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TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
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Every Möbius transformation is a biholomorphism of the Riemann sphere

Statement

Every Möbius transformation is a biholomorphism of the Riemann sphere. Explicitly, if M(z)=az+bcz+d(adbc0), then M:C^C^ is holomorphic in the sphere charts and its inverse is again a Möbius transformation.

Facts & Assumptions

Given: A Möbius transformation M(z)=(az+b)/(cz+d) with adbc0.

[L1]

The Riemann sphere charts are the finite z-chart and the 1/z-chart at (The standard holomorphic charts on the Riemann sphere, with holomorphy and poles at infinity).

[L2]

Möbius transformations form a group and inverses are again Möbius (Möbius transformations form a group and identify with the projective linear quotient of GL_2(C)).

Proof

technique · direct
1.1

On every open set where cz+d0, the finite-chart expression z(az+b)/(cz+d) is a rational function with nonvanishing denominator, hence holomorphic; and if c0, then near the finite pole p=d/c the target infinity-chart expression is (cz+d)/(az+b), which is holomorphic because az+b does not vanish at p.

L1givenalgebra
1.2

At , if c0 then the source infinity-chart expression is (a+bw)/(c+dw), which is holomorphic at 0; if c=0, then M()= and the target infinity-chart expression is dw/(a+bw), again holomorphic at 0. Thus M is holomorphic at every sphere point.

L1givenalgebra
2.1

By [L2], the inverse map is again Möbius, so the same two chart computations apply to M1 as well. Therefore M is a biholomorphism of the sphere.

L2given

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