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✓ 3 results · all verified · 0 also independently AI-judged
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Resampling schemes and the sampling-unit contract

1 · Prerequisites

2 · Summary

Objective

This page defines the empirical law, size-n bootstrap, delete-d replicates, subsampling without replacement, and the sampling-unit contract. It proves only the finite probability facts that make these procedures well-defined, including that the empirical law is a probability measure and the bootstrap draws are conditionally IID from it. No procedure here is asserted valid for a particular estimand or sampling design. Variance scaling for jackknife replicates is a separate statistic with an explicit target.

Development

Start with the resampling unit, which is the indivisible random or design unit selected together. The empirical measure Empirical measure of observed units assigns mass 1/n to each observed index; The empirical measure is a probability measure proves it is a probability measure, including when observed values repeat. Size-n bootstrap from the empirical law then samples indices independently with replacement, and Empirical-law bootstrap draws are conditionally IID proves the exact conditional law.

For any finite index set, Uniform laws on finite subset families proves the equal-weight subset law, including the endpoints. The delete-d algorithm Delete-d jackknife replicates and their uniform average returns all complement-statistic replicates and their uniform average without a variance multiplier. Uniform subsampling without replacement selects a uniformly chosen b-subset and applies the declared statistic at that subsample size.

The conditional bootstrap law is not a Bayesian posterior. A design-randomization law is the actual law over assignments declared by the experiment; its relationship to the bootstrap law is illustrated on the examples page. Any exact or asymptotic validity claim needs a separate result matched to the data-generating or assignment design.

3 · Logical flowchart

4 · Definitions, theorems and proofs

DefinitionDefinition: AI-adaptedProof: Not applicableOpen item page →

Sampling units and the resampling-unit contract

Definition

Let E=((X,A),Θ,(Pθ)θ∈Θ) be a statistical experiment (Statistical experiments) with a declared sampling or assignment mechanism. A sampling unit is one indexed unit that the declared mechanism treats as an indivisible draw or assignment object. Its unit record contains the complete observed data attached to that unit, including repeated measurements or labels that the analysis keeps together. Examples of sampling units are individuals, matched pairs, clusters, time blocks, and treatment-assignment units.

The declared mechanism also specifies a measurable unit-record space (Z,F) and represents each unit record as an element of Z. The record space may be the whole data space or one record-valued component of it; the convention is part of the experiment's sampling or assignment contract.

A resampling unit is the complete unit record or predeclared group of records that one draw of a resampling procedure selects. A procedure is unit-compatible for a stated target when it declares which records are sampled together and does not split a bundle whose joint sampling or assignment dependence is part of that target's data-generating design. Unit compatibility describes the procedure's input and dependence contract; it does not itself establish exact or asymptotic validity. A validity claim requires a separate theorem with hypotheses matched to the sampling or assignment law, target, and resample-size regime.

The conditional bootstrap law of observed units is a law on resampled data records given the fixed observations. When defined, a Bayesian posterior is instead a conditional law on parameter values under a specified prior and joint parameter-data model. They have different state spaces and are not identified by this definition. In particular, neither law determines the other.

DefinitionDefinition: AI-adaptedProof: Not applicableOpen item page →

Empirical measure of observed units

Definition

Let (Z,F) be a measurable unit space (Measurable spaces and measurable sets), let n≥1, and fix an observed ordered tuple z1,…,zn∈Z. Its empirical measure is the set function Pn:=1n∑i=1nδzi,Pn(A)=1n∑i=1n1{zi∈A}(A∈F), where δzi is the Dirac set function from The Dirac set function at a point. Repeated observations contribute once for each index at which they occur. The statement that Pn is a probability measure is established in The empirical measure is a probability measure ↗.

LemmaStatement: AI-adaptedProof: AI-generatedprecheck passOpen item page →

Uniform laws on finite subset families

Statement

For n≥0, let [n]:={1,…,n}, with [0]=∅. For an integer r with 0≤r≤n, let Sn,r:={I⊆[n]:∣I∣=r}. Then Sn,r is finite and nonempty, and assigning weight 1/∣Sn,r∣ to each member defines a finite probability space on Sn,r.

Facts & Assumptions

Given: Integers n≥0 and 0≤r≤n, the index set [n], and the subset family Sn,r in the statement.

