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A four-dimensional boundary case is outside the smooth h-cobordism theorem

Statement refuted

False claim: every compact smooth h-cobordism over a closed simply connected manifold of dimension four is diffeomorphic to the product. More precisely: the dimension hypothesis n≥5 of the smooth h-cobordism theorem (The smooth simply connected h-cobordism theorem) can be weakened to n=4, so that every h-cobordism of boundary dimension four over a closed simply connected 4-manifold is trivial.

Facts & Assumptions

Given: The dimension count for a clean embedded Whitney disk in a middle level of dimension m: the sheets must satisfy a,b≤m−3, or one of them has dimension at least 3 in the borderline version; and the literature record for boundary dimension four.

[F1]

In boundary dimension four the relevant middle level is four-dimensional and the general-position count fails: for complementary sheets with a=b=2 one has 2+a−m=0, and the smooth Whitney trick has no general embedded-disk replacement; the failure is the content of the dimension-four Whitney-trick remark together with its companion counterexample (The smooth Whitney trick fails in dimension four).

[F2]

The conclusion fails in the smooth category: there are smooth orientable simply connected 4-manifolds that are all smoothly s-cobordant and homeomorphic but pairwise not diffeomorphic (Kasprowski--Powell--Ray, EMS Surv. Math. Sci. 9 (2022), Example 1.13, first pair due to Donaldson), so no h-cobordism between two of them is a product; equivalently the smooth h-cobordism theorem is false for boundary dimension four in general, while the topological statement holds for good fundamental groups, in particular for the trivial group, by Freedman (The h-cobordism theorem does not cover boundary dimension four).

[F3]

An h-cobordism is a compact smooth cobordism whose two face inclusions are homotopy equivalences, and its triviality is the existence of a diffeomorphism to the product relative to the incoming boundary (h-Cobordism, Simply connected topological spaces).

[F4]

The smooth simply connected h-cobordism theorem assumes boundary dimension n≥5, equivalently total dimension n+1≥6 (The smooth simply connected h-cobordism theorem).

Counterexample

1.1F1given

The proof route fails in boundary dimension four: by [F1], a clean embedded Whitney disk in a four-dimensional middle level cannot generally be produced, since the general-position dimension count for complementary sheets of dimensions 2 and 2 gives no room for an embedded disk; the Whitney-trick step of the theorem is therefore unavailable exactly when n=4.

2.1F2F3givenstep 1.1

The conclusion also fails, so the failure is not merely a gap in the proof: by [F2] there are smooth orientable simply connected 4-manifolds that are smoothly s-cobordant and homeomorphic but not diffeomorphic, and an s-cobordism is in particular an h-cobordism between them; were such an h-cobordism diffeomorphic to the product relative to its incoming boundary, [F3] would make its two faces diffeomorphic, contradicting the choice of the pair.

3.1F2F4step 2.1∎

Therefore the hypothesis n≥5 of the smooth h-cobordism theorem cannot be weakened to n=4: the dimension count at the Whitney step stops working and the conclusion itself is false in general for simply connected closed 4-manifolds, while the parallel topological statement for good fundamental groups is a genuinely different theorem. No smooth four-dimensional Poincaré or disk conclusion follows from the theorem of this page, whose statement is restricted to boundary dimension at least five by [F4].

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