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Existence of the base graph A
PDF p. 3: Section 3, paragraph beginning First
Statement
Let be non-isomorphic finite connected simple graphs, each with an edge, ordered so that and, when equality holds, . Let be an independent set of such that satisfies , and let be an integer. Then there is a graph .
Here is the induced graph on the vertices outside , and independent means that no edge has both endpoints in . A block is a maximal 2-connected subgraph or a bridge with its endpoints; a 2-connected graph has at least three vertices, is connected, and remains connected after deletion of any one vertex. A bridge is an edge whose deletion increases the number of connected components. For a graph with an edge, is the largest block order; for an edgeless nonempty graph it is . Graph order is the number of vertices, and denotes the number of edges of .
The class consists of nonempty finite simple graphs containing no induced copy of . The class consists of such graphs in which every assignment of available colours to the vertices has a monochromatic induced copy of . An induced copy preserves both adjacency and nonadjacency.
If is edgeless, one may take edgeless on vertices. Otherwise, choose a block of of order and take any graph supplied by Construction 1. This construction places copies of on the hyperedges of a suitable finite uniform hypergraph of the specified girth and chromatic property; its choices are as in Construction 1: graph G(H,q,k).
Facts & Assumptions
Deleting an independent set from a finite simple graph with an edge leaves a nonempty finite induced graph. Thus is nonempty. Nonempty remainder after deleting an independent set The independent set I and remainder F
Under the stated induction hypotheses, if is edgeless, the edgeless graph on vertices belongs to both required classes. Edgeless choice of A
If has an edge, a largest block of has vertices. For every graph obtained by Construction 1, the block-exclusion result gives membership in . Blocks and the parameter beta Block exclusion in the high-girth base graph
For nonempty finite simple , integers and , construction choices exist, and every graph obtained from them belongs to . Construction 1: graph G(H,q,k) Construction 1 gives an induced vertex-Ramsey graph Induced vertex-Ramsey class
Proof
Given: Graphs , an independent set , its remainder , and an integer satisfying the statement.
Goal: Construct a graph in both stated classes, with the stated choice in each case.
By F1, is nonempty. If is edgeless, take the edgeless graph on vertices. The hypotheses of F2 hold, so this graph belongs to .
Suppose instead that has an edge. Choose a largest block of and put . By F3, has at least three vertices and is a block with an edge, so . By F4, the required construction choices exist; choose any resulting graph . F3 gives , while F4 gives .
The two cases exhaust the possibilities for . In each case the displayed choice of lies in the required intersection.
Depends on
- Graph and colouring conventions
- The independent set I and remainder F
- Blocks and the parameter beta
- Construction 1: graph G(H,q,k)
- Induced forbidden-subgraph class
- Induced vertex-Ramsey class
- Edgeless choice of A
- Block exclusion in the high-girth base graph
- Construction 1 gives an induced vertex-Ramsey graph
- Nonempty remainder after deleting an independent set
Dependency tree · 2 levels
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Sources
- Maria Axenovich and Patrick Schmitteckert, Non-isomorphic graphs have distinct vertex-Ramsey classes, arXiv:2610.03704v1 · PDF p. 3, Section 3, paragraph beginning First