[F1]

The cardinality ∣A∣ of a finite set: finiteness means being bijective with a von Neumann natural.

[F2]

The set AB of functions B→A between finite sets is finite, with ∣AB∣=∣A∣∣B∣: for finite sets A,B, the function set AB is finite with cardinality ∣A∣∣B∣. In particular, the set of maps [n]→{0,1} is finite.

[F4]

Finite probability spaces, outcome weights, events, and event probabilities: a finite outcome set with nonnegative weights summing to 1 is a finite probability space, with every subset an event.

[F5]

The cardinality ∣A∣ of a finite set: the cardinality of a finite set is the unique von Neumann natural bijective with it.

[F6]

The cardinality ∣A∣ of a finite set: a finite set has cardinality 0 exactly when it is empty.

Proof

1.1F1F2F3construct

Let B={0,1}. The shift j↦j−1 is a bijection from the conventional index set [n]={1,…,n} to the von Neumann natural n={0,…,n−1}; for n=0 both sets are empty. Thus [n] is finite by [F1]. The set B is bijective with 2, so it is finite as well. For each I∈Sn,r define its indicator function χI:[n]→B by χI(j)=1 if j∈I and 0 otherwise. The map I↦χI is injective because equal indicator functions have equal inverse images of {1}. Its image is a subset of the finite set B[n], which is finite by [F2] and [F3]. Therefore some natural k is bijective with this image; composing that bijection with I↦χI makes Sn,r bijective with k, so [F1] makes it finite.

1.2givenF1F5F6constructalgebra

If r=0, then ∅∈Sn,r. If r>0, then {1,…,r}⊆[n] because r≤n, and the shift j↦j−1 is a bijection from {1,…,r} to the von Neumann natural r; hence this subset has cardinality r by [F1, F5], so {1,…,r}∈Sn,r. Thus Sn,r is nonempty. By [F5], its cardinality M:=∣Sn,r∣ is defined; by [F6] and nonemptiness, M≥1. Give each I∈Sn,r weight q(I)=1/M. These weights are nonnegative and their finite sum is M(1/M)=1.

2.1F4step 1.1step 1.2∎

The outcome set is finite by step 1.1 and its weights satisfy the conditions in step 1.2, so [F4] makes (Sn,r,q) a finite probability space. The argument includes n=0, r=0, and r=n.

LemmaStatement: AI-adaptedProof: AI-generatedprecheck passOpen item page →

The empirical measure is a probability measure

Statement

For every n≥1, every measurable space (Z,F), and every observed tuple z1,…,zn∈Z, the empirical measure Pn=1n∑i=1nδzi from Empirical measure of observed units is a probability measure on (Z,F).

Facts & Assumptions

Given: A measurable space (Z,F), an integer n≥1, and fixed observations z1,…,zn.

[F1]

Empirical measure of observed units: Pn(A)=1n∑i=1nδzi(A) for every A∈F.

[F2]

A Dirac set function is a probability measure: each Dirac set function δzi is a probability measure on (Z,F); in particular it is countably additive, is 0 on ∅, and assigns mass 1 to Z.

[F3]

Probability measures and probability spaces: a probability measure is a measure with total mass 1.

Proof

1.1F1F2algebra

For any A∈F, the finite sum in [F1] is nonnegative by [F2]. Also Pn(∅)=0 and Pn(Z)=1n∑i=1n1=1.

1.2F1F2algebra

Let (Ak)k≥1 be pairwise disjoint members of F. For each fixed i, at most one term δzi(Ak) is nonzero, and countable additivity in [F2] gives δzi(⋃kAk)=∑kδzi(Ak). Because the sum over i is finite and there are at most n nonzero terms in the resulting double sum, we may regroup to obtain Pn(⋃kAk)=1n∑i=1n∑kδzi(Ak)=∑k1n∑i=1nδzi(Ak)=∑kPn(Ak). Thus Pn is countably additive.

2.1F3step 1.1step 1.2∎

By step 1.1, Pn has total mass 1, and by step 1.2 it is countably additive and vanishes on the empty set. Therefore it is a measure of total mass 1, hence a probability measure by [F3].

