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Radial Carleman estimate

Statement

Assume the Axiom of Countable Choice (The Axiom of Countable Choice (ACω)). Let s≥1 be an integer, τ:=s+1, and let u∈Cc∞(R3∖{0}) (Smooth compactly supported functions of an open set are dense in L2). Write r=∣x∣ and Δ for the Laplacian. Then ∥r−τu∥L2(R3)≤2s∥r−τ+2Δu∥L2(R3). The inequality extends to every compactly supported H2 function that vanishes in a neighborhood of the origin.

Facts & Assumptions

Given: the integer s≥1, τ=s+1, and u∈Cc∞(R3∖{0}).

[F1]

Spherical decomposition: (Ylm) is a complete orthonormal family of L2(S2,σ) and the polar unitary ψ↦(ulm), ulm(r)=r∫S2ψ(rΩ)Ylm(Ω)‾dσ(Ω), identifies L2(R3) with ⨁l,mL2((0,∞),dr); in the (l,m) channel the Laplacian acts as −Δulm=−ulm′′+l(l+1)r−2ulm, and the Laplace-Beltrami operator has eigenvalue −l(l+1) on Ylm (Sphere ONB, Sphere Laplacian diagonal domain, Angular radial unitary reduction clauses (a)-(d)).

[F2]

Write the physical spherical coefficient as ϕlm(r)=ulm(r)/r. Under t=−log⁡r, put vlm(t)=r1/2ϕlm(r)=r−1/2ulm(r) and wlm(t)=estvlm(t). Direct differentiation of the radial expression gives Δϕlm=r−5/2[∂t2−(l+1/2)2]vlm. Since the physical radial measure is r2dr=r3dt after reversing the bounds and τ=s+1, the exact weighted norms are ∥r−τu∥22=∑l,m∥wlm∥L2(dt)2 and ∥r−τ+2Δu∥22=∑l,m∥[(∂t−s)2−(l+1/2)2]wlm∥L2(dt)2. Equivalently the first radial integral in the reduced coefficient is ∫r−2τ∣ulm(r)∣2dr, with no second radial Jacobian. The sums follow from angular Parseval in [F1] and nonnegative integration; they need not be finite (Plancherel theorem, algebra).

[F3]

One-dimensional Fourier calculus: for w∈Cc∞(R) the Fourier transform of (∂t−s)2w is (iξ−s)2w^(ξ), and Plancherel gives ∥(∂t−s)2w∥L2(dt)2=∫R∣iξ−s∣4∣w^(ξ)∣2dξ; the algebraic identity ∣(iξ−s)2−(l+12)2∣2=[ξ2+(s−l−12)2][ξ2+(s+l+12)2] holds for real ξ (Plancherel theorem, algebra).

[F4]

Compactly supported H2(R3;C) classes admit smooth compact-support mollifications converging in H2, with support in K+B‾ε(0) for a mollifier supported in B‾1(0); this is the explicit construction in Compactly supported smooth functions are dense in W^{k,p}(R^n) Proof, fourth and fifth steps, under Countable Choice.

Proof

1.1F3algebra

[Multiplier lower bound] Fix integer l≥0. In the factorization of [F3] the second factor is at least (s+l+12)2≥s2; the first factor is at least ∣s−l−12∣2≥1/4, since an integer s differs from the half-integer l+12 by at least 12. Hence ∣(iξ−s)2−(l+12)2∣2≥s2⋅14, so Plancherel gives ∫∣w∣2dt≤(4/s2)∫∣[(∂t−s)2−(l+12)2]w∣2dt, including w=0 without division.

2.1step 1.1F1F2algebra

[Summing the channels] Each coefficient of a smooth function supported in an annulus is smooth with the same compact radial support, so step 1.1 applies to wlm defined in [F2]. It gives ∥wlm∥22≤(4/s2)∥[(∂t−s)2−(l+1/2)2]wlm∥22. Sum over the countable family of channels using monotone convergence for nonnegative partial sums. The exact norm identities of [F2] identify both sums with the full weighted physical norms, proving ∥r−τu∥22≤(4/s2)∥r−τ+2Δu∥22; taking square roots proves the estimate. Compact radial support does not imply finite angular support, and no such assertion is used.

3.1step 2.1F1F4algebra∎

[Extension] Let u∈H2 have compact support K disjoint from a neighborhood of zero. The zero function satisfies the inequality; otherwise fix d:=dist⁡(K,0)>0. Use the compact-support mollification construction of Compactly supported smooth functions are dense in W^{k,p}(R^n) Proof, fourth and fifth steps at k=p=2, without its preliminary cutoff since u is already compactly supported. It gives uε=ρε∗u→u in H2, with supp⁡uε⊆K+B‾ε(0). For 0<ε<d/2 these supports lie in one fixed compact annulus. Both weights r−τ and r−τ+2 are bounded there, so r−τuε→r−τu and r−τ+2Δuε→r−τ+2Δu in L2. Taking the limit of step 2.1 proves the same bound for u.

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