Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-08-30
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Gamma has no zeros

Statement

Gamma has no zeros on C, and 1/Γ has simple zeros exactly at 0,−1,−2,….

Facts & Assumptions

Given: The reciprocal-Gamma product.

[L1]

One has 1/Γ(z)=zeγz∏n≥1(1+z/n)e−z/n (The Weierstrass product for reciprocal Gamma).

Proof

technique · direct
1.1L1given

In [L1], the exponential factors never vanish, while the factor z gives a simple zero at 0 and the factor 1+z/n gives a simple zero at z=−n for each n≥1. There are no other zeros.

2.1step 1.1algebra∎

Therefore 1/Γ vanishes exactly at the nonpositive integers, and Gamma has poles there and no zeros anywhere.

Depends on

Used by

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources