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Vanishing of an eigenfunction invisible outside a ball

PDF p. 11: Lemma 3.4 proof (iii)

Statement

Assume the Axiom of Choice. Let Ω=Rn∖Θ, n≥2, be the connected smooth exterior of the compact obstacle, and let φ be the real observation cutoff: φ=0 on BR(0) and φ>0 on ω={x∈Ω:∣x∣>R}, where Θ⊂BR(0). Let A=I−ΔD be the positive self-adjoint Dirichlet realization, RA=A−1, and HDs its completed spectral scale.

For any σ∈R and μ∈C, suppose v0∈HDσ satisfies ΔDv0=μv0 in HDσ−2 and is invisible to φ. Then v0=0.

Here the eigenvalue equation uses the consistent map ΔD=I−A:HDσ→HDσ−2, with the right-hand side placed in that space by the canonical embedding. For arbitrary real σ, invisibility means ⟨v0,φη⟩=0 for every η∈Cc∞(Ω;C), using the pivot pairing, linear in its first argument. This is well-defined because φη belongs to the common core D(A∞). For function-valued states it is the usual weak meaning of φv0=0. Thus no cutoff bound outside the already supplied range is assumed.

In fact, unless v0 is already zero, the resolvent identity places it in every higher spectral space, its eigenvalue is real, and it has the analytic representative supplied by Helmholtz continuation. Non-trapping and a boundary multiplier sign are not needed for this eigenfunction implication.

Facts & Assumptions

Given: The geometry, cutoff, spectral scale, σ, μ and v0 in the statement, under the Axiom of Choice.

Goal: Prove that v0=0.

[F1]

The exterior Ω is open and connected. The cutoff φ is real and smooth, and ω={x∈Ω:φ(x)>0}={∣x∣>R} is a nonempty open subset of Ω. Compactness of Θ and Θ⊂BR(0) ensure that this exterior region is present. The geometry and cutoff are fixed by Exterior and truncated obstacle domains and Control region and nested real cutoffs.

[F2]

The Dirichlet realization is self-adjoint and nonpositive on L2(Ω), with domain H2(Ω)∩H01(Ω); on that domain it is the weak Laplacian. Its shift A=I−ΔD is self-adjoint and at least the identity Dirichlet Laplacian and positive shift.

[F3]

The completed scale has the first-slot-linear pivot pairing and identifies HD0=L2, HD1=H01, and HD2=D(A)=H2∩H01. The pivot pairing agrees with the L2 integral when its arguments are functions at nonnegative levels Dirichlet spectral Sobolev scale and duality.

[F4]

For every real a, RA:HDa→HDa+2 is an isometric isomorphism. Powers and embeddings are consistent extensions of their common-core operations; in particular A:HDa+2→HDa is inverse to RA, and ΔD=I−A:HDa→HDa−2 is the consistent scale Laplacian Scale isometries and free Schrödinger evolution, Dirichlet spectral Sobolev scale and duality.

[F5]

If b≥a, the identity on the common core extends to a contractive injective embedding HDb→HDa. A finite set of these spaces has a common Hausdorff realization at its smallest index; identities of scale powers agree under these embeddings Spectral cutoff cores and unitary identifications of completed scales.

[F6]

The complex test functions Cc∞(Ω;C) are smooth actual functions with support compactly contained in Ω; conjugation preserves this test space Test function space d of an open set. The map f↦(η↦∫Ωfη) is injective on Lloc1 classes under Countable Choice Locally integrable functions embed in distributions.

[F7]

Under Choice, an H1 weak solution of Δu=μu on a connected open subset of Rn, n≥2, with real μ, has a real analytic representative; if it vanishes almost everywhere on a nonempty open subset, it vanishes everywhere as a Sobolev class Helmholtz continuation through a harmonic lift.

[F8]

Full Choice is assumed for the exact spectral and realization interfaces, and supplies Countable Choice for the injectivity and continuation inputs. It is the foundational hypothesis used here, not an empirical or physical premise The Axiom of Choice.

Proof

Given: The geometry, cutoff, spectral scale, σ, μ and v0 in the statement, under the Axiom of Choice.

Goal: Prove that v0=0.

[F1] The exterior Ω is open and connected. The cutoff φ is real and smooth, and ω={x∈Ω:φ(x)>0}={∣x∣>R} is a nonempty open subset of Ω. Compactness of Θ and Θ⊂BR(0) ensure that this exterior region is present. The geometry and cutoff are fixed by Exterior and truncated obstacle domains and Control region and nested real cutoffs.

[F2] The Dirichlet realization is self-adjoint and nonpositive on L2(Ω), with domain H2(Ω)∩H01(Ω); on that domain it is the weak Laplacian. Its shift A=I−ΔD is self-adjoint and at least the identity Dirichlet Laplacian and positive shift.

