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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Final induced-Ramsey separator

PDF p. 4: Section 3, second paragraph

Example

Let k be a natural number with k≥2, and let H1,H2 be non-isomorphic finite connected simple graphs, each with an edge, ordered so that β(H1)≥β(H2) and, if equality holds, ∣V(H1)∣≥∣V(H2)∣. A graph is connected if every two vertices are joined by a path. A block is a maximal 2-connected subgraph or a bridge with its endpoints; 2-connected means connected, having at least three vertices, and remaining connected after deletion of any vertex. A bridge is an edge whose deletion increases the number of connected components. For a graph with an edge, β(H) is the greatest number of vertices in a block of H; for a nonempty edgeless graph, set β(H)=1.

Choose an independent set I of H2 and its nonempty induced remainder F=H2−I with β(F)<β(H2), and choose a finite simple core A containing no induced copy of H1 such that every colouring of its vertices with k available colours has a monochromatic induced copy of F. Independent means that no two vertices of I are adjacent. An induced copy is the image of an injective vertex map preserving adjacency and nonadjacency. Construct A1,…,Ak by the specified recursive induced-separator construction, starting with A1=H2 and attaching copies of Ar−1 to a copy of A at stage r.

Then Ak∈Rindk(H2)∖Rindk(H1). Here Rindk(H) consists of the nonempty finite simple graphs whose every vertex map to {1,…,k} has a monochromatic induced copy of H; colours need not all be used. Consequently the two induced vertex-Ramsey classes are distinct, contradicting any assumption that they are equal.

Facts & Assumptions

[F1]

Under the hypotheses and recursive construction in the example, for every 2≤r≤k the invariant gives Ar∈Rindr(H2) and Ar∉Rindr(H1). Invariant of the recursive induced separator

[F2]

Membership in Rindk(H) means that every vertex colouring with the k available colours has a monochromatic induced copy of H; a colouring need not use every colour. Induced vertex-Ramsey class Unrestricted finite colourings and used palettes

Verification

Given: The ordered graphs, choices of I and A, and recursive graphs in the example.

Goal: Verify the displayed class difference and the resulting inequality of classes.

1.1F1given

Since k is a natural number with k≥2, take r=k in F1. Thus Ak∈Rindk(H2) and Ak∉Rindk(H1).

2.1F2step 1.1∎

By F2 these are membership and nonmembership in the stated classes, so Ak lies in their displayed set difference. A graph belonging to one class and not the other witnesses that the classes are unequal; hence equality would be contradicted.

Depends on

Used by · 1

Dependency tree · 2 levels

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Sources