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Two-band Chern number and degree formula

Statement

Assume Axiom of Choice and Countable Choice. Let a two-orbital finite-range Bloch Hamiltonian on the oriented torus T2π2 have the form

h(k)=d0(k)I+d1(k)σ1+d2(k)σ2+d3(k)σ3,

where d0,d1,d2,d3 are real smooth periodic functions, σ1=(0110), σ2=(0−ii0), σ3=(100−1) are the Pauli matrices, and d=(d1,d2,d3) is nowhere zero. Define n=d/∣d∣. The upper and lower band projectors are P+=(I+n⋅σ)/2 and P−=(I−n⋅σ)/2. With the Chern convention C(P)=(i/2π)∫T2tr⁡(P(dP∧dP)P) and orientation dk1∧dk2,

C(P+)=−deg⁡(n)=−14π∫T2n⋅(∂k1n×∂k2n) dk1 dk2,C(P−)=+deg⁡(n)=+14π∫T2n⋅(∂k1n×∂k2n) dk1 dk2.

Facts & Assumptions

Given: Axiom of Choice, Countable Choice, the stated finite-range Bloch Hamiltonian, and ∣d(k)∣>0 on the torus.

[A1]

Axiom of Choice and Countable Choice are the principles in The Axiom of Choice and The Axiom of Countable Choice (ACω).

[F1]

Lattice Bloch transform and band projectors fixes the finite-range Bloch convention and torus orientation; Exact Bloch transform and regularity of gapped band projectors gives smooth Hermitian fibers and smooth isolated-band projectors.

[F2]

Gapped band curvature and Chern invariance gives the Chern integral convention and identifies it with an integer for a smooth gapped projector.

[F3]

Normalized area integral equals the degree identifies the normalized sphere-area pullback integral with the oriented homological degree.

Proof

Given: [A1], [F1]–[F3]. Write s∈{+1,−1} for the upper or lower band sign.

1.1A1F1givenalgebra

Direct multiplication of the displayed Pauli matrices gives σaσb=δabI+i∑cϵabcσc, tr⁡σa=0, and tr⁡(σaσb)=2δab. Thus (n⋅σ)2=∣n∣2I=I, and h=d0I+∣d∣(n⋅σ) has eigenvalues d0±∣d∣ with the stated orthogonal projectors. Since ∣d∣ is continuous and positive on compact T2, its minimum is positive, so the two bands are uniformly separated; n and Ps are smooth.

2.1F2step 1.1givenalgebra

Differentiating Ps=(I+sn⋅σ)/2 gives ∂jPs=(s/2)(∂jn)⋅σ. The Pauli product identity yields [a⋅σ,b⋅σ]=2i(a×b)⋅σ, hence [∂1Ps,∂2Ps]=i2(∂1n×∂2n)⋅σ. Using tr⁡(Psσa)=sna, which follows from the trace identities in step 1.1, we obtain tr⁡(Ps[∂1Ps,∂2Ps])=is2n⋅(∂1n×∂2n). In dimension two this is the coefficient of tr⁡(Ps(dPs∧dPs)Ps): cyclicity and Ps2=Ps give tr⁡(PsXPs)=tr⁡(PsX). Multiplying by i/(2π) therefore gives C(Ps)=−s(4π)−1∫n⋅(∂1n×∂2n) dk1dk2.

3.1F3step 2.1algebra∎

The normalized area form in [F3] pulls back to (4π)−1n⋅(∂1n×∂2n) dk1∧dk2, by the defining outward area form on the unit sphere. Hence its integral is deg⁡(n) by [F3]. Substitution into step 2.1 gives C(Ps)=−sdeg⁡(n), which is the two displayed upper- and lower-band formulas.

Remarks

The cited Qi–Wu–Zhang treatment of Asbøth, Oroszlány, and Pályi uses the same two-band lattice Hamiltonian and gap-closing values, but defines its band invariant with the opposite sign: its Eqs. (2.40)–(2.41) give Q=−(2π)−1∫(∂kxAy−∂kyAx) for Aj=i⟨u∣∂kju⟩. The C(P) convention here instead gives +(2π)−1∫dA. Accordingly, the signs in this theorem and its examples come from the explicit projector and Pauli calculation above; the cited table is not copied without conversion.

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