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CorollaryStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-30
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A nonconstant meromorphic function on the plane omits at most two sphere values

Statement

A nonconstant meromorphic function on C omits at most two values of C^.

Facts & Assumptions

Given: A nonconstant meromorphic function f:CC^.

[L1]

A unique Möbius transformation carries any ordered triple of distinct sphere points to any other (A unique Möbius transformation carries any ordered triple of distinct sphere points to any other).

[L2]

Möbius transformations are biholomorphic sphere self-maps (Every Möbius transformation is a biholomorphism of the Riemann sphere).

[L3]

A nonconstant entire function omits at most one finite value (Little Picard theorem).

Proof

technique · direct
1.1

Assume toward a contradiction that f omits three distinct sphere values. By [L1], choose a Möbius transformation M sending them to 0, 1, and . Then g:=Mf is meromorphic by [L2], omits 0, 1, and , and therefore is actually entire.

L1L2givenassume-contrachoose
2.1

Fact [L3] makes an entire function omitting 0 and 1 constant, so g is constant. Since M is biholomorphic by [L2], f=M1g is constant as well, contradicting the hypothesis.

L2L3step 1.1discharge-contradiction
3.1

Therefore a nonconstant meromorphic function on the plane omits at most two sphere values.

step 2.1

Depends on

Used by

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources