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Harmonic Cauchy estimates in supremum norm

Statement

Assume Countable Choice and n≥2. Let u be real or complex harmonic on an open Ω⊆Rn with Br(x)⋐Ω, r>0, and let α be a multi-index. Then ∣Dαu(x)∣≤Cn,α′ r−∣α∣sup⁡Br(x)∣u∣, with Cn,α′ depending only on n and α.

Facts & Assumptions

Given: Countable Choice, an integer n≥2, an open set Ω, a harmonic u on Ω, x∈Ω, r>0 with Br(x)‾⊂Ω, and a multi-index α.

[F1]

Under these hypotheses, ∣Dαu(x)∣≤Cn,αr−n−∣α∣∫Br(x)∣u(y)∣ dy with Cn,α independent of u,x,r,Ω (Interior derivative estimates for harmonic functions).

[F2]

For n≥1 and r>0, ∣Br∣=ωn−1rn/n, finite and positive (Sphere and ball measures scale in Rn).

[F3]

Countable Choice ACω is the standing hypothesis (The Axiom of Countable Choice (ACω)).

Proof

technique · direct
1.1givenF3

Work under [F3] and set M:=sup⁡Br(x)∣u∣∈[0,+∞]. Since ∣u∣ is continuous and Br(x) is bounded, the integral ∫Br(x)∣u∣ is defined in [0,+∞].

2.1step 1.1F2algebra

If M<+∞, then ∣u(y)∣≤M for every y∈Br(x), so by monotonicity of the integral ∫Br(x)∣u∣≤M ∣Br(x)∣=M ωn−1rn/n by [F2].

3.1step 2.1F1F2algebra

Substituting step 2.1 into [F1] gives ∣Dαu(x)∣≤Cn,αr−n−∣α∣⋅Mωn−1rn/n=(Cn,αωn−1/n) r−∣α∣M, so the stated estimate holds with Cn,α′:=Cn,αωn−1/n, a constant depending only on n and α.

4.1step 1.1step 3.1cases∎

If M=+∞ the right-hand side of the stated inequality is +∞ while ∣Dαu(x)∣ is a finite real number, so the inequality holds trivially; for the local applications of this estimate one always takes a compactly contained ball on which ∣u∣, being continuous, is bounded, so the case M=+∞ never carries mathematical content.

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Sources