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Tensor and Fusion Categories — Examples

1 · Prerequisites

2 · Summary

These examples use finite-dimensional vector spaces and do not reconstruct their tensor product.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: Literature-sourcedVerification: Literature-sourcedjudge pass (gpt-5.6-terra)audited 2026-09-06Open item page →

Finite-dimensional vector spaces form a fusion category

Example

For a field k, the category Vectkfd is a fusion category.

Facts & Assumptions

Given: A field k.

[F1]

k-modules are monoidal under ⊗k with unit k (Modules over a commutative ring form a monoidal category).

[F2]

Every finite-dimensional k-vector space is rigid (Finite-dimensional vector spaces are rigid).

[F3]

Fusion means finite semisimple tensor category (Fusion and multifusion categories).

Verification

technique · direct
1.1F1F2given

By [F1] and [F2], the finite-dimensional subcategory is a rigid k-linear monoidal category.

2.1step 1.1F3

Every finite-dimensional vector space is a finite direct sum of copies of k, so k is the only simple isomorphism class and the category is finite semisimple. Its unit has endomorphism algebra k.

3.1step 2.1F3∎

These clauses are exactly those of [F3], so Vectkfd is fusion.

ExampleConstruction: Literature-sourcedVerification: AI-adaptedaudited 2026-09-06Open item page →

The Grothendieck ring of finite-dimensional vector spaces

Example

The dimension map identifies K0(Vectkfd) with Z as a ring.

Facts & Assumptions

Given: A field k and Vectkfd.

[F1]

This category is fusion (Finite-dimensional vector spaces form a fusion category). Every finite-dimensional vector space is isomorphic to a finite direct sum of copies of k, and k is simple, so k is its only simple class.

[F2]

The Grothendieck group is generated by object classes modulo short-exact relations; its intended multiplication on generators is [V][W]=[V⊗kW] (The Grothendieck ring of a tensor category). We verify that this multiplication is well-defined in the present example.

Verification

technique · direct
1.1F1F2given

Dimension is additive on short exact sequences: a basis of a subspace, together with lifts of a basis of the quotient, is a basis of the middle space. Thus d([V])=dim⁡kV respects every relation in [F2] and induces a group homomorphism d:K0→Z. Split direct-sum sequences and [F1] give [V]=(dim⁡kV)[k], including [0]=0. Hence e:Z→K0, m↦m[k], satisfies de=id⁡ and ed=id⁡, proving the asserted additive bijection on all classes, including negative virtual classes.

2.1step 1.1F2algebra∎

Transport integer multiplication along this bijection: set a⋅b=e(d(a)d(b)). This is a well-defined unital ring structure, with unit e(1)=[k]. Tensor products of finite bases give dim⁡k(V⊗kW)=dim⁡kVdim⁡kW, so [V]⋅[W]=e(dim⁡k(V⊗kW))=[V⊗kW]. Thus the intended tensor multiplication in [F2] descends to the quotient; its bilinear extension is unique because object classes generate the group. The map d is therefore an isomorphism of rings, with zero and unit preserved.

ExampleConstruction: Literature-sourcedVerification: Literature-sourcedjudge pass (gpt-5.6-terra)audited 2026-09-06Open item page →

A matrix multifusion category with nonsimple unit

Example

For n>1, finite n×n matrices of finite-dimensional vector spaces, with matrix multiplication using ⊕ and ⊗k, form a multifusion category whose unit is not simple.

Facts & Assumptions

Given: A field k and an integer n>1.

[F2]

A multifusion category is finite semisimple multitensor category (Fusion and multifusion categories).

Verification

technique · direct
1.1F1givenconstruct

Let objects be n×n matrices (Vij) and set (V⊗W)ij=⨁rVir⊗kWrj. The matrix I with k on the diagonal and 0 off it is a unit.

2.1step 1.1F1F2

Entrywise semisimplicity and finite direct sums from [F1] give the finite semisimple rigid structure required in [F2].

3.1step 1.1F2∎

But I=E11⊕⋯⊕Enn is a nontrivial direct sum when n>1. Hence this is multifusion, not fusion.

ExampleConstruction: Literature-sourcedVerification: AI-adaptedaudited 2026-09-06Open item page →

Fusion rules for a supplied finite simple family

Example

For the supplied simple family (k) of Vectkfd, the only fusion coefficient is N111=1.

Facts & Assumptions

Given: The one-term family (k).

[F1]

Vectkfd is a fusion category (Finite-dimensional vector spaces form a fusion category). Every finite-dimensional vector space is a finite direct sum of copies of the simple object k, so k is its sole simple class.

[F2]

Fusion coefficients are defined by products of simple classes (Fusion rules).

Verification

technique · direct
1.1F1given

The unit isomorphism k⊗kk≅k gives [k][k]=[k].

2.1step 1.1F2∎

Comparing this with the defining expansion in [F2] for the supplied one-element family yields N111=1.

Sources