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Independent subsystem bulk limit

Statement

Let Ω0 be a nonempty finite set, let E:Ω0→R, and fix β∈R. Define Z1=∑i∈Ω0e−βEi and the canonical law qi=e−βEi/Z1, and define Eˉ:=∑iqiEi. For N≥1, on Ω0N define HN(i1,…,iN)=∑k=1NEik. Give Ω0N the product probability law assigning (i1,…,iN) weight ∏k=1Nqik, and define the N-subsystem partition sum ZN:=∑(i1,…,iN)∈Ω0Ne−βHN(i1,…,iN). Then ZN=Z1N, E[HN/N]=Eˉ, and Var⁡(HN/N)=Var⁡q(E)/N. Consequently, for every ε>0, P(∣HN/N−Eˉ∣≥ε)≤Var⁡q(E)/(Nε2). If β≠0, the mathematical free-energy density −β−1N−1log⁡ZN is exactly −β−1log⁡Z1 for every N.

Facts & Assumptions

Given: The finite one-subsystem state set, energy function, canonical law, and its finite product law.

[A1]

Ω0 is a nonempty finite set, E is real-valued, β is fixed, and the N-subsystem law is the product of the one-subsystem canonical law.

[F4]

The real exponential function and the number e by a power series, The natural logarithm as the inverse of the exponential function, The exponential addition formula exp⁡(x+y)=exp⁡(x)exp⁡(y), and Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm: exp⁡(x+y)=exp⁡(x)exp⁡(y) for real x,y, the exponential has positive values as specified by the logarithm inverse convention, and logarithms convert positive products to sums.

Proof

Given: The finite one-subsystem state set, its energy function, and the product probability model.

1.1A1F1F4F5

By finite Fubini, ZN=∑(i1,…,iN)∏k=1Ne−βEik=∏k=1N∑ik∈Ω0e−βEik=Z1N. This is an exact finite identity.

1.2A1F1F2F3

Under the product law, the coordinate energies E(ik) are mutually independent and each has mean Eˉ and variance v:=Var⁡q(E). Linearity gives EHN=NEˉ; the covariance terms between distinct coordinates vanish by independence, so [F3] gives Var⁡(HN)=Nv. Dividing by N and N2 proves the mean and variance formulas.

2.1F2F3step 1.2

On the event ∣HN/N−Eˉ∣≥ε, the nonnegative random variable (HN/N−Eˉ)2 is at least ε2. Summing over that event gives ε2P(∣HN/N−Eˉ∣≥ε)≤E[(HN/N−Eˉ)2]=v/N, proving the probability bound without any independence assertion beyond the product model.

3.1A1F4F5step 1.1∎

If β≠0, substitute ZN=Z1N and apply the logarithm product law: −β−1N−1log⁡ZN=−β−1N−1Nlog⁡Z1=−β−1log⁡Z1.

Depends on

Dependency tree · 2 levels

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