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The PBW theorem for rational Cherednik algebras

Statement

Let (W,h) and c:S→C be as in Reflection data and parameters for a rational Cherednik algebra, and let t∈C. For Ht,c(W,h) of The rational Cherednik algebra H_{t,c}(W,h), choose any ordered basis x1,…,xn of h∗ and its dual basis y1,…,yn of h. Then the elements x1a1⋯xnan w y1b1⋯ynbn(ai,bi∈Z≥0, w∈W) form a complex-vector-space basis. Equivalently, multiplication induces an isomorphism of vector spaces C[h∗]⊗CCW⊗CC[h] ⟶ Ht,c(W,h).

Facts & Assumptions

Given: A finite complex reflection group W on a finite-dimensional complex vector space h, a conjugacy-invariant parameter c, the scalar t, and the quotient presentation of Ht,c(W,h).

[F1]

The rational Cherednik algebra H_{t,c}(W,h): Ht,c is generated by h∗, h and W, with xx′=x′x, yy′=y′y, [y,x]=κ(y,x), and wvw−1=w(v) for v∈h⊕h∗.

[F2]

The rational Cherednik commutator satisfies Jacobi compatibility: κ is W-equivariant and satisfies the cyclic Jacobi compatibility for every triple of vectors in h⊕h∗.

[F3]

Reflection data and parameters for a rational Cherednik algebra: h is finite dimensional, W is finite, and all group and parameter sums in the presentation are finite.

Proof

technique · direct

Given: [F1]–[F3], an ordered basis x1,…,xn of h∗, and its dual basis y1,…,yn of h.

1.1F1F3construct

Put all xi before every group symbol and all group symbols before all yj, and order the xi and yj within their respective blocks by index. Use the defining relations as reductions: sort inverted pairs of x's and of y's; replace wx by w(x)w; replace yw by w w−1(y); replace yx by xy+κ(y,x); and multiply adjacent group symbols. Each vector in w(x) or w−1(y) is expanded in the chosen finite bases. The irreducible words for these rules are precisely the displayed ordered monomials.

2.1F1step 1.1algebra

The reductions terminate. Use the lexicographic measure (i) number of vector letters, (ii) number of inversions of letter types for x<group<y, ignoring basis indices, (iii) number of group symbols, and (iv) sum of index inversions among the x letters and among the y letters. A correction term κ(y,x) strictly decreases (i). The main mixed swap and each group crossing strictly decrease (ii), although expanding the group action may change (iv). Multiplication of adjacent group symbols cannot increase (ii) and, when it preserves (ii), decreases (iii); delete an identity group symbol by the same measure. A same-side sorting rule preserves (i)–(iii) and strictly decreases (iv). Every reduction therefore decreases a well-founded measure on finite words, so no infinite reduction sequence exists.

2.2F1F2step 1.1algebra

All overlapping reductions have the following forms. Overlaps among two adjacent group multiplications or group-crossing rules agree because the action of W is an action and group multiplication is associative. Overlaps among same-side sorting rules agree because the x's commute with one another and the y's commute with one another. The forks wxjxi and yjyiw also join: a linear action preserves these commutativity relations, so applying the action before or after sorting gives the same symmetric product. A mixed group overlap ywx agrees along its two reductions exactly by W-equivariance of κ in [F2]. The only remaining overlaps are triples of vector letters, with two y's and one x, or one y and two x's; the difference between reducing the two adjacent mixed pairs is the cyclic Jacobi expression from [F2], hence is zero. Reductions at disjoint pairs commute by substitution. Thus every one-step fork joins.

3.1F1step 2.1step 2.2algebra

Termination from step 2.1 and the joining property from step 2.2 imply unique normal forms: by induction on the well-founded measure, if two first reductions differ, their join has smaller measure and therefore has the same normal form along both paths. Hence every word reduces uniquely to a linear combination of irreducible words. The reduction rules are consequences of [F1], so these words span the quotient. Conversely, the normal-form map annihilates each defining relation and all its left and right multiples; if a linear combination of irreducible words belonged to the defining ideal, its normal form would be both that combination and zero, so every coefficient would vanish. The irreducible words are therefore linearly independent in the quotient.

4.1F1F3step 3.1algebrastep 1.1∎

The irreducible words identified in step 1.1 are exactly x1a1⋯xnanwy1b1⋯ynbn. Step 3.1 proves they form a basis. The tensor-product map in the Statement sends the tensor-product monomial basis to this basis, so it is an isomorphism. No restriction on t or c was used beyond the data definitions.

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