AlgorithmAlgorithm: AI-adaptedProof: Not applicableOpen item page →

Delete-d jackknife replicates and their uniform average

Definition

Input. Let n≥2, let (Z,F) be the declared measurable space of unit records, and fix observed records z1,…,zn∈Z whose resampling unit satisfies Sampling units and the resampling-unit contract. For each tuple length m, declare a sample sigma-algebra Fm on the ordered tuple space Zm. Choose 1≤d<n and provide a statistic Tn−d:(Zn−d,Fn−d)→(Rq,Bq), where q≥1 is finite and Bq is the declared target sigma-algebra; "statistic" has the measurable-map meaning in Statistics and estimators.

Write [n]:={1,…,n} for the indexing set; the finite subset law on these indices is established in Uniform laws on finite subset families.

Procedure. Form In,d:={I⊆[n]:∣I∣=d}. For every I∈In,d, list the indices in [n]∖I in increasing order and compute θ^(−I):=Tn−d((zi)i∈[n]∖I). Let Mn,d:=∣In,d∣ and return the full collection of replicates together with the uniform average θ‾(−d):=1Mn,d∑I∈In,dθ^(−I). The finite, nonempty subset family and its uniform law are justified by Uniform laws on finite subset families.

This algorithm defines the replicates and their average only. Any variance or bias scaling is a separate statistic with an explicitly stated target; no scaling is implicit in the term delete-d jackknife, and the algorithm asserts no validity theorem.

AlgorithmAlgorithm: AI-adaptedProof: Not applicableOpen item page →

Uniform subsampling without replacement

Definition

Input. Let n≥2, let (Z,F) be the declared measurable space of unit records, and fix observed records z1,…,zn∈Z whose resampling unit satisfies Sampling units and the resampling-unit contract. Declare a sample sigma-algebra Fb on the ordered tuple space Zb, choose 1≤b<n, and provide a statistic Tb:(Zb,Fb)→(Rq,Bq), where q≥1 is finite and Bq is the declared target sigma-algebra; "statistic" has the measurable-map meaning in Statistics and estimators.

Write [n]:={1,…,n} for the indexing set; the finite subset law on these indices is established in Uniform laws on finite subset families.

Procedure. Draw I uniformly from the finite family In,b:={J⊆[n]:∣J∣=b}, without replacement; list its indices in increasing order; and return the subsample (zi)i∈I and statistic value Tb((zi)i∈I). The uniform law is well-defined by Uniform laws on finite subset families.

This is subsampling without replacement. It is different from drawing b indices independently with replacement. The procedure defines a finite law only; validity requires a separate theorem for the data-generating design and asymptotic regime.

AlgorithmAlgorithm: AI-adaptedProof: Not applicableOpen item page →

Size-n bootstrap from the empirical law

Definition

Input. Let n≥1, let (Z,F) be the declared measurable space of sampling units, and fix the observed ordered tuple z=(z1,…,zn). Let Pn be its empirical probability measure from Empirical measure of observed units and The empirical measure is a probability measure. Declare a sample sigma-algebra Fn on the ordered tuple space Zn and provide a statistic Tn:(Zn,Fn)→(Rq,Bq), where q≥1 is finite and Bq is the declared target sigma-algebra; "statistic" has the measurable-map meaning in Statistics and estimators.

Write [n]:={1,…,n} for the indexing set.

Procedure. Draw indices I1,…,In independently and uniformly from [n], so repeated indices are allowed. Set Zj∗:=zIj for j=1,…,n. Return the bootstrap tuple (Z1∗,…,Zn∗) and the replicate Tn(Z1∗,…,Zn∗). Generate further replicates by repeating the index draws with fresh randomness. These are resampling units only when the tuple entries satisfy the unit contract in Sampling units and the resampling-unit contract.

The conditional IID law of the draws is proved in Empirical-law bootstrap draws are conditionally IID ↗. This algorithm does not claim that its conditional law consistently approximates any sampling law; such validity requires separate hypotheses and a separate theorem.

TheoremStatement: AI-adaptedProof: AI-generatedprecheck passOpen item page →

Empirical-law bootstrap draws are conditionally IID

Statement

Fix n≥1, write [n]:={1,…,n}, let (Z,F) be a measurable unit space, and fix an observed tuple z=(z1,…,zn). Let Pn=1n∑i=1nδzi be its empirical probability measure. For the bootstrap algorithm Size-n bootstrap from the empirical law, equip the conditional index vector (I1,…,In) with the finite uniform law on Ωn:={f:[n]→[n]} and set Zj∗=zIj. For every A1,…,An∈F, P∗(Z1∗∈A1,…,Zn∗∈An)=∏j=1nPn(Aj). Thus, conditional on the fixed observed tuple, Z1∗,…,Zn∗ are independent random elements with common law Pn (Identical distribution and IID families).

