L12] is in force), and BA(p)=bA.

2.1step 1.1L4L9given

Consider the smooth functions GAB(q):=gq(BA(q),BB(q)) and h(q):=gq(B0(q),Nq) on U0. They are smooth because in the chart x they equal the finite sums GAB=∑a,bbAabBbgab and h=∑a,bb0aNbgab of products of smooth functions, using [L4] and [L9]; and GAB(p)=ηAB, while h(p)<0 by step 1.1 and the definition of future-directedness.

3.1step 2.1L7L8

By [L7] and [L8] applied to the continuous functions −G00 (positive at p) and −h (positive at p), there is an open neighborhood U1⊆U0 of p on which G00<0 and h<0.

4.1step 3.1L1L3L9L10L11

Define F0:=B0/−G00 on U1. The function u↦u−1/2 is C∞ on (0,∞): the map u↦u1/2 is the inverse of the injective C∞ squaring map u↦u2 on (0,∞) whose derivative 2u is invertible everywhere there, so it is C∞ by [L11], and u↦u−1 has derivatives (−1)nn! u−n−1 for every n by iterating the product and quotient rules of [L10]; composites and products of C∞ maps are C∞ by [L9]. Hence F0 is smooth on U1, and gq(F0(q),F0(q))=G00(q)/(−G00(q))=−1; since −G00>0, the field F0 is a positive multiple of B0 at every point, so gq(F0(q),Nq)=h(q)/−G00(q)<0 and F0(q) is future-directed.

5.1step 4.1L4L7L8L9algebra

For i=1,2,3 define Pi:=Bi+gq(Bi,F0)F0 on U1; these are smooth fields by [L9], and gq(Pi,F0)=gq(Bi,F0)+gq(Bi,F0)(−1)=0, so Pi(q) lies in the gq-orthogonal complement of F0(q). The function φ1:=gq(P1,P1) is smooth by [L4] and [L9], and φ1(p)=gp(b1,b1)=1>0 because F0(p)=b0 and gp(b1,b0)=0. By [L7] and [L8] there is an open U2⊆U1 containing p with φ1>0 on U2. Define F1:=P1/φ1 on U2; it is smooth by the argument of step 4.1, g(F1,F1)=1, and g(F1,F0)=0.

6.1step 5.1L4L7L8L9algebra

Define P2′:=P2−g(P2,F1)F1 on U2, a smooth field with g(P2′,F1)=g(P2,F1)−g(P2,F1)=0 and g(P2′,F0)=0, and let φ2:=g(P2′,P2′), smooth with φ2(p)=gp(b2,b2)=1>0 because F1(p)=b1 and gp(b2,b1)=0. Shrink to an open U3⊆U2 containing p with φ2>0 and define F2:=P2′/φ2; then F2 is smooth, g(F2,F2)=1 and g(F2,F0)=g(F2,F1)=0.

7.1step 6.1L4L7L8L9algebra

Define P3′:=P3−g(P3,F1)F1−g(P3,F2)F2 on U3, smooth with g(P3′,F1)=g(P3′,F2)=g(P3′,F0)=0, and let φ3:=g(P3′,P3′), smooth with φ3(p)=gp(b3,b3)=1>0. Shrink to an open U4⊆U3 containing p with φ3>0 and define F3:=P3′/φ3; then F3 is smooth, g(F3,F3)=1 and g(F3,FA)=0 for A=0,1,2.

8.1step 4.1step 5.1step 6.1step 7.1L1algebra

On U4 the four smooth fields F0,F1,F2,F3 satisfy g(FA,FB)=ηAB by steps 4.1-5.1, and F0 is future-directed by step 4.1. The Gram matrix η is invertible, so a linear relation ∑AλAFA(q)=0 implies ∑AλAηAB=0 for all B after pairing with FB(q), hence λ=0; thus the tuple is pointwise an ordered basis, a future-directed tetrad field on U4 by [L1].

9.1step 8.1∎

The open neighborhood U4 of p and the field (F0,F1,F2,F3) have the asserted properties; this proves the theorem.

Remarks

Choice convention. The construction uses smooth vector fields, hence tangent-bundle sections, whose canonical smooth structure assumes the axiom ACω of The Axiom of Countable Choice (ACω) as recorded in [L12]; no further choice principle is used, and the construction selects a definite basis at p by an explicit finite procedure.

Depends on

Dependency tree · 2 levels

Sources