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Compact sets of positive area are not conformally removable
Statement
Assume the Axiom of Choice. Let be compact and suppose its finite-chart part has positive planar Lebesgue area, , using (Lebesgue measurable sets, the family , and the restricted set function , as the Euclidean plane and as a normed real algebra: what the identification preserves). Then there is a homeomorphism conformal on that is not a Möbius transformation. Thus is not globally conformally removable (Conformal removability of compact sets), and every globally conformally removable compact set has zero area in the finite chart.
Facts & Assumptions
Given: AC, a compact set , and with .
The Riemann sphere is compact Hausdorff and has its finite and infinity holomorphic charts (The Riemann sphere is the published one-point compactification of the complex plane, The standard holomorphic charts on the Riemann sphere, with holomorphy and poles at infinity). Hence compact is closed, so is Borel in the finite chart (In a Hausdorff space a point and a disjoint compact set, and two disjoint compact sets, have disjoint open neighbourhoods; hence every compact subset is closed, and in a compact Hausdorff space the compact subsets are exactly the closed ones, The Borel sigma-algebra of a topological space).
Under Countable Choice, Borel subsets of are Lebesgue measurable (Assuming countable choice, every Borel subset of is Lebesgue measurable, Lebesgue measurable sets, the family , and the restricted set function ). Thus the indicator of is a measurable function in the finite chart.
A Beltrami coefficient on the sphere is an almost-everywhere class determined by its finite-chart representative, with its infinity-chart expression fixed by the holomorphic transition rule; its norm is the essential supremum of the modulus (Measurable Beltrami coefficients and measurable conformal structures).
A weak solution on the sphere is locally in holomorphic charts and satisfies almost everywhere; a sphere Beltrami coefficient of norm below has a quasiconformal homeomorphic solution with that coefficient (Weak solutions of the Beltrami equation, The measurable Riemann mapping theorem on the sphere).
If a homeomorphism of complex domains lies in and has weak Wirtinger derivative almost everywhere, then it is conformal (Every 1-quasiconformal homeomorphism is conformal).
Möbius transformations are biholomorphic in the sphere charts, so their Beltrami coefficient is zero almost everywhere (Every Möbius transformation is a biholomorphism of the Riemann sphere, The Beltrami coefficient and the maximal dilatation).
A compact sphere set is globally conformally removable exactly when every sphere homeomorphism conformal off it is Möbius (Conformal removability of compact sets).
AC implies Countable Choice (AC implies DC implies countable choice); the Borel/Lebesgue, coefficient, weak-solution and normalized measurable-Riemann-mapping interfaces use the stated choice assumptions (The Axiom of Choice, The Axiom of Countable Choice ()).
Proof
Let . By [F1], is Borel in the finite chart, and [F2] makes it Lebesgue measurable. The Countable Choice assumption of the Borel/Lebesgue interface follows from AC by [F8].
Define the finite-chart function for and for . By [F2] it is measurable. Since , its essential supremum is exactly : the pointwise bound gives at most , while for every the set contains and has positive measure. The sphere-chart rule [F3] therefore defines a Beltrami coefficient with .
Apply the existence clause of [F4] with . It gives an orientation-preserving sphere homeomorphism that is a weak solution for and has Beltrami coefficient almost everywhere.
On every local chart in , the coefficient is zero almost everywhere because its finite-chart support is and the transition rule preserves zero. Hence the weak Beltrami equation from [F4] gives almost everywhere there. The local coordinate maps belong to by [F4], so [F5] makes them conformal. The Countable Choice assumptions of these measurable and weak-solution interfaces follow from AC by [F8]. Thus is conformal on .
If were Möbius, [F6] would give almost everywhere. This contradicts on the positive-area set by step 2.1. Therefore is not Möbius, and [F7] says is not globally conformally removable. The same argument for any compact of positive area proves that every globally conformally removable compact set has zero area. The normalized measurable-Riemann-mapping and measure interfaces use the choice assumptions recorded in [F8].
Depends on
- The Axiom of Choice
- The Borel sigma-algebra of a topological space
- The Beltrami coefficient and the maximal dilatation
- A complex domain is a nonempty connected open subset of $\mathbb C$
- Conformal removability of compact sets
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Lebesgue measurable sets, the family $\mathcal{L}(\mathbb{R}^n)$, and the restricted set function $\lambda_n$
- Measurable Beltrami coefficients and measurable conformal structures
- The standard holomorphic charts on the Riemann sphere, with holomorphy and poles at infinity
- Weak solutions of the Beltrami equation
- $\mathbb C=\mathbb R[x]/(x^2+1)$ as the Euclidean plane and as a normed real algebra: what the identification preserves
- The Riemann sphere is the published one-point compactification of the complex plane
- Assuming countable choice, every Borel subset of $\mathbb{R}^n$ is Lebesgue measurable
- AC implies DC implies countable choice
- In a Hausdorff space a point and a disjoint compact set, and two disjoint compact sets, have disjoint open neighbourhoods; hence every compact subset is closed, and in a compact Hausdorff space the compact subsets are exactly the closed ones
- The measurable Riemann mapping theorem on the sphere
- Every Möbius transformation is a biholomorphism of the Riemann sphere
- Every 1-quasiconformal homeomorphism is conformal
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Sources
- Malik Younsi, On removable sets for holomorphic functions, EMS Surv. Math. Sci. 2 (2015) 219-254 (standard reference, not scraped)
- Mikhail Lyubich, Conformal Geometry and Dynamics of Quadratic Polynomials, vol. I (book draft, Stony Brook) (standard reference, not scraped)