[F3] The completed scale has the first-slot-linear pivot pairing and identifies HD0=L2, HD1=H01, and HD2=D(A)=H2∩H01. The pivot pairing agrees with the L2 integral when its arguments are functions at nonnegative levels Dirichlet spectral Sobolev scale and duality.

[F4] For every real a, RA:HDa→HDa+2 is an isometric isomorphism. Powers and embeddings are consistent extensions of their common-core operations; in particular A:HDa+2→HDa is inverse to RA, and ΔD=I−A:HDa→HDa−2 is the consistent scale Laplacian Scale isometries and free Schrödinger evolution, Dirichlet spectral Sobolev scale and duality.

[F5] If b≥a, the identity on the common core extends to a contractive injective embedding HDb→HDa. A finite set of these spaces has a common Hausdorff realization at its smallest index; identities of scale powers agree under these embeddings Spectral cutoff cores and unitary identifications of completed scales.

[F6] The complex test functions Cc∞(Ω;C) are smooth actual functions with support compactly contained in Ω; conjugation preserves this test space Test function space d of an open set. The map f↦(η↦∫Ωfη) is injective on Lloc1 classes under Countable Choice Locally integrable functions embed in distributions.

[F7] Under Choice, an H1 weak solution of Δu=μu on a connected open subset of Rn, n≥2, with real μ, has a real analytic representative; if it vanishes almost everywhere on a nonempty open subset, it vanishes everywhere as a Sobolev class Helmholtz continuation through a harmonic lift.

[F8] Full Choice is assumed for the exact spectral and realization interfaces, and supplies Countable Choice for the injectivity and continuation inputs. It is the foundational hypothesis used here, not an empirical or physical premise The Axiom of Choice.

Proof technique: resolvent regularization, the self-adjoint L2 pairing, and connected-domain Helmholtz continuation.

1.1givenF4F5

The eigenvalue equation gives Av0=(1−μ)v0 in HDσ−2. Applying RA there gives v0=(1−μ)RAv0 in HDσ, where the right-hand side is the image of an element of HDσ+2. If μ=1, this identity already gives v0=0; henceforth suppose v0≠0, so μ≠1.

2.1step 1.1F3F4F5

Applying powers of RA to the identity in step 1.1 and using their consistency gives v0=(1−μ)kRAkv0 in the common lower scale, for every integer k≥1. Its right-hand side belongs to HDσ+2k. The embeddings are injective, so these are compatible representatives of the same element. Thus v0 belongs to every higher spectral space. In particular choose k with b=σ+2k≥2 and write u for its representative in HD2⊆L2. If u=0 then injectivity would give v0=0, contrary to the present case.

3.1givenstep 2.1F2F3F4F5

The difference ΔDu−μu belongs to HDb−2 and maps to zero in HDσ−2 by the original eigenvalue equation and consistency. Injectivity of the scale embedding implies that the difference is zero already in HDb−2, and therefore in L2 because b−2≥0. Since u∈HD2=D(ΔD), this is the weak equation Δu=μu with u∈H01(Ω).

3.2givenstep 2.1F1F2F3F5F6F8

For each test function η, the product φη is again smooth with compact support in Ω. Every iterate Aj(φη)=(I−Δ)j(φη) is smooth with compact support there, so φη∈D(A∞). Compatibility of the pivot pairing and step 2.1 turn the assumed invisibility into 0=⟨u,φη⟩=∫Ωφuη‾ dx. The product φu is locally integrable, since u∈L2 and φ is smooth and bounded. Conjugation maps the test space onto itself; hence [F6] implies φu=0 almost everywhere.

4.1step 2.1step 3.1F2F3

Self-adjointness and nonpositivity give μ∥u∥22=⟨ΔDu,u⟩2∈(−∞,0]. Because u≠0, ∥u∥22>0, so μ is real and nonpositive. This obtains the real eigenvalue only after regularization has placed the eigenvector in the self-adjoint operator domain.

5.1step 3.1step 4.1step 3.2F1F5F7F8∎

On ω, the multiplier φ is strictly positive. Removing the null set on which φu may fail to vanish therefore gives u=0 almost everywhere on the nonempty open set ω. Steps 3.1 and 4.1 meet exactly the H1, real-eigenvalue and weak-equation hypotheses of [F7], with the connected domain D=Ω. That lemma gives an analytic representative and u=0 in Ω. Injectivity of the scale embeddings then gives v0=0, contradicting the assumed nonzero case and proving the assertion.

Source notes

The original article, Lemma 3.4 proof (iii), PDF page 11, is retained as attribution for the spectral regularization and connected-exterior argument. The proof above is locally authored from the completed exact supplier interfaces; the analytic-continuation input is the completed harmonic-lift lemma. No upstream proof review or new external literature reading is claimed. The published closed-form and flow suppliers stored in the physics namespace both have mathematical domain; that storage namespace introduces no physical premise. This authoring resolution concerns a generated draft and makes no finding about the original article.

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