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Third edge isomorphism
PDF p. 14: Proposition 6.2
Statement
Assume the Axiom of Choice. Let be an algebraically closed field and a normal affine threefold over , where threefold means a finite-type -scheme of Krull dimension three. Then the third edge homomorphism is an isomorphism. Moreover, the actual stage-to- homomorphism is injective.
Here is the nonconnective -theory spectrum of perfect complexes, , and is the third stage of its decreasing motivic filtration. The group is the image of the stage-to- homomorphism. The group is degree-six cohomology of the weight-three motivic complex. The map is the inverse of the actual third-stage-to-graded isomorphism followed by the stage-to- homomorphism with codomain restricted to its image. A group is torsion-free if no nonzero element is killed by a nonzero integer.
Statement references
Facts & Assumptions
Given: The Axiom of Choice, an algebraically closed field , and a normal affine finite-type -scheme of dimension three.
Goal: Prove that the specified third edge map is an isomorphism and that the actual third-stage map to is injective.
A finite-type scheme over a field is Noetherian. Under the Axiom of Choice, Third-stage graded isomorphism supplies the actual isomorphism . By Third edge homomorphism, the stated edge map is followed by the stage map restricted to its image, and is surjective. The choice assumption used by these suppliers is as in The Axiom of Choice.
For an affine finite-type threefold over an algebraically closed field, Torsion freeness of top threefold motivic cohomology states that is torsion-free.
Under the Axiom of Choice, Rational third-edge comparison states that the rationalization of the actual third edge map is an isomorphism for a Noetherian dimension-three scheme over a field.
Detecting injectivity by rationalization states that a homomorphism with torsion-free domain is injective if its rationalization is injective.
Proof
The given finite-type scheme is Noetherian and has dimension three. Thus the hypotheses of [F1], [F2], and [F3] hold. In particular, the domain of is torsion-free, and is an isomorphism, hence injective.
Apply [F4] to . Step 1.1 shows that its domain is torsion-free and its rationalization is injective, so is injective. It is surjective by [F1], and therefore is an isomorphism.
Let be the actual stage-to- homomorphism and let be the same map with codomain restricted to its image. By [F1], . Both factors are isomorphisms by [F1] and step 2.1, so is injective. The inclusion of its image into is injective; consequently is injective. This proves both assertions.
Depends on
- Third edge homomorphism
- Third-stage graded isomorphism
- Torsion freeness of top threefold motivic cohomology
- Rational third-edge comparison
- Detecting injectivity by rationalization
- The Axiom of Choice
- Jean Fasel and Maria Yakerson, Vector bundles on singular surfaces and threefolds · Proposition 6.2 and its proof, PDF p. 14
Dependency tree · 3 levels
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External dependencies
For a normal affine threefold over an algebraically closed field, the third edge map is an isomorphism and the third-stage map into K_0 is injective.
Hypotheses: X is a normal affine threefold over an algebraically closed field, with the article’s motivic filtration and conventions.
Reading limits: The proposition and proof paragraph were read in the supplied article text. The proof below invokes the completed local supplier contracts for their substantive inputs.
Sources
- Jean Fasel and Maria Yakerson, Vector bundles on singular surfaces and threefolds · Proposition 6.2 and its proof, PDF p. 14