Facts & Assumptions

Given: n≥1, a measurable space (Z,F), a fixed tuple z1,…,zn, and the size-n bootstrap procedure.

[F1]

Size-n bootstrap from the empirical law: each replicate selects I1,…,In independently and uniformly from [n] and sets Zj∗=zIj.

[F2]

Finite probability spaces, outcome weights, events, and event probabilities: a finite outcome set with nonnegative weights summing to 1 defines a probability on every subset of outcomes.

[F3]

Empirical measure of observed units: Pn(A)=1n∑i=1n1{zi∈A}.

[F4]

The set AB of functions B→A between finite sets is finite, with ∣AB∣=∣A∣∣B∣: for finite sets A,B, there are ∣A∣∣B∣ functions B→A.

[F6]

Random elements and real random variables: a random element is a measurable map from a probability space to a measurable space.

[F7]

Law or distribution of a random element: the law of a random element assigns to each target event the probability of its preimage.

[F8]

Independent random elements and Independent sigma-algebras and independent events: a family of random elements is independent when their generated sigma-algebras are independent; event independence is characterized by factorization of probabilities of all finite intersections.

[F9]

Identical distribution and IID families: random elements with the same target are IID when their laws agree and the family is mutually independent.

[F10]

The cardinality ∣A∣ of a finite set: a set is finite when it is bijective with a von Neumann natural.

[F11]

The cardinality ∣A∣ of a finite set: every von Neumann natural n has cardinality n.

[F12]

The cardinality ∣A∣ of a finite set: a bijection transports finiteness and cardinality.

Proof

1.1F1F2F4F6F10F11F12algebra

The shift j↦j−1 is a bijection from [n] to the von Neumann natural n. By [F10]–[F12], [n] is finite with cardinality n. Let Ωn={f:[n]→[n]}, the set of index vectors. By [F4], ∣Ωn∣=nn. Assign weight n−n to each ω∈Ωn. The weights are nonnegative and sum to nnn−n=1, so [F2] gives a finite probability space (Ωn,w) whose event sigma-algebra contains every subset. Each coordinate map Ij(ω)=ω(j) and record map Zj∗(ω)=zω(j) is measurable, because every preimage is a subset of Ωn; hence each Zj∗ is a random element of (Z,F) by [F6].

2.1F3F5F7F13step 1.1algebra

For Aj∈F, put Bj:={i∈[n]:zi∈Aj}. Each Bj is a subset of the finite set [n], so [F13] makes it finite. The event {Zj∗∈Aj for every j} consists of the functions g:[n]→[n] with g(j)∈Bj for every j. The shift τ:[n]→n, τ(j)=j−1, from step 1.1 has inverse ρ:n→[n], ρ(k)=k+1; thus g↦g∘ρ is a bijection from this event's index functions onto ∏k<nBk+1. By [F5] this set has cardinality ∏k<n∣Bk+1∣, which is the same product as ∏j=1n∣Bj∣ under that reindexing. Its probability under the uniform weights is therefore ∏k<n(∣Bk+1∣/n)=∏j=1n(∣Bj∣/n). Taking all events except the jth to be Z gives P∗(Zj∗∈Aj)=∣Bj∣/n=Pn(Aj) by [F3] and [F7]. Hence the joint event probability is the product of its marginal probabilities.

3.1F8F9step 2.1∎

The one-coordinate case of step 2.1 gives each Zj∗ law Pn. To check independence for any finite subfamily indexed by J⊆[n], take arbitrary Aj∈F for j∈J and set Aj=Z for every omitted coordinate. Since Pn(Z)=1 and P∗(Zj∗∈Z)=1, step 2.1 then gives P∗(⋂j∈J{Zj∗∈Aj})=∏j∈JPn(Aj). This is the finite-intersection factorization in [F8], so the coordinate random elements are independent. They have a common measurable target and the same law, hence they are IID by [F9].

5 · Examples, counterexamples and false statements

None yet.

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