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Rational Cherednik Algebras and Their Category O: Examples and Counterexamples
1 · Prerequisites
2 · Summary
This companion checks the A-page conventions in two small cases. The trivial group gives the first Weyl algebra. In rank one at , the polynomial standard module contains and the resulting short exact sequence is nonsplit, so category is not semisimple at that parameter.
Companion to rational-cherednik-algebras-and-category-o.
Examples
For and , the reflection sum vanishes and ; the polynomial standard module is with . The full presentation and verification are in The trivial reflection group gives the first Weyl algebra.
For acting on by , the fixed normalization is . At , the explicit formula shows that is a submodule. The quotient is the trivial one-dimensional module, and no invariant complement exists because multiplication by has no nonzero polynomial eigenvector. See Category O is not semisimple at the rank-one parameter c=1/2.
Scope
These finite computations test the sign and normalization of the A-page relations. The rank-one sequence refutes semisimplicity at ; it makes no claim about other parameter values. Source locators and the inspected full-text evidence appear in the batch coverage record.
Definition, diagram, and repair contracts
Apply the definition and diagram contracts and prerequisite and repair holds before treating examples as suppliers. No diagram is needed for these finite algebra calculations; any later diagram must state its objects, maps, orientations and algebraic verification. The lane reference is 05-hecke and its source inventory. The full placement record is the placed-pages inventory, entry rational-cherednik-algebras-and-category-o-examples; the original audited research inventory is unchanged.
3 · Logical flowchart
4 · Definitions, theorems and proofs
The trivial reflection group gives the first Weyl algebra
Example
Take and . Then is the first Weyl algebra, with polynomial representation on which acts by multiplication and acts by .
Facts & Assumptions
Given: The one-dimensional reflection datum with trivial group.
The rational Cherednik algebra H_{t,c}(W,h): is generated by with .
The PBW theorem for rational Cherednik algebras: the ordered monomials form a basis of .
The polynomial representation of a rational Cherednik algebra: has underlying vector space .
Dunkl operators realize the polynomial standard module: on , acts by .
Proof
Given: [F1]–[F4] and a basis with dual .
Since for and , [F1] reduces to with no other generators. This is the defining presentation of the first Weyl algebra; [F2] also gives its basis .
In [F4] the reflection sum is empty, so and is multiplication by on [F3]. Directly, for every polynomial , verifying the Weyl relation in this representation.
Thus the trivial-group rational Cherednik algebra is the first Weyl algebra and its polynomial standard module is the usual polynomial representation.
Category O is not semisimple at the rank-one parameter c=1/2
Statement
Let act on by . At and , the polynomial standard module has a nonsplit exact sequence Thus category is not semisimple at this parameter.
Facts & Assumptions
Given: The rank-one reflection representation, parameter , and the polynomial representation.
Reflection data and parameters for a rational Cherednik algebra: choose and , so and .
The rational Cherednik algebra H_{t,c}(W,h): in this rank-one normalization.
The PBW theorem for rational Cherednik algebras and Standard modules for rational Cherednik category O: the polynomial standard module is as a vector space.
Category O for a rational Cherednik algebra and Standard modules lie in rational Cherednik category O: and its submodules and quotients are objects of .
Proof
Given: [F1]–[F5].
By [F2] and [F5], for every , while . At , this is for even and for odd . In particular, .
The subspace is nonzero and proper. Multiplication by preserves , preserves , and step 1.1 shows for every : for it is zero, while for its polynomial degree is . By [F3], this is the polynomial standard module; [F4] places it and its submodules in .
The quotient is one dimensional; and act by zero and acts trivially, so it is simple. If the displayed exact sequence split, its complement would be a one-dimensional submodule mapping isomorphically to the quotient. A generator would have nonzero constant term; rescale so . Since , there would be a scalar with , or . The polynomial ring is an integral domain and both factors are nonzero, a contradiction. The sequence is nonsplit, so is not semisimple.
5 · Examples, counterexamples and false statements
None yet.