Alphabeta Math
CounterexampleConstruction: AI-generatedVerification: AI-generatedprecheck passverified 2026-08-09 (gpt-5.6-terra-codex-subscription)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

On the domain {0}∪[1,2] every real is vacuously a limit at 0

Statement refuted

Refuted claim: for every A⊆R, every f:A→R and every c∈A, at most one real L satisfies

(∀ε>0) (∃δ>0) (∀x∈A) [ 0<∣x−c∣<δ ⟹ ∣f(x)−L∣<ε ]

— the false statement FALSE: a function has at most one limit at every point of its domain, isolated points included.

The witness is A:={0}∪[1,2] (Intervals of R: the nine order-convex forms, nondegeneracy, and length), f:A→R the constant 0, and c:=0. At c the displayed formula holds for every real L at once, so it determines nothing.

What this item adds. It exhibits the dichotomy inside one example: at the isolated point 0 the formula is vacuous, while at the point 1 of the same domain — which is a limit point of A — the formula is not vacuous and At a limit point of the domain a function has at most one limit applies, so the limit there exists and is unique. The same A, the same f, and opposite behaviour at two of its points.

Facts & Assumptions

Given: The set A:={0}∪[1,2], the constant function f:A→R with f(x):=0 for every x∈A, and the points 0 and 1 of A.

[L1]

The ε-δ formula displayed above, and the fact that The ε-δ limit lim⁡x→cf(x)=L of f:A→R at a limit point c of A imposes it only at a limit point of the domain, where At a limit point of the domain a function has at most one limit then makes L unique.

[L2]

Limit point and isolated point: c is a limit point of S when Nρ∗(c)∩S≠∅ for every real ρ>0; c∈S is isolated in S when Nρ(c)∩S={c} for some real ρ>0; and for c∈S the two are exact opposites (Limit point, isolated point, adherent point, derived set, and dense subset of R, The ε-neighbourhood and the punctured ε-neighbourhood of a point of R).

[L3]

Neighbourhoods: Nρ(u)={ y:∣y−u∣<ρ } and Nρ∗(u)=Nρ(u)∖{u} (The ε-neighbourhood and the punctured ε-neighbourhood of a point of R).

[L4]

Intervals: [1,2]={ y:1≤y≤2 } (Intervals of R: the nine order-convex forms, nondegeneracy, and length).

[L5]

Absolute value: ∣u∣≥0; ∣u∣=0 exactly when u=0; ∣u∣=u for u≥0; ∣0∣=0 (Basic properties of the absolute value).

[L6]

Order in R: trichotomy and totality; 0<1, so 2>0 and ρ/2>0 with ρ/2<ρ for ρ>0; and of two positive reals the smaller is positive (The multiplicative identity is positive, Order is preserved by adding a constant and by adding inequalities, Sign rules for products and monotonicity of multiplication, Ordered field).

Counterexample

technique · direct
1.1

A={0}∪[1,2] is a subset of R, and f is the constant 0 on A; both 0 and 1 belong to A.

L4
1.2

0 is an isolated point of A and not a limit point of A: N1(0)∩A={0}, since an element of A is either 0, with ∣0−0∣=0<1, or an element of [1,2], with ∣y−0∣=y≥1 and hence outside N1(0).

L2L3L4L5
1.3

The reals 0 and 1 are distinct.

L6
2.1

Take δ:=1. No x∈A satisfies 0<∣x−0∣<1: such an x would lie in N1∗(0)∩A, which is contained in N1(0)∩A={0} and excludes 0, hence is empty. So for every real L and every real ε>0 the choice δ=1 makes the implication vacuously true, and every real L satisfies the displayed formula at c=0.

step 1.2L1L3L5
2.2

By contrast 1∈A is a limit point of A: given a real ρ>0, let σ be the smaller of ρ and 1, so σ>0; then 1+σ/2 satisfies 1≤1+σ/2≤1+1/2≤2, so it lies in [1,2]⊆A, and 0<∣(1+σ/2)−1∣=σ/2<ρ. There The ε-δ limit lim⁡x→cf(x)=L of f:A→R at a limit point c of A applies, At a limit point of the domain a function has at most one limit gives at most one L, and in fact lim⁡x→1f(x)=0, since ∣f(x)−0∣=∣0∣=0<ε for every x∈A and every real ε>0.

step 1.1L1L2L4L5L6
3.1

In particular L=0 and L=1 both satisfy the formula at c=0, and they are distinct: more than one real satisfies it, so the claim is refuted. This is why The ε-δ limit lim⁡x→cf(x)=L of f:A→R at a limit point c of A is stated only at a limit point, and why lim⁡x→0f(x) is left undefined on this domain.

step 1.3step 2.1L1L6
4.1

So on one and the same domain the formula pins down a unique value at the limit point 1 and no value at all at the isolated point 0: uniqueness of the limit is a property of limit points, not of arbitrary points of the domain.

step 2.2step 3.1∎

Remarks

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

